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[CIRCUIT IDEAS] MUDIT AGARWAL Bicycle Turning Indicator Sanjay Kumar Turning vehicle without indicators on is always dangerous. Two wheelers and four wheelers are always equipped with indicators, whereas Bicycle doesn’t have indicators. This may prove dangerous to children. A simple solution to it is to build a circuit for it. The circuit consists of LM3909 IC. The LM3909 is a monolithic oscillator specifically designed to flash Light Emitting Diodes. Most ICs are designed to operate on voltages of 4.5 volts to 40 volts. However, the LM3909 IC is a low-voltage chip that operates from a 1.5-volt battery. Four LEDs are suitable for any LED flasher using a supply up to 6V. LM3909 IC performs functions similar to circuits containing many transistors, resistors, and capacitors. To get a diode to flash on and off at a constant rate, the flasher part of the IC is used. A flasher uses an electronic timer to control the flash rate of the LED. Electronic timers contain a resistor to restrict current flow so that a capacitor charges up slowly. Once the capacitor is charged to a predetermined voltage level, a transistor starts to conduct current to the LED. This discharges the capacitor, shuts off the transistor, and causes the S1 L R 1 6 5 Off 4 L R S2 FASTRC SLOWRC RL V+ OUT LM3909 8 Off 2 + 10nF V- + D1 Front Left D2 Front right D3 Back left U D4 Back right 1.5V used indicating the front and back indicators. To turn left move the switch to left. This will turn on the front left LED (D1) and back left LED (D3). To turn right move the switch to right .This will turn on the front right LED (D2) and back right LED (D4). By using the timing capacitor for voltage boost, it delivers pulses of 2 or more volts to the LED while operating on a supply of 1.5V or less. The circuit is inherently self-starting, and requires addition of only a battery and capacitor to function as an LED flasher. Timing capacitors will generally be of the electrolytic type, and a small 3V rated part will be LED to stop glowing. The capacitor now starts to charge again and the process is repeated. In the LM3909 IC, electrons from the battery pass through a resistor and charge up the capacitor. The size of the capacitor determines how long it will take for the capacitor to charge. Once the voltage of the capacitor reaches the level that was designed into the IC, a transistor will start conducting current from the capacitor to the LED. This results in the LED lighting up and discharging the capacitor. Once the capacitor is discharged, the LED will go out and the transistor will stop conducting current.