Download Practice Genetics Problems Bio 120

These problems are from a biology textbook for biology majors by Campbell. You can
find these online as well and I will try and give more problems later. The answers are at
the end of the document. Try and do the problems without looking at the answers to see if
you really understand the concepts and how to use them. Some of these problems are
harder than what will be on the exam, but if you can do them then you know that you
have a firm grasp of the concepts.
Practice Genetics Problems Bio 120
1. A rooster with gray feathers is mated with a hen of the same phenotype. Among
their offspring, 15 chicks are gray, 6 are black, and 8 are white. What is the
simplest explanation for the inheritance of these colors in chickens? What
offspring would you predict from the mating of a gray rooster and a black hen?
2. In some plants, a true-breeding, red-flowered strain gives all pink flowers when
crossed with a white-flowered strain: RR (red) x rr (white) --- Rr (pink). If flower
position (axial or terminal) is inherited as it is in peas (i.e., axial is dominant to
terminal), what will be the ratios of genotypes and phenotypes of the generation
resulting from the following cross: axial-red (true-breeding) x terminal-white?
What will be the ratios in the F2 generation?
3. A black guinea pig crossed with an albino guinea pig produced 12 black
offspring. When the albino was crossed with a second black one, 7 blacks and 5
albinos were obtained. What is the best explanation for this genetic situation?
Write genotypes for the parents, gametes, and offspring.
4. Color patterns in a species of duck is determined by one gene with three alleles.
Alleles H and I are semidominant (i.e., incomplete dominance), and allele i is
recessive to both. How many phenotypes are possible in a flock of ducks that
contains all the possible combinations of these three alleles.
5. In 1981, a stray black cat with unusual rounded, curled black ears was adopted by
a family in California. Hundreds of descendants of the cate have since been born,
and cat fanciers hope to develop the "curl" cat into a show breed. Suppose you
owned the first culr cat and wanted to develop a true-breeding variety. How
would you determine whether the curl allele is dominant or recessive? How would
you select for true-breeding cats? How would you know they are true breeding?
6. In tigers, a recessive allele causes an absence of fur pigmentation (a "white tiger")
and a cross-eyed condition. If two phenotypically normal tigers that are
heterozygous at this locus were mated, what percentatge of their offspring will be
cross-eyed? What percentage will be white?
7. A man has six fingers on each hand and six toes on each foot. His wife and their
daughter have the normal number of digits. Extra digits is a dominant trait. What
fraction of this couple's children would be expected to have extra digits?
8. The pedigree below traces the inheritance of a very rare biochemical disorder in
humans. Affected individuals are indicated by filled-in circles and squares. Is the
allele for this disorder dominant or recessive? What genotypes are possible for the
individuals marked 1, 2, and 3.
9. The pedigree below traces the inheritance of alkaptonuria, a biochemical disorder.
Affected individuals, indicated here by the filled-in circles and squares, are unable
to break down a substance called alkapton, which colors the urine and stains body
tissues. Does alkaptonuria appear to be caused by a dominant or recessive allele?
Fill in the genotypes of the individuals whose genotypes you know. What
genotypes are possible for each of the other individuals? (from class)
10. A man with group A blood marries a woman with group B blood. Their child has
group O blood.


What are the genotypes of these individuals?
What other genotypes and in what frequencies, would you expect in offspring
from this marriage?
Answers:
1. Incomplete or codominance. Feather color is controlled by 2 genes B = black
and b = white. The third phenotype is the result of a 50-50 mix of black and
white to produce gray.
The 15 gray, 6 black, and 8 white birds represent a 2:1:1 ratio&emdash;the
result of mating two heterozygous individuals: (Bb x Bb)
1 BB : 2 Bb : 1 bb
What offspring would you predict from the mating of a gray rooster and a black
hen?
A gray rooster (Bb ) mated to a black hen (BB ) can be represented by the
following Punnett square:
50% of the offspring should be gray (Bb ) and 50% black (BB )
2. Note: Axial (A ) is dominant over terminal (a ).
The genotypes of the parents are AARR and aarr. Therefore the gametes of the
parents must be AR and ar so the genotype for all the offspring in the F1
generation will be AaRr, and their phenotype will be axial-pink.
What will be the ratios in the F2 generation?
The ratio of genotypes can be determined by examining the Punnett square
below:
The ratio of phenotypes will be:
6 axial-pink
3 axial-red
3 axial-white
8 pink
4 red
4 white
2 terminal-pink
1 terminal-white
1 terminal-red
12 axial
4 terminal
3. Black is dominant over white
Write genotypes for the parents, gametes, and offspring.
First cross:
Parent's genotypes
gametes
F1 offspring
Second cross:
Parent's genotypes
gametes
=
=
BB (black)
B
=
all Bb
=
=
Bb (black)
B or b
x
bb (white)
b
x
bb (white)
b
F1 offspring
=
Bb or bb
There should be 50% black to 50% white offspring in this cross.
4. As in the ABO blood system 4 phenotypes are possible in this case:
Genotype
Phenotype
HH, Hi
II, Ii
HI
ii
(H)
(I)
(HI)
(i)
5. How would you determine whether the curl allele is dominant or recessive?
Mate the stray to a non-curl cat. If any offspring have the "curl" trait it is likely
to be dominant. If the mutation is recessive, then on ly non-curl offspring will
result.
How would you select for true-breeding cats?
You know that cats are true-breeding when curl crossed with curl matings
produce only curl offspring.
How would you know they are true-breeding?
A pure-bred "curl cat" is homozygous.
1. If the trait is recessive any inividual with the "curl" condition is
homozygous recessive.
2. If the trait is dominant you can determine if the individual in question is
true breeding (CC) or heterozygous (Cc) with a test cross (to a
homozygous recessive individual).
6. Using the Punnett square below where P = normal pigmenation and p =
white
then 25% will be white (pp) and all of the white offspring will also be crosseyed
7. Because the daughter is normal the man's genotype must be heterozygous for
the trait so:
if X = extra digits and x = normal (5) digits then:
50% of the offspring will be polydactylic
8. The allele is most likely dominant because the #2 individual (see below) with
the trait marries a woman with the trait and 50% of their offspring are normal.
If the trait were recessive one would expect the following:
100% of offspring would have the disease, which
is not the case.
What genotypes are possible for the individuals marked 1, 2, and 3?
1. Bb (heterozygous)
2. Bb ( if 2's genotype were bb he would not have the disease and if BB all
his children would have the condition.)
3. bb (all normal individuals are homozygous recessive)
9. Recessive
Fill in the genotypes of the individuals whose genotypes you know. What
genotypes are possible for each of the other individuals?
If alkaptonuria is recessive George must be a carrier. See below.
If alkaptonuria is dominant Carla could not have the disease, as indicated in the
pedigree chart, since the parents do not express the trait. See Below.
10. Father = AO (or IAi)
Mother = BO (or IBi)
First Child = OO (or ii)
What other genotypes and in what frequencies, would you expect in offspring
from this marriage?
Examine the Punnett square to determine the other genotypes possible.
The other genotypes for children are (according to Campbell's system): 1/4
IAIB, 1/4 IAi, 1/4 IBi