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Module G1 Electric Power Generation and Machine Controls James D. McCalley Overview • Energy transformation into electrical form • Generation operation – – – – – Revolving magnetic field Phasor diagram Equivalent Circuit Power relationships Generator pull-out power • Excitation control • Turbine speed control Energy Transformation • Transformation processes: – Chemical – photovoltaic – electromechanical • Electromechanical: conversion of energy from coal, petroleum, natural gas, uranium, water flow, geothermal, and wind into electrical energy • Turbine-synchronous AC generator conversion process most common in industry today Click on the below for some pictures of power plants and synchronous generators ISU Power Plant http://powerlearn.ee.iastate.edu/library/html/isupp39.html ISU Power Plant synchronous generator http://powerlearn.ee.iastate.edu/library/html/isupp1.html Ames Power Plant http://powerlearn.ee.iastate.edu/library/html/amespp34.html Ames Power Plant synchronous generator http://powerlearn.ee.iastate.edu/library/html/amespp1.html Feedback Control Systems for Synchronous Generators • Turbine-generator basic form • Governor and excitation systems are known as feedback control systems; they control the speed and voltage respectively Synchronous Machine Structure ROTOR (field winding) + N + DC Voltage The negative terminal for each phase is 180 degrees from the corresponding positive terminal. STATOR (armature winding) S + A Two Pole Machine (p=2) Salient Pole Structure Salient Pole Construction Smooth rotor Construction Synchronous Machine Structure N S S N A Four Pole Machine (p=4) (Salient Pole Structure) Generation Operation • The generator is classified as a synchronous machine because it is only at synchronous speed that it can develop electromagnetic torque 2 • m p e • e 2f = frequency in rad/sec • Ns 120 f = machine speed in RPM p • p = number of poles on the rotor of the machine For 60 Hz operation (f=60) • Synchronous generator Rotor construction Round Rotor Two pole Four Pole Eight Pole Salient Pole s = 3600 rpm s = 1800 rpm s = 900 rpm For 60 Hz operation (f=60) No. of Poles (p) ------------------2 4 6 8 10 12 14 16 18 20 Synchronous speed (Ns) ----------------------------3600 1800 1200 900 720 600 514 450 400 360 Fact: hydro turbines are slow speed, steam turbines are high speed. Do hydro-turbine generators have few poles or many? Do steam-turbine generators have few poles or many? Fact: salient pole incurs significant mechanical stress at high speed. Do steam-turbine generators have salient poles or smooth? Fact: Salient pole rotors are cheaper to build than smooth. Do hydro-turbine generators have salient poles or smooth? Generation Operation • A magnetic field is provided by the DC-current carrying field winding which induces the desired AC voltage in the armature winding • Field winding is always located on the rotor where it is connected to an external DC source via slip rings and brushes or to a revolving DC source via a special brushless configuration • Armature winding is located on the stator where there is no rotation • The armature consists of three windings all of which are wound on the stator, physically displaced from each other by 120 degrees Synchronous Machine Structure • voltage induced in phase wdgs by flux from field wdg + • current in phase wdgs produces flux that also induces voltage in phase wdgs. N + DC Voltage S + Rotor Stator winding Brushes +Stator winding Slip rings Generation Operation: The revolving magnetic field • f = flux associated with the revolving magnetic field which links the armature windings. It will have a flux density of B. • At any given time t, the B-field will be constant along the coil. • By Faraday’s Law of Induction, the rotating magnetic field will induce voltages phase displaced in time by 120 degrees (for a two pole machine) in the three armature windings • Let’s consider just the A-phase. eA (u B) dl c _ u B B field + Direction of rotation Voltage