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Everything you
always wanted to
know about trig*
Explained by
John Baber, A.B.,Cd.E.
*but were afraid to ask.
Any figure drawn on a piece of paper with straight edges can be split up into right triangles. Because of this, studying squares, rectangles, rhombi, trapezoids, and all other regular and irregular polygons,
can be seen as studying right triangles only. This is why there is a subject in school called trigonometry
(measurement of triangles).
To study a right triangle fully, we have six functions defined to relate its sides and angles.
opposite
hypoteneuse
adjacent
cos θ =
hypoteneuse
opposite
tan θ =
adjacent
sin θ =
hypoteneuse
opposite
hypoteneuse
sec θ =
adjacent
adjacent
cot θ =
opposite
csc θ =
Really, sin θ and cos θ contain all of the information, the others are just shorthand.
tan θ =
sin θ
cos θ
csc θ =
1
sin θ
sec θ =
1
cos θ
cot θ =
cos θ
1
=
sin θ
tan θ
You can memorize which is which by the old stand-by SOH-CAH-TOA*. i.e.
Cosine = Adj/Hyp
Tangent = Opp/Adj
Sine = Opp/Hyp
¯
¯
¯
¯
¯
¯
¯
¯
¯
The fact that s = 1c and c = 1s , tan, and cot, you’ll just have to get used to.
Since these were defined with θ being a non-right angle in a right triangle, they only make sense when
0 < θ < π2 . The only thing you ever do with degrees is translate them into radians: (π = 180◦ ⇒ 30◦ =
π
180◦
6 = 6 etc.). So, graphs of sin and cos would look like
* Or you can use “Silly Old Harry Carried A Horse To Our Apartment” if it bothers you that Sohcahtoa
¯
¯ ¯
¯
¯ ¯
¯ ¯
¯
is meaningless aside from its similarity to Krakatoa. . .
Even though triangles with θ = 0 or θ = π2 don’t make sense, by the graphs, we can tell what the values
should be. Here’s an easy way to memorize all of the “important” values for sin, cos, and tan. Notice the
pattern in
π/6
π/4
π/3
π/2
θ
0
◦
◦
◦
◦
◦
θ
0
30
45
60
90
p
p
p
p
p
sin θ p 0/4 p 1/4 p 2/4 p 3/4 p 4/4
cos θ p 4/4 p 3/4 p 2/4 p 1/4 p 0/4
0/4
1/3
2/2
3/1
4/0
tan θ
So
cos π4 =
q
2
4
=
q
1
2
=
√1
2
=
√
2
2
To generalize these definitions so that θ can be any number, define sin θ and cos θ with a circle
Given an angle θ, find the point corresponding in the unit circle — the x-coordinate will be cos θ and
the y-coordinate will be sin θ. This is very nice for solving problems like
√
− 3
sin θ =
2
All solutions to the problem are
θ, θ + 2π,
θ + 4π,
...
θ − 2π,
ω, ω + 2π,
ω − 2π,
θ − 4π, . . .
ω + 4π, . . .
ω − 4π, . . .
which is always shortened to
θ + 2πk and ω + 2πk,
k ∈∗ Z†
In our case, we can examine the same triangle moved to the I quadrant and figure out what α is.
Looking at the table, see that α is
π
3,
π
= 43 π and ω = 2π − α = 2π
= 35 π. So
−
√ 3
k ∈ Z. A calculator, when asked for sin−1 −2 3 only tells
so θ = π + α = π +
all solutions would be these two angles +2πk,
you one of these angles, namely − π3 .
π
3
* ∈ means “member of”
† Z means “the integers”, i.e. . . . , −2, −1, 0, 1, 2, . . .
So “k ∈ Z” means “k in the set of integers” i.e. “k = . . . , −2, −1, 0, 1, 2, . . .”
With the circular definition of sin and cos, we can have the graphs we’re more accustomed to
Notice that sin−1 and cos−1 would have to be (by flipping about the 45-degree line)
but these wouldn’t be functions (since they’d fail the vertical line test), so a decision had to be made.
This is why sin−1 and cos−1 look like
These are the functions your calculator uses, which explains why it misses ∞ of the answers to a simple
question like:
Given
what is θ?
√
− 3
,
sin θ =
2
Now, how do we memorize all of the trigonometric identities we’re expected to know? First memorize
the “pythagorean identity”
sin2 θ + cos2 θ = 1
Immediately, you can see that this means
sin2 θ = 1 − cos2 θ
cos2 θ = 1 − sin2 θ
Derive the two similar identities by dividing by sin2 θ on both sides of the pythagorean identity
1 + cot2 θ = csc2 θ
and dividing by cos2 θ on both sides of the pythagorean identity
tan2 θ + 1 = sec2 θ
Now memorize the angle addition formulae and you don’t have to memorize anything else. The rest can
be derived. These are easier to understand when you say them out loud than when you read them on paper.
So, say out loud “Sine sucks”
sin(x + y) = sin x cos y + cos x sin y
(s
cos(x + y) = cos x cos y − sin x sin y
(c
c
c
s =
succs =
¯ ¯¯¯
sucks)
s
cicss =
¯ ¯¯¯
kicks)
“Cosine kicks”
c
s
=
make sure to memorize which one has a minus sign in the middle and which doesn’t.
Now you can derive every other identity anybody has ever expected of you
sin(2x) = sin(x + x) = sin x cos x + cos x sin x = 2 sin x cos x
cos(2x) = cos(x + x) = cos x cos x − sin x sin x = cos2 x − sin2 x
= cos2 x − sin2 x = cos2 x − (1 − cos2 x) = cos2 x − 1 + cos2 x = 2 cos2 x − 1
= (1 − sin2 x) − sin2 x = 1 − 2 sin2 x
From the last two, you can also see that
1 − cos 2x
2
1 + cos 2x
2
2
= 2 cos x − 1 ⇒ cos x =
2
cos 2x = 1 − 2 sin2 x ⇒ sin2 x =
Work all of the above derivations out on a piece of paper yourself. Once you’ve done it once, you can’t
help but be able to do them in the future.