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MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 15 = 5 + 5 + 5 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 15 = 5 + 5 + 5 3 standard deviations from the mean MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 15 = 5 + 5 + 5 3 standard deviations from the mean This time, When endpoints are 3 standardlet’s take deviations from the mean advantage of the summary 99.7% of scores sheet we 49.85% 49.85% 0.15% 0.15% developed. 𝜇 − 3𝜎 𝜇 𝜇 + 3𝜎 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 15 = 5 + 5 + 5 3 standard deviations from the mean This time, When endpoints are 3 standardlet’s take deviations from the mean advantage of the summary 99.7% of scores sheet we 49.85% 49.85% 0.15% 0.15% developed. 𝜇 − 3𝜎 𝜇 18 𝜇 + 3𝜎 33 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 18 and a standard deviation of 5. Use the 68-95-99.7 rule to find the percentage of values between 18 and 33. 33 − 18 = 15 15 = 5 + 5 + 5 3 standard deviations from the mean This time, When endpoints are 3 standardlet’s take deviations from the mean advantage of the summary 99.7% of scores sheet we 49.85% 49.85% 0.15% 0.15% developed. 𝜇 − 3𝜎 𝜇 18 𝜇 + 3𝜎 33 49.85% of the values are between 18 and 33. MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean When endpoints are 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 𝜇 2.5% 𝜇 + 2𝜎 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean When endpoints are 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 𝜇 2.5% 𝜇 + 2𝜎 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean When endpoints are 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 9 𝜇 15 2.5% 𝜇 + 2𝜎 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean When endpoints are 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 9 𝜇 15 2.5% 𝜇 + 2𝜎 MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 6=3+3 2 standard deviations from the mean When endpoints are 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 9 𝜇 15 2.5% 𝜇 + 2𝜎 47.5% + 47.5% + 2.5% = 97.5% MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises A normal distribution has a mean of 15 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie above 9. 15 − 9 =6 When endpoints are 2 standard deviations from the mean 6=3+3 2 standard deviations from the mean 2.5% 95% of scores 47.5% 47.5% 𝜇 − 2𝜎 9 𝜇 15 2.5% 𝜇 + 2𝜎 47.5% + 47.5% + 2.5% = 97.5% 97.5% of the values are between 18 and 33.