induced in the conductor = Blu e Stator t 0 2t Air B, flux density gap in the air gap Rotor Magnetic field lines Voltage induced in one turn ( 2 conductors) is e = 2Blu. If there are N turns per winding, the voltage induced is e = 2NBlu. If the speed of rotation of the rotor is , and the radius of the rotor is r, u = r, and e = 2NBlr If the flux density changes sinusoidally in the air gap, B = Bmax sin t, and the induced voltage is e = 2BmaxNlr sin t = Emax sin t Generation Operation: The revolving magnetic field (cont’d) If each of the three armature windings are connected across equal impedances, balanced three phase currents will flow in them producing their own magnetic fields a = b = c • ar = resultant field with associated flux obtained as the sum of the three component fluxes is the field of armature reaction • The two fields represented by f and arare stationary with respect to each other • The armature field has “locked in” with the rotor field and the two fields are said to be rotating in synchronism • The total resultant field r = ar + f Generation Operation: The phasor diagram • From Faraday’s Law of Induction, a voltage is induced in each of the three armature windings: d r where N = number of winding turns e N dt • All voltages, Er , Ear , E f ,lag their corresponding fluxes, r , ar , f ,by 90 degrees • The current winding a, denoted by Ia , is in phase with the flux it produces ar Generation Operation: The phasor diagram (cont’d) • Note: Er E f Ear Generation Operation: The equivalent circuit model • Develop equivalent model for winding a only; same applies to winding b and c with appropriate 120 degree phase shifts in currents and voltages given a balanced load Ear N dar dt ( X ar 90) Ia jX ar Ia Er E f jX ar Ia Vt Er jX l I a E f j( X l X ar ) I a E f jX s Ia Generation Operation: The equivalent circuit model (cont’d) Generation Operation: The equivalent circuit model (cont’d) Ia jXs Ef Vt Zload Generation Operation: The equivalent circuit model (cont’d) You can perform per-phase equivalent analysis or you can perform per-unit analysis. In per-phase, Ef and Vt are both line to neutral voltages, Ia is the line current, and Z is the impedance of the equivalent Y-connected load. In per-unit, Ef and Vt are per-unit voltages, Ia is the per unit current, and Z is the per unit load impedance. Leading and Lagging Generator Operation Let Z | Z | , Vt | Vt | V From the equivalent circuit, Vt | Vt | V | Vt | Ia (V ) Z | Z | | Z | So here we see that i V V i Leading and Lagging Generator Operation Assign Vt as the reference: V 0 Then, Vt | Vt | | Vt | Ia (V ) ( ) Z |Z| |Z| So here we see that i This gives an easy way to remember the relation between load, sign of current angle, leading/lagging, and sign of power angle. Leading and Lagging Generator Operation Circle the correct answer in each column Inductive load Capacitive load ---------------------------------------------------------------- load absorbs/supplies Q gen absorbs/supplies Q X ?0 ?0 i ? 0 load absorbs/supplies Q gen supplies/absorbs Q X ?0 ?0 i ? 0 current is leading/lagging current is leading/lagging Phasor Diagram for Equivalent Circuit Ia jXs Ef From KVL: E f Vt jX s I a Vt Zload Phasor Diagram for Equivalent Circuit E f Vt jX s I a This equation gives directions for constructing the phasor diagram. 1. Draw Vt phasor 2. Draw Ia phasor 3. Scale Ia phasor magnitude by Xs and rotate it by 90 degrees. 4. Add scaled and rotated vector to Vt Try it for lagging case. Ia XsIa Ef jXsIa jXsIa Vt Phasor Diagram for Equivalent Circuit E f Vt jX s I a This equation gives directions for constructing the phasor diagram. 1. Draw Vt phasor 2. Draw Ia phasor 3. Scale Ia phasor magnitude by Xs and rotate it by 90 degrees. 4. Add scaled and rotated vector to Vt You do it for leading case. Phasor Diagram for Equivalent Circuit E f Vt jX s I a Let’s define the angle that Ef makes with Vt as E f | E f | For generator operation (power supplied by machine), this angle is always positive. For motor operation, this angle is negative.