* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Abstract
Mathematical proof wikipedia , lookup
Line (geometry) wikipedia , lookup
Georg Cantor's first set theory article wikipedia , lookup
Vincent's theorem wikipedia , lookup
List of important publications in mathematics wikipedia , lookup
Central limit theorem wikipedia , lookup
Pythagorean theorem wikipedia , lookup
Recurrence relation wikipedia , lookup
Brouwer fixed-point theorem wikipedia , lookup
Fundamental theorem of calculus wikipedia , lookup
Four color theorem wikipedia , lookup
Wiles's proof of Fermat's Last Theorem wikipedia , lookup
System of polynomial equations wikipedia , lookup
Partial differential equation wikipedia , lookup
Russell Jay Hendel Linear equalities in Fibonacci numbers, Fibonacci Quart. 44 (2006), no. 3, 235–248. Abstract We study the equation Fb = Fx(1) + F−x(3) + F−x(4) + · · · + F−x(m) with m ≥ 3, 0 < x(1) < b, and 0 < x(3) < x(4) < · · · < x(m). This equation naturally arises in the generalization of several problems that have appeared in The Fibonacci Quarterly in the problem sections. This equation also has intrinsic interest in its own right. The main theorem - the Accident theorem–states, that under very mild conditions, solutions to this equation cannot happen by accident; that is, there are no singular solutions, but rather every solution belongs to a parametrizable class of solutions. Furthermore if m ≥ 4, then b must be even and there are exactly 9 parametrizable solutions. This is the first major theorem in the literature on identities in Fibonacci numbers with an arbitrary number of summands whose subscripts have mixed signs. There are only 2 hypothesii of the accident theorem: We require that for all i, x(i) > 2 and that no proper subset of summands on the right hand side of the equation has a sum of zero. While the proof of the accident theorem requires many sub-theorems and lemmas, the basic proof method is to exploit Fibonacci Telescoping lemmas. An example of Fibonacci Telescoping is illustrated by the following identity which leads to one of the 9 parametrizable solutions for m ≥ 4 : Fb = Fb−o−3 + F−(b−o−2) + F−(b−o) + · · · + F−(b−1) with b even and o an arbitrary positive odd integer. 1