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Translation of ER-diagram into Relational Schema Prof. Sin-Min Lee Department of Computer Science 1 Learning Objectives Define each of the following database terms Relation Primary key Functional dependency Foreign key Referential integrity Field Data type Null value 9.2 2 Learning Objectives Discuss the role of designing databases in the analysis and design of an information system Learn how to transform an entityrelationship (ER) Diagram into an equivalent set of well-structured relations 9.3 3 Process of Database Design • 9.4 Logical Design – Based upon the conceptual data model – Four key steps 1. Develop a logical data model for each known user interface for the application using normalization principles. 2. Combine normalized data requirements from all user interfaces into one consolidated logical database model 3. Translate the conceptual E-R data model for the application into normalized data requirements 4. Compare the consolidated logical database design with the translated E-R model and produce one final logical database model for the application 4 9.5 5 Relational Database Model • Data represented as a set of related tables or relations • Relation – A named, two-dimensional table of data. Each relation consists of a set of named columns and an arbitrary number of unnamed rows – Properties • Entries in cells are simple • Entries in columns are from the same set of values • Each row is unique • The sequence of columns can be interchanged without changing the meaning or use of the relation 9.6 • The rows may be interchanged or stored in any sequence 6 Relational Database Model • Well-Structured Relation – A relation that contains a minimum amount of redundancy and allows users to insert, modify and delete the rows without errors or inconsistencies 9.7 7 Transforming E-R Diagrams into Relations • It is useful to transform the conceptual data model into a set of normalized relations • Steps 1. Represent entities 2. Represent relationships 3. Normalize the relations 4. Merge the relations 9.8 8 Transforming E-R Diagrams into Relations 1. Represent Entities – Each regular entity is transformed into a relation – The identifier of the entity type becomes the primary key of the corresponding relation – The primary key must satisfy the following two conditions a. The value of the key must uniquely identify every row in the relation b. The key should be nonredundant 9.9 9 9.10 10 Transforming E-R Diagrams into Relations 2. Represent Relationships – Binary 1:N Relationships • Add the primary key attribute (or attributes) of the entity on the one side of the relationship as a foreign key in the relation on the right side • The one side migrates to the many side 9.11 11 9.12 12 Transforming E-R Diagrams into Relations – Binary or Unary 1:1 • Three possible options a. Add the primary key of A as a foreign key of B b.Add the primary key of B as a foreign key of A c. Both 9.13 13 Transforming E-R Diagrams into Relations 2. Represent Relationships (continued) – Binary and higher M:N relationships • Create another relation and include primary keys of all relations as primary key of new relation 9.14 14 9.15 15 Transforming E-R Diagrams into Relations – Unary 1:N Relationships • Relationship between instances of a single entity type • Utilize a recursive foreign key – A foreign key in a relation that references the primary key values of that same relation – Unary M:N Relationships • Create a separate relation • Primary key of new relation is a composite of two attributes that both take their values from the same primary key 9.16 16 9.17 17 9.18 18 Transforming E-R Diagrams into Relations 3. Merging Relations (View Integration) – – Purpose is to remove redundant relations View Integration Problems • Synonyms • Homonyms • – – – – Two different names used for the same attribute When merging, get agreement from users on a single, standard name A single attribute name that is used for two or more different attributes Resolved by creating a new name Dependencies between nonkeys – – Dependencies may be created as a result of view integration In order to resolve, the new relation must be normalized 9.19 19 Primary Key Constraints • A set of fields is a key for a relation if : 1. No two distinct tuples can have same values in all key fields, and 2. This is not true for any subset of the key. – Part 2 false? A superkey. – If there’s >1 key for a relation, one of the keys is chosen (by DBA) to be the primary key. • E.g., sid is a key for Students. (What about name?) The set {sid, gpa} is a superkey. Primary key can not have null value 20 Foreign Keys, Referential Integrity • Foreign key : Set of fields in one relation that is used to `refer’ to a tuple in another relation. (Must correspond to primary key of the second relation.) Like a `logical pointer’. • E.g. sid is a foreign key referring to Students: – Enrolled(sid: string, cid: string, grade: string) – If all foreign key constraints are enforced, referential integrity is achieved, i.e., no dangling references. – Can you name a data model w/o referential integrity? 