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Resistors in Series 1) There must be the same current in both resistors I1 = I 2 = I What is the Current? 2) V1 ≠ V2 so V1 = IR1 V2 = IR2 But we know the total potential ε = V1 + V2 ε = IR1 + IR2 ε = I ( R1 + R2 ) 3) The current is the same as if the circuit had one resistor with R = R1 + R2 We say R is the electrically “equivalent resistor. For Req = R1 + R2 + R3 + R4 + R5 + ... Resistors in Parallel 1) The ends of the two resistors are connected by conductors so they must be at the same potential V1 = I1R1 = V V2 = I 2 R2 = V What is the Current? V I1 = R1 V I2 = R2 2) Since all of the current must flow through the resisitors ⎛1 V V 1 ⎞ I1 = + = V ⎜⎜ + ⎟⎟ R1 R2 ⎝ R1 R2 ⎠ 3) The two resistors act like one resistor with 1 1 1 = + R eq R1 R2 = 1 1 1 1 = + + R eq R1 R2 R3 Reminder: Series/parallel rules for resistors are just the “opposite” of that for capacitors Analysis of a More Complex Circuit Question: What are the Currents example 26.1 Resistors in Series and Parallel R = R1 + R2 + R3 1 1 1 1 = + + R R1 R2 R3 Sample Exercises: 26.4, 26.8, 26.12, 26.13, 26.18 Many complex circuits can be resolved using repeated application of the series and parallel rules…BUT NOT ALL! Examples of circuits that CANNOT be solved that way: Kirchoff’s Rules ∑I =0 ∑V = 0 Junction Rule – Valid at any Junction Loop Rule – Valid for any closed loop example Many complex circuits can be resolved using repeated application of the series and parallel rules…BUT NOT ALL! Examples of circuits that CANNOT be solved that way: Kirchhoff’s Rules ∑I =0 ∑V = 0 Junction Rule – Valid at any Junction Loop Rule – Valid for any closed loop example Sampe Problem: What is the current in each resistor? What is the equivalent resistance of the 5 resistors? [See Problem Solving Strategy using Kirchhoff’s Rules (Y&F p987)] Step 1- Lay out a clear diagram of circuit. Step 2- Label ALL Currents – Use Kirchhoff’s Junction Rule to simplify The directions of currents you chose is NOT IMPORTANT If you guess wrong – Mr. Kirchhoff will give you a minus sign for the current. Step 3- Identify Positive and Negative sense for each component + - + + + + The sense of + and – depends on your choice of current Step 4- Draw Loops around circuit – every resistor must lie on at least one loop + + + + + The directions of the loops is NOT IMPORTANT It does NOT have to be in the direction of the currents! Step 5 – Go around the loops to get the equationsNOTE – If we go from + to – potential change is NEGATIVE If we go from - to + potential change is POSITIVE + + + + 13V − 13V − I 1 (1Ω ) − (I 1 − I 3 )(1Ω ) = 0 − I 2 (1Ω ) − (I 2 + I 3 )(2Ω ) + 13V = 0 − I 1 (1Ω ) − I 3 (1Ω ) + I 2 (1Ω ) = 0 + Loop 1 Loop 2 Loop 3 Step 3- Solve the Simultaneous Equations 13V − I 1 (1Ω ) − (I 1 − I 3 )(1Ω ) = 0 Loop 1 − I 2 (1Ω ) − (I 2 + I 3 )(2Ω ) + 13V = 0 Loop 2 − I 1 (1Ω ) − I 3 (1Ω ) + I 2 (1Ω ) = 0 Loop 3 Solve Equation 3 for I2: I 2 = I1 + I 3 Plug into Equations 1 and 2 (this gives 2 equations and 2 unknowns): 13V = I 1 (2Ω ) − I 3 (1Ω ) 13V = I 1 (3Ω ) + I 3 (5Ω ) Multiply top equation by 5 and add two equations: 65V = I 1 (10Ω ) − I 3 (5Ω ) 13V = I 1 (3Ω ) + I 3 (5Ω ) 78V = I 1 (13Ω ) I1 = 6 A I 3 = −1 A Negative sign here means we guessed wrong about direction of I3 I2 = 5 A Time Dependent