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Transcript
```14. Introduction to inference
Objectives (PSLS Chapter 14)
Introduction to inference

REVIEW: Uncertainty and confidence

REVIEW: Confidence intervals

REVIEW: Confidence interval for a Normal population mean (σ
known)

Significance tests

Null and alternative hypotheses

The P-value

Test for a Normal population mean (σ known)
Uncertainty and confidence
If you picked different samples from a population, you would probably
get different sample means ( x̅ ) and virtually none of them would
actually equal the true population mean, .
When we take a random sample, we
can compute the sample mean and an
interval of size plus-or-minus 2σ/√n


n
n

x̅

Based on the ~68-95-99.7% rule, we
can expect that:
~95% of all intervals computed with this
method capture the parameter μ.
Red arrow: Interval
of size plus or
minus 2σ/√n
Blue dot: mean
value of a given
random sample
The margin of error, m
A confidence interval (“CI”) can be expressed as:

a center ± a margin of error m:

an interval:
 within x̅ ± m
 within (x̅ − m) to (x̅ + m)
The confidence level C
(in %) represents an area
of corresponding size C
under the sampling
distribution.
m
m
Significance tests
Someone makes a claim about the unknown value of a population
parameter. We check whether or not this claim makes sense in light of
the “evidence” gathered (sample data).
A test of statistical significance tests a specific hypothesis using
sample data to decide on the validity of the hypothesis.
You are in charge of quality control and sample randomly 4 packs of cherry
tomatoes, each labeled 1/2 lb (227 g).
The average weight from the 4 boxes is 222 g.

Is the somewhat smaller weight simply due to chance variation?

Is it evidence that the packing machine that sorts cherry
tomatoes into packs needs revision?
Null and alternative hypotheses
The null hypothesis, H0, is a very specific statement about a
parameter of the population(s).
The alternative hypothesis, Ha, is a more general statement that
complements yet is mutually exclusive with the null hypothesis.
Weight of cherry tomato packs:
H0: µ = 227 g (µ is the average weight of the population of packs)
Ha: µ ≠ 227 g (µ is either larger or smaller than as stated in H0)
Biological and statistical hypotheses
Distinguish between the biological hypotheses and the statistical
hypotheses.
They should be linked, but are unlikely to be the same.
State:
What is the practical question, in the context of a realworld setting?
Plan:
What specific statistical operations does this problem
call for?
Solve:
Make the graphs and carry out the calculations needed
for this problem.
Conclude:
Give your practical conclusion in the real-world setting.
One-sided vs. two-sided alternatives

A two-tail or two-sided alternative is symmetric:
Ha: µ  [a specific value or another parameter]

A one-tail or one-sided alternative is asymmetric and specific:
Ha: µ < [a specific value or another parameter]
OR
Ha: µ > [a specific value or another parameter]
What determines the choice of a one-sided versus two-sided test is the
question we are asking and what we know about the problem before
performing the test. If the question or problem is asymmetric, then Ha
should be one-sided. Ha should always be two-sided, unless we would
never care if the difference is in the opposite direction of the alternative
hypotheses.
Is an herbal remedy manufacturer overstating the concentration of the active
ingredient package label (325 mg/tablet)?
H0: µ = 325
Ha: µ ≠ 325
Is nicotine content greater than the written 1 mg/cigarette, on average?
H0: µ = 1
Ha: µ > 1 Ha: µ = 1
Is a new drug useful in reducing blood pressure?
H0: µ = 0
Ha: µ ≠ 0
The Probability-value (P-value)
The packaging process is Normal with standard deviation  = 5 g.
H0: µ = 227 g versus Ha: µ ≠ 227 g
The average weight from your 4 random boxes is 222 g.
What is the probability of drawing a random sample such as yours, or even
more extreme, if H0 is true?
P-value: The probability, if H0 were true, of obtaining a sample
statistic as extreme as the one obtained or more extreme.
This probability is obtained from the sampling distribution of the statistic.
What are the parameters of our working sampling distribution?
http://bcs.whfreeman.com/psls2e/#616957__662349__
Interpreting a P-value
Could random variation alone account for the difference between
H0 and observations from a random sample? The answer is yes!
You must decide if that is a reasonable working explanation.