21 Enforcing Referential Integrity • Consider Students and Enrolled; sid in Enrolled is a foreign key that references Students. • What should be done if an Enrolled tuple with a non-existent student id is inserted? (Reject it!) • What should be done if a Students tuple is deleted? – Also delete all Enrolled tuples that refer to it. – Disallow deletion of a Students tuple that is referred to. – Set sid in Enrolled tuples that refer to it to a default sid. 22 Logical DB Design: ER to Relational • Entity sets to tables. ssn name Employees lot CREATE TABLE Employees (ssn CHAR(11), name CHAR(20), lot INTEGER, PRIMARY KEY (ssn)) 23 Relationship Sets to Tables • In translating a relationship set to a relation, attributes of the relation must include: – Keys for each participating entity set (as foreign keys). • This set of attributes forms a superkey for the relation. CREATE TABLE Works_In( ssn CHAR(1), did INTEGER, since DATE, PRIMARY KEY (ssn, did), FOREIGN KEY (ssn) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments) 24 Review: Key Constraints since • Each dept has at most one manager, name ssn dname lot Employees did Manages budget Departments according to the key constraint on Manages. 1-to-1 1-to Many Translation to relational model? Many-to-1 Many-to-Many 25 Translating ER Diagrams with Key Constraints • Map relationship to a table: – Note that did is the key now! – Separate tables for Employees and Departments. • Since each department has a unique manager, we CREATE TABLE Manages( ssn CHAR(11), did INTEGER, since DATE, PRIMARY KEY (did), FOREIGN KEY (ssn) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments) CREATE TABLE Dept_Mgr( did INTEGER, dname CHAR(20), budget REAL, ssn CHAR(11), since DATE, PRIMARY KEY (did), FOREIGN KEY (ssn) REFERENCES Employees) 26 Review: Participation Constraints • Does every department have a manager? – If so, this is a participation constraint: the participation of Departments in Manages is said to be total (vs. partial). since name dname ssn did budget lot in Departments • Every did value table must appearEmployees in a row ofManages the ManagesDepartments table (with a non-null ssn value!) Works_In since 27 Participation Constraints in SQL • We can capture participation constraints involving one entity set in a binary relationship, butDept_Mgr( little else (without CREATE TABLE did INTEGER, resorting to CHAR(20) CHECK, constraints). dname budget REAL, ssn CHAR(11) NOT NULL, since DATE, PRIMARY KEY (did), FOREIGN KEY (ssn) REFERENCES Employees, ON DELETE NO ACTION) 28 Review: Weak Entities • A weak entity can be identified uniquely only by considering the primary key of another (owner) entity. – Owner entity set and weak entity set must participate name in a one-to-many relationship set (1 cost ssn lot entities). owner, many weak – pname age WeakEmployees entity set must have total participation in Policy Dependents this identifying relationship set. 29 Translating Weak Entity Sets • Weak entity set and identifying relationship set are translated into a single table. CREATE TABLE Dep_Policy ( pnamethe CHAR(20) , entity is deleted, all – When owner age INTEGER, owned weak entities must also be cost REAL, ssn CHAR(11) NOT NULL, deleted. PRIMARY KEY (pname, ssn), FOREIGN KEY (ssn) REFERENCES Employees, ON DELETE CASCADE) 30 Review: Binary vs. Ternary Relationships name ssn • If each policy is owned by just 1 employee: – Key constraint on Policies would mean policy can only cover 1 pname lot Employees Dependents Covers Bad design Policies policyid cost name ssn age pname lot age Dependents Employees Purchaser Better design policyid Beneficiary Policies cost 31 Binary vs. Ternary Relationships (Contd.) CREATE TABLE Policies ( policyid INTEGER, cost REAL, ssn CHAR(11) NOT NULL, PRIMARY KEY (policyid). FOREIGN KEY (ssn) REFERENCES Employees, ON DELETE CASCADE) • The key constraints allow us to combine Purchaser with CREATE TABLE Dependents ( Policies and pname CHAR(20), age INTEGER, Beneficiary policyid INTEGER, with PRIMARY KEY (pname, policyid). FOREIGN KEY (policyid) REFERENCES Policies, Dependents. • Participation ON DELETE CASCADE) 32 Relational Model: Summary • A tabular representation of data. • Simple and intuitive, currently the most widely used. • Integrity constraints can be specified by the DBA, based on application semantics. DBMS checks for violations. – Two important ICs: primary and foreign keys – In addition, we always have domain constraints. • Powerful and natural query languages exist. • Rules to translate ER to relational model 33 An Example CREATE TABLE Student ( ID NUMBER, Fname VARCHAR2(20), Lname VARCHAR2(20), ); 34 Constraints in Create Table • Adding constraints to a table enables the database system to enforce data integrity. • Different types of constraints: * Not Null * Default Values * Unique * Primary Key * Foreign Key * Check Condition 35 Not Null Constraint CREATE TABLE Student ( ID NUMBER, Fname VARCHAR2(20) NOT NULL, Lname VARCHAR2(20) NOT NULL, ); 36 Primary Key Constraint CREATE TABLE Student ( ID NUMBER PRIMARY KEY, Fname VARCHAR2(20) NOT NULL, Lname VARCHAR2(20) NOT NULL, ); Primary Key implies: * NOT NULL * UNIQUE. There can only be one primary key. 37 Primary Key Constraint (Syntax 2) CREATE TABLE Students ( ID NUMBER, Fname VARCHAR2(20) NOT NULL, Lname VARCHAR2(20) NOT NULL, PRIMARY KEY(ID) ); Needed when the primary key is made up of two or more fields 38 Another Table CREATE TABLE Studies( Course NUMBER, Student NUMBER ); What should be the primary key? What additional constraint do we want on Student? 