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Large-Sample C.I.s for a Population Mean; Large-Sample C.I. for a Population Proportion Chapter 7: Estimation and Statistical Intervals 2/17/12 Lecture 13 1 2/17/12 Lecture 13 2 Confidence Intervals (CIs): • Typically: estimate ± margin of error • Always use an interval of the form (a, b) • Confidence level (C) gives the probability that such interval(s) will cover the true value of the parameter. – It does not give us the probability that our parameter is inside the interval. – In Example 1: C = 0.95, what Z gives us the middle 95%? (Look up on table) Z-Critical for middle 95% = 1.96 – What about for other confidence levels? • 90%? 99%? • 1.645 and 2.575, respectively. Lecture 11 A large-sample Confidence Interval: • Data: SRS of n observations (large sample) • Assumption: population distribution is N (µ,σ) with unknown µ and σ • General formula: s X ± (z critical value) n 2/17/12 Lecture 13 4 Interpreting CI • Given a 95% Confidence Level, the Confidence Interval of a population mean should be interpreted as: – We are 95% confident that the population mean falls in the interval (lower limit, upper limit) • For the example we just saw, we say – We are 95% confident that the mean corn yield is between X − 1.96 s , X + 1.96 s 2/17/12 Lecture 13 n n 5 Choosing a sample size: • The margin of error or half-width of the interval is sometimes called the bound on the error of estimation • Before collecting data, we can determine the sample size for a specific bound, B. • We just rearrange the margin of error 2 formula by solving for n ⎛ 1.96 s ⎞ • For 95% confidence, we have: n = ⎜ B ⎟ ⎝ ⎠ • For any confidence level, we have 2 ⎛ Z Crit s ⎞ n = ⎜ ⎟ ⎝ B ⎠ 2/17/12 Lecture 13 6 Example 2 (cont.) • Suppose we wanted to estimate the mean breakdown voltage in our previous example but we wanted a bound, B, of no more than 0.5kV with 95% confidence. • What is the required sample size to achieve this bound? 2 2 ⎛ 1.96 s ⎞ ⎛ 1.96 × 5.23 ⎞ n = ⎜ , ⎟ = 420.3 ⎟ = ⎜ 0.5 ⎝ B ⎠ ⎝ ⎠ rounded up to 421. 2/17/12 Lecture 13 7 If s is unknown? • If you don’t have a sample standard deviation, you may use a “best guess” from a previous study of what it might be. • OR, as long as the population is not too skewed, dividing the range by 4 often gives a rough idea of what s might be. • For 95% confidence: 2/17/12 ⎛ 1.96(range / 4) ⎞ n = ⎜ ⎟ B ⎝ ⎠ Lecture 13 2 8 One-sided Confidence Intervals (Confidence Bounds) • There are circumstances where we are only interested in a bound or limit on some measurement – Examples? Cutoff score for the top 10% students in a Science Competition. • To do this we simply put all the area on one side, maintaining the confidence and Zcritical value we desire. 2/17/12 Lecture 13 9 One-sided Confidence Intervals (Confidence Bounds) • Large-sample confidence bounds • Upper: s µ < X + (z critical value) n • Lower: s µ > X − (z critical value) n 2/17/12 Lecture 13 10 7.3 More Large Sample Confidence Intervals • Be aware that most confidence intervals take a similar format estimate ± critical value ⋅ SEestimate • Understanding the sampling distribution of the estimate is the critical part that gives us the pieces above • We’ll come back to this in a few minutes! 2/17/12 Lecture 13 11 Confidence interval for p • To estimate the pop proportion p (or called π), we can use the sample proportion p̂ – Recall p is a number between 0 and 1 • How to find a confidence interval for p? – Need to know the mean, standard deviation and sampling distribution of p̂ – When the sampling distribution is known, we can use it to calculate the CI under certain confidence level 2/17/12 Lecture 13 12 Sampling Distribution of p • As we’ve seen in chapter 5, from the CLT we have (when n is sufficiently large): ⎛ p(1 − p) ⎞ pˆ ~ N ⎜⎜ p, ⎟⎟ n ⎝ ⎠ • We can then standardize p̂, and get a standard normal distribution z= 2/17/12 pˆ − p ~ N ( 0,1) p(1 − p) n Lecture 13 13 Confidence interval for π • So, based on the previous formula, we can construct a confidence interval as such: P(| pˆ − p |< Zcrit ) = confidence level p(1 − p) n • So thankfully, when n is large (≥25), we have: pˆ (1 − pˆ ) pˆ ± Zcrit n 2/17/12 Lecture 13 14 Example 3: Parking problem?! • To estimate the proportion of Purdue Students who think parking is a problem, we sample 100 students and find that 67 of them agree that parking is indeed a problem. • Give a 95% confidence interval for the true proportion of students that think parking is a problem. – Make sure you can interpret the interval. Answer: (58%,76%). 2/17/12 Lecture 13 15 After Class… • Review Sections 7.1 through 7.3 • Read sections 7.4 (till Pg 316) and 7.5 • Exam#1, next Tuesday evening. • Lab#3, next Wed. 2/17/12 Lecture 13 16