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Lesson 9-6 Perfect Squares and Factoring Determine whether each trinomial is a perfect square trinomial. If so, factor it. • Questions to ask. •16x2 + 32x + 64 •Is the first term a perfect square? Yes, 16x2 = (4x)2 •Is the last term a perfect square? Yes, 64 = 82 •Is the middle term equal to 2(4x)(8)? No, 32x 2(4x)(8) 16x2 + 32x + 64 is not a perfect square trinomial. Determine whether each trinomial is a perfect square trinomial. If so, factor it. • 25x2 - 30x + 9 •49x2 + 42x + 36 Number of Terms Factoring Technique 2 or more Greatest Common Factor 2 Difference of Squares Perfect square trinomial a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2 x2 + bx + c x2 + bx + c = (x + m)(x + n), when m + n = b and mn = c. ax2 + bx + c ax2 + bx + c = ax2 + mx + nx+ c, when m + n = b and mn = ac. Then using factoring by grouping Factoring by grouping ax + bx + ay + by = x(a + b) + y(a + b) = (a + b)(x + y) 3 4 or more a2 - b2 = (a + b)(a - b) Ex. 2 Factor Completely Factor each polynomial •4x2 - 36 •First check for the GCF. Then, since the polynomial has two terms, check for the difference of two squares. 4x2 - 36 = 4(x2- 9) 4 is the GCF = 4(x2 - 32) x2 = x x, and 9 = 3 3 = 4(x + 3)(x - 3) factor the difference of squares. Ex. 2 Factor Completely 25x2 + 5x - 6 •This polynomial has three terms that have a GCF of 1. While the first term is a perfect square 25x2 = (5x)2, the last term is not. Therefore, this is not a perfect square trinomial. •This trinomial is one of the form ax2 + bx + c. Are there two numbers m and n whose product is 25 -6 or -150 and whose sum is 5? Yes, the product of 15 and -10 is -150 and their sum is 5. 25x2 + 5x - 6 = 25x2 + mx + nx - 6 Write the pattern = 25x2 + 15x - 10x - 6 m = 15 and n = -10 = (25x2 + 15x) + ( -10x - 6) Group terms with common factors. = 5x(5x + 3) -2 ( 5x + 3) Factor out the GCF for each grouping. = (5x + 3) (5x - 2) 5x + 3 is the common factor. Factor each polynomial. •6x2 - 96 •16x2 + 8x -15 Ex. 3 Solve Equations with Repeated Factors. Solve x2 - x + ¼ = 0 x2 - x + ¼ = 0 Original equation x2 - 2(x)(½) + (½)2 = 0 Recognize x2 - x + ¼ as a perfect square trinomial (x - ½)2 = 0 Factor the perfect square trinomial. x-½=0 Set repeated factor equal to zero. x=½ Solve for x. Factor each polynomial. •4x2 + 36x + 81 Key Concept • For any number n > 0, if x2 = n, then x = n x2 = 9 x2 = 9 or 3 Ex. 4 Use the Square Root Property to Solve Equations Solve (a + 4)2 = 49 (a + 4)2 = 49 a+4= 49 Original equation Square Root Property a+4=7 49 = 7 7 a = -4 7 Subtract 4 from each side. a = -4 + 7 or a = -4 - 7 Separate into two equations. a = 3 or a = -11 Simplify Ex. 4 Use the Square Root Property to Solve Equations Solve y2 -4y + 4 = 25 y2 -4y + 4 = 25 Original equation (y)2 -2(y)(2) + 22 Recognize perfect square trinomials. (y - 2)2 = 25 Factor perfect square trinomial. y-2= Square root property. 25 y-2=5 25 = 5 5 y = 2 + 5 or y = 2 - 5 Separate into two equations. y = 7 or y = -3 Simplify Ex. 4 Use the Square Root Property to Solve Equations Solve (x - 3)2 = 5 (x - 3)2 = 5 x-3= x =3 Original equation 5 5 Square root property. Add 3 to each side. x = 3 + 5 or x = 3 - 5 Separate into two equations. x ≈ 5.24 or x ≈ 0.76 Simplify Solve each equation. Check your solutions. •(b - 7)2 = 36 •y2 + 12y + 36 = 100 •(x + 9)2 = 8