39 Foreign Key Constraint CREATE TABLE Studies( Course NUMBER, Student NUMBER, FOREIGN KEY (Student) REFERENCES Students(ID) ); NOTE: ID must be unique (or primary key) in Student 40 Translating ER-Diagrams to Table Definitions 41 Relations vs. Tables • We show how to translate ER-Diagrams to table definitions • Sometimes, people translate ER-Diagrams to relation definitions, which is more abstract than table definitions. – e.g., Student(ID, Fname, Lname); – table definitions contain, in addition, constraints and datatypes 42 Translating Entities id name birthday Actor address General Rule: • Create a table with the name of the Entity. • There is a column for each attribute • The key in the diagram is the primary key of the table 43 Translating Entities id birthday Actor name address Relation: Actor (id, name, birthday, address) create table Actor(id varchar2(20) primary key, name varchar2(40), birthday date, address varchar2(100)); 44 Translating Relationships (without constraints) title birthday id Actor Acted In Film year name address salary type General Rule: • Create a table with the name of the relationship • The table has columns for all of the relationship's attributes and for the keys of each entity participating in the relationship • What is the primary key of the table? • What foreign keys are needed? 45 Translating relationships (without constraints) birthday id Actor Acted In Film title year name address salary type What would be the relation for ActedIn? How would you define the table for ActedIn? 46 Translating Recursive Relationships (without constraints) manager id Employee name worker Manages address Relation: Actor (worker-id, manager-id) What would be the table definition? 47 Translating relationships (key constraints): Option 1 id name Director Directed Film salary title year General Rule for Option 1: • Same as without key constraints, except that the primary key is defined differently 48 Translating relationships (key constraints): Option 1 id Director Directed name Film salary title year create table Directed( id varchar2(20), title varchar2(40), salary integer, What primary and foreign keys are missing? ) 49 Translating relationships (key constraints): Option 2 id name Director Directed Film salary title year General Rule for Option 2: • Do not create a table for the relationship • Add information columns that would have been in the relationship's table to the table of the entity with the key constraint • What is the disadvantage of this method? • What is the advantage of this method? 50 Translating relationships (key constraints): Option 2 id Director Directed name salary Film title year create table Film( title varchar2(40), year integer, primary key (title), What 3 lines are missing? ) 51 Translating relationships (key constraints) A R B C • What are the different options for translating this diagram? 52 Translating relationships (participation constraints) id Director name Directed Film salary title year General Rule: • If has both participation and key constraint, use Option 2 from before. • Add the not null constraint to ensure that there will always be values for the key of the other entity 53 Translating relationships (participation constraints) id Director Directed name Film title year salary create table Film( title varchar2(40), year integer, id varchar2(20), Where should we add NOT NULL? salary integer, foreign key (id) references Director, primary key (title)) 54 Translating relationships (participation constraints) id name Actor Acted In salary Film title year • How would we translate this? 55 Translating Weak Entity Sets phone number name create table award( name varchar2(40), year integer, Organization money number(6,2), o_name varchar2(40), Gives primary key(name, year, o_name), Award year foreign key (o_name) references Organization(name) money on delete cascade name ) 56 Translating ISA: Option 1 address id Movie Person name ISA picture Actor Director create table MoviePerson( ... ) create table Actor(id varchar2(20), picture bfile, primary key(id), foreign key (id) references MoviePerson)) create table Director(...) 57 Translating ISA: Option 2 address id Movie Person name ISA picture Actor Director No table for MoviePerson! create table Actor(id varchar2(20), address varchar2(100), name varchar2(20), picture blob, primary key(id)); create table Director(...) 58 Which Option To Choose? • What would you choose if: – Actor and Director DO NOT COVER MoviePerson? – Actor OVERLAPS Director? 59 Translating Aggregation phone number name Organization picture salary Gives Actor Acted In Won year Award year name Film title type • Create table for Won using: – key of ActedIn – key of Award (careful, award is a weak entity) 60