Circuits – The RC Circuit Example 1 – Charging a Capacitor- Capacitor has no net charge at t=0 Voltage and Current are functions of Time – However – Kirchhoff’s Rules are still valid at instant in Time vab = iR q vbc = C Ohms Law Definition of Capacitance q ε − iR − = 0 C + ε q i= − R RC Close Switch at t=0 Kirchhoff;s Loop Rule At t=0, there is no charge on the capacitor so at the “instant” the switch is closed, we expect a current of I0=ε/R. As the capacitor charges, we the current to fall. ε q i= − R RC dq ε q = − dt R RC This is a “Differential” Equation – Here are the steps to solve a Differential Equation – 1) 2) 3) 4) 5) Guess a solution and check to see if it works. Look it up in Math Book Use “Mathematica” or some other numerical computer tool Ask a Mathematician If steps 1-4 fail… Give up…Find another problem! dq ε q = − dt R RC ( q = Cε 1 − e − t / RC see page 999 in Y&F for solution ) ( q = Cε 1 − e − t / RC ) dq d ε −t / RC −t / RC I= = Cε 1 − e = e dt dt R ( I = I 0 e − t / RC ) d Bt e = Be Bt dt Time Dependent Circuits – The RC Circuit Example 1 – Charging a Capacitor- Capacitor has no net charge at t=0 Voltage and Current are functions of Time – However – Kirchhoff’s Rules are still valid at instant in Time vab = iR q vbc = C Ohms Law Definition of Capacitance q ε − iR − = 0 C + ε q i= − R RC Close Switch at t=0 Kirchhoff;s Loop Rule At t=0, there is no charge on the capacitor so at the “instant” the switch is closed, we expect a current of I0=ε/R. As the capacitor charges, we the current to fall. ε q i= − R RC dq ε q = − dt R RC This is a “Differential” Equation – Here are the steps to solve a Differential Equation – 1) 2) 3) 4) 5) Guess a solution and check to see if it works. Look it up in Math Book Use “Mathematica” or some other numerical computer tool Ask a Mathematician If steps 1-4 fail… Give up…Find another problem! dq ε q = − dt R RC ( q = Cε 1 − e − t / RC see page 999 in Y&F for solution ) τ = RC Time Constant ( q = Cε 1 − e − t / RC ) ε −t / RC dq d −t / RC I= = Cε 1 − e = e dt dt R ( I = I 0 e − t / RC ) d Bt e = Be Bt dt Example 2 – Discharging a CapacitorMr. Kirchhoff says: + q = Q0 e − t / RC q iR + = 0 C I = I 0 e − t / RC Exponential Decay – Which Curve is right? Strategy for understanding which curve is correct: Try to figure out what the current (or charge) would be just when the switch is closed (or opened) t=0 Then try to figure out what the current (or charge) would be after a very long time t=∞ At t=0 there is NO charge on the capacitor – and therefore no voltage across capacitor I0 I0=ε/R At t=∞ the capacitor is fully charged and there is no current: I0 I∞=0 At t=0 there is NO charge on the capacitor – therefore Q0=0 At t=∞ the capacitor is fully charged and therefor Q∞=CV QI∞ 0 End of Chapter 26 You are responsible for the material covered in T&F Sections 26.1-26.4 You are expected to: • Understand the following terms: Equivalent Resistance, Junction, Kirchhoff junction rule, Kirchhoff’s loop rule, RC circuit, RC time constant • Be able to calculate equivalent resistances in simple geometries • Be able to apply Kirchoff’s rules to determine currents and voltages in more complex geometries • Determine the current and voltage as a function of time in R-C circuits. Recommended F&Y Exercises chapter 26: • 4, 6, 11, 12, 22,24, 44,46, 48