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Transcript
6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) Peak value * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T f = 1 T Peak to peak value 6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) Peak value * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T f = 1 T Peak to peak value 6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) Peak value * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , Peak to peak value 6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , 6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) Peak value * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , 6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers AC measurements Frequency: f (Hz) Peak value * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. * Mains frequency is 50 Hz , Peak to peak value 6.1 Alternating current and power * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T One cycle f = 1 T Peak value Peak to peak value 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R also Av value of a sin 2 plot = 1/2 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R also Av value of a sin 2 plot = 1/2 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R also Av value of a sin 2 plot = 1/2 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R also Av value of a sin 2 plot = 1/2 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater maximum power is supplied = Io2 R At peak current Io At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io 2 R also Av value of a sin 2 plot = 1/2 6.1 Alternating current and power 6.1 Alternating current and power 6.1 Alternating current and power 6.1 Alternating current and power 6.1 Alternating current and power 6.1 Alternating current and power 6.1 Alternating current and power The mean power supplied to a resistor: 6.1 Alternating current and power The mean power supplied to a resistor: 6.1 Alternating current and power 6.1 Alternating current and power
