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Thermodynamics Thermodynamics Heat and Forces Thermodynamics Dynamics is to do with forces and motion Thermal Thermometer Thermo means heat Internal Energy, Heat and Work Internal energy is the total PE and KE of all the molecules in an object Heat is energy that is transferred due to temperature difference (conduction, convection or radiation) Work is done when a force changes its point of application F First Law ΔQ = heat added ΔU =increase in internal energy ΔW work done by the system ΔQ = ΔU + ΔW 100 = 20 + 80 ΔQ = 100J ΔW = +80J ΔU = 20 J First Law ΔQ = heat added ΔU =increase in internal energy ΔW work done by the system ΔQ = -60J ΔQ = ΔU + ΔW -60 = 40 - 100 Negative because work done ON the gas ΔW = -100J ΔU= 40J ΔW = PΔv ΔW = F x d ΔW = PxA xd ΔW = PΔv d x A = ΔV p ΔW = pΔV v1 v2 A F d v P = F/A F = PxA Isothermal p Constant Temperature ΔU = 0 ΔQ = ΔU + ΔW ΔQ = ΔW Boyles’ Law is an example of isothermal change ΔQ Compression must happen slowly and walls should be thin so that heat can escape ΔQ ΔW v ΔW ΔW Adiabatic No heat enters or leaves the system ΔQ = 0 ΔQ =ΔU + ΔW ΔU = -ΔW The compression must happen quickly and the walls should be well insulated Diesel engines use adiabatic compression to ignite the fuel Once again the adiabatic line is The line is steeper steeper than the than the isothermal isothermal. The line. The pressure pressure goes down goes up because because the volume the volume gets gets bigger and smaller and because the because the goes gas temperature getsdown warmer p v -ΔU ΔU -ΔW ΔW Isobaric Isobaric means constant pressure As in Charles law p ΔW = pΔv v Isovolumetric Δv = 0 Like in the pressure law What is ΔW? ΔW = 0 p v Heat Engine A device that changes heat energy to useful work is called a heat engine. A steam engine and an internal combustion engine are both examples of a heat engine You do not need to know the details of how these work. We just draw a very simple diagram. Efficiency = ΔW/Qhot Efficiency = Qhot-Qcold Qhot hot Q hot Qhot = Qcold + ΔW ΔW Q cold cold Remember this is the best an engine can possibly be at these temperatures. A real engine will be less efficient than this We all know that efficiency cannot be Carnot Efficiency more than 100% so ΔW has to be less than QH However with heat engines it has to be a lot less than this or it breaks the second law of thermodynamic A clever French dude called Carnot worked out that the best efficiency a heat engine can ever have is 600 – 300 300 Efficiency = Thot – Tcold = 50% Thot What is the Carnot efficiency of this engine? 600K Q hot ΔW Q cold 300K Carnot Cycle Carnot also worked out that to get this maximum efficiency you would need Isothermal compression Adiabatic compression Isothermal expansion Adiabatic expansion p ΔW v Coin toss If you toss two coins what is the most likely outcome? 2 heads, 2 tails, 1 head and 1 tail H H H T 25% 50% T H T T 25% Drop balls in the box 3 41 2 If we drop 4 balls what is the most likely outcome? 4-0 1 way 3-1 4 ways 2-2 6 ways 1-3 4 ways 0-4 1 way 3 4 2 4 2 23 31 4 1 13 42 4 1 12 33 4 1 1212324 34 It doesn’t have to end like this but this is the most common way 1 2 1 3 12 13 44 21 23 34 31 22 44 1412323434 100 balls If you drop 100 balls the chances of all landing on 1 side is 2100 This is 1.3 x 1030 The universe is 4.7 x 1017 seconds old If all 6 billion people on Earth dropped balls every second for the entire age of the universe they would be very unlikely to get 100 on one side You are very likely to get about half on each side Air molecules move at random Gasp ! What’s to stop all the air molecules moving to the other side of the room? Nothing, except the laws of probability When we deal with a billion billion air molecules it is as near certain as anything can be that this won’t happen. Entropy With twelve balls there is a 1 in 212 chance that they will unmix. This is 1 in 4096 It might happen With a hundred balls it wont With a billions and billions of molecules it wont This is why heat engines cannot be 100% efficient Kinetic energy is organised. All the molecules move in the same direction KE changes to internal energy in a collision there are so many molecules that the chances of this IfBut all the molecules vibrate in the same direction at the same time then Internal energy is random. All the molecules vibrate independently happening are rediculous. warm objects would suddenly start to move The second Law of Thermodynamics The entropy of a system and its environment cannot decrese Entropy means disorder Smashed cups cannot mend themselves Warm water cannot be unmixed to give hot and cold water Heat energy cannot be completely turned into work ΔS = ΔQ/T The above equation can be used to calculate the change in entropy (ΔS) Assume this heat engine has the ideal Carnot efficiency: T1 –T2 / T1 = 600-300/ 600 = 50% ΔS = -100/600 + 50/300 = 0 Zero change in entropy This is an ideal engine, it works in theory but friction would not allow this in practice ΔQ is negative because heat is lost 600K 100J Q hot 50J ΔW 50J 300K Q cold Greater than Carnot efficiency What if efficency = 60%? 600K ΔS = -100/600 + 40/300 = - 0.033JK-1 100J Entropy decreases! The positive bit got Impossible smaller That’s why we need 40J Carnot’s theorem 300K Q hot 60J ΔW Q cold A real engine If efficiency is less than 50%, say 40% ΔS = -100/600 + 60/300 = - 0.167 + 0.02 = + 0.033 JK-1 Change in entropy is positive so this machine does not break the second law 600K 100J Q hot 40J ΔW 60J 300K Q cold