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MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
15 = 5 + 5 + 5
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
15 = 5 + 5 + 5
3 standard
deviations from
the mean
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
15 = 5 + 5 + 5
3 standard
deviations from
the mean
This time,
When endpoints are 3 standardlet’s take
deviations from the mean advantage of
the summary
99.7% of scores
sheet we
49.85%
49.85%
0.15%
0.15%
developed.
𝜇 − 3𝜎
𝜇
𝜇 + 3𝜎
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
15 = 5 + 5 + 5
3 standard
deviations from
the mean
This time,
When endpoints are 3 standardlet’s take
deviations from the mean advantage of
the summary
99.7% of scores
sheet we
49.85%
49.85%
0.15%
0.15%
developed.
𝜇 − 3𝜎
𝜇
18
𝜇 + 3𝜎
33
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 18 and a standard deviation of 5.
Use the 68-95-99.7 rule to find
the percentage of values between 18 and 33.
33 − 18 = 15
15 = 5 + 5 + 5
3 standard
deviations from
the mean
This time,
When endpoints are 3 standardlet’s take
deviations from the mean advantage of
the summary
99.7% of scores
sheet we
49.85%
49.85%
0.15%
0.15%
developed.
𝜇 − 3𝜎
𝜇
18
𝜇 + 3𝜎
33
49.85% of the values are between 18 and 33.
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
When endpoints are 2 standard
deviations from the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
𝜇
2.5%
𝜇 + 2𝜎
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
When endpoints are 2 standard
deviations from the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
𝜇
2.5%
𝜇 + 2𝜎
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
When endpoints are 2 standard
deviations from the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
9
𝜇
15
2.5%
𝜇 + 2𝜎
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
When endpoints are 2 standard
deviations from the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
9
𝜇
15
2.5%
𝜇 + 2𝜎
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
6=3+3
2 standard
deviations from
the mean
When endpoints are 2 standard
deviations from the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
9
𝜇
15
2.5%
𝜇 + 2𝜎
47.5% + 47.5% + 2.5% = 97.5%
MATH 110 Sec 14-4 Lecture: Statistics-The Normal Distribution Practice Exercises
A normal distribution has a mean of 15 and a standard deviation of 3.
Use the 68-95-99.7 rule to find the percentage of values that lie above 9.
15 − 9 =6
When endpoints are 2 standard
deviations from the mean
6=3+3
2 standard
deviations from
the mean
2.5%
95% of scores
47.5%
47.5%
𝜇 − 2𝜎
9
𝜇
15
2.5%
𝜇 + 2𝜎
47.5% + 47.5% + 2.5% = 97.5%
97.5% of the values are between 18 and 33.