 Small P-values are strong evidence AGAINST H0 and we reject H0.
The findings are “statistically significant.”
 Large P-values don’t give enough evidence against H0 and we fail
to reject H0. Beware: This is not evidence for “proving H0” is true.
Range of P-values
P-values are probabilities, so they are always a number between 0 and 1.
The order of magnitude of the P-value matters more than its exact
numerical value.
Possible P-values
Somewhat significant
Highly significant
Very significant
Significant
0
1
--------------------------- Not significant --------------------------
The significance level α
SN: The use of alpha is an entrenched custom, which is criticized by
many statisticians. The significance level, α, is the largest P-value
tolerated for rejecting H0 (how much evidence against H0 we require).
This value is determined arbitrarily, subjectively, or based on
convention before conducting the test.

When P-value ≤ α, they reject H0.

When P-value > α, they fail to reject H0.
Industry standards require a significance level α of 5%.
Does the packaging machine need revision?
What if the the P-value is 4.56%.
What if the P-value is 5.01%
Test for a population mean (σ known)
To test H0: µ = µ0 using a random sample of size n from a Normal
population with known standard deviation σ, we use the null sampling
distribution N(µ0, σ√n).
The P-value is the area under N(µ0, σ√n) for values of x̅ at least as
extreme in the direction of Ha as that of our random sample.
Calculate the z-value
then use Table B or C.
Or use technology.
x  0
z
 n
P-value in one-sided and two-sided tests
One-sided
(one-tailed) test
Two-sided
(two-tailed) test
To calculate the P-value for a two-sided test, use the symmetry of the
normal curve. Find the P-value for a one-sided test and double it.
H0: µ = 227 g versus Ha: µ ≠ 227 g
What is the probability of drawing a random sample such as this one or
worse, if H0 is true?
x  222g
  5g
n4
x is normally distributed
z
x   222  227

 2
 n
5 4
From Table B, area left of z is 0.0228.
 P-value = 2*0.0228 = 4.56%.
Sampling
distribution if
H0 were true
From Table C, two-sided P-value is
σ/√n = 2.5g
between 4% and 5% (use |z|).
2.28%
2.28%
sampling distribution questionable?
the tomato sorting machine?
217
222
227
232
x,
µ (H0)weight (n=4)
Average
package
z  2
237
Confidence intervals to test hypotheses
Because a two-sided test is symmetric, you can easily use a confidence
interval to test a two-sided hypothesis.
In a two-sided test,
C = 1 – α.
C confidence level
α significance level
α /2
α /2
Packs of cherry tomatoes (σ = 5 g): H0: µ = 227 g versus Ha: µ ≠ 227 g
Sample average 222 g. 95% CI for µ = 222 ± 1.96*5/√4 = 222 g ± 4.9 g
227 g does not belong to the 95% CI (217.1 to 226.9 g). Thus, we reject H0.
Logic of confidence interval test
A sample gives a 99% confidence interval of
x  m  0.84  0.0101.
With 99% confidence, could samples be from populations with µ =0.86? µ =0.85?
 Cannot reject
H0:  = 0.85
Reject H0:  = 0.86
99% C.I.
x
The Bad: A confidence interval doesn’t precisely gauge the level of significance.

Reject or don’t reject H0 (Are significance tests really that much better?)
The Great: It estimates a range of likely values for the true population mean µ.
A P-value quantifies how strong the evidence is against the H0, but doesn’t provide any
information about the true population mean µ.
CI vs. test of significance
Confidence intervals quantify the
Tests of significance evaluate
uncertainty in an estimate of a
statistically whether a particular
population parameter.
statement is reasonable.
Only small %
p of samples
would give x¯
so far from 
under H0
The national average birth weight is 120 oz: N(natl =120,  = 24 oz).
An SRS of 100 poor mothers gave an average birth weight x̅ = 115 oz.
Is significantly lower than the national average?
Statistical Hypotheses:
We calculate the z score for x̅:
H0: poor = 120 oz
Ha: poor ≠ 120 oz
z
(no difference with natl )
x   0 115  120

 2.083
 n 24 100
In Table B, z = –2.08 gives area beyond = 0.0188  P-value 3.7%.
In Table C, we find that the P-value is between 2% and 4%.
```
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