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Optimal Replenishment Policy for MML Step Sheets Joe Halo, Gaston Moliva, Jacob Boyle November 18th, 2014 IE 425: Stochastic Operations Research Executive Summary (300 to 400 words) This is a case study on the optimal replenishment policy of inventory of step sheets that will be inserted into a folder providing detailed information about the program. The information provided on these sheets will be curriculum, partnership with industry, admission guidelines, placement statistics, and financial assistance. Ordering of these step sheets must be done in large quantities in order to be cost efficient, however the tricky part is re-printing after some of the information in the packets is changed or becomes out dated. ACG also known as Advanced Color Graphics is the company through which these documents are printed by and with that, they set the prices and set bundles. As it is stated in the Introduction the cost of ordering an exact reprint is $1,157 for the initial 500 sets and an additional $174 for every 500 sets. Unfortunately for the university, if the reprint has changes or updates made to it the price goes up to $1,532 for the initial set of 500, but the price for 500 additional sets stays the same at $174. It is known that the current demand for step sheets is 1000 per year and the probability that the step sheets require an update at the end of any given academic year is approximately 0.255. As found in this case study the most economic order quantity (EOQ) that minimizes the average annual cost is 4000 sets. In order to come to this conclusion transition state diagrams were built, that can be found in the appendix, and a cost analysis was done on various order quantities ranging from 1000 to 5000. As part of the cost analysis the probability matrix was formed from the transition state diagrams and the steady state probabilities were calculated from that matrix. The fact that 4000 sets is the most economical order quantity gives some insight as to how the university should continue to business with ACG. Even though the demand is only 1000 per year, orders should only be placed in quantities of 4000 and saved for the next years. Introduction The objective of the case study was to determine the most economical way to re order sheets for their program to give out to prospective students. Every year there is a demand of 1000 sheets with a cost of $1157 without a redesign and a cost of $1532 with a redesign for the first 500 sheets and any additional 500 sheets was $174 for both scenarios. After every year there is a probability of .255 that there will be a redesign after each year. Given all these conditions identifying a cost effective solution had to be calculated. Estimated costs for several scenarios were calculated where the program order different amounts of sheets such as 1000, 2000, 3000 and so on at the beginning of each year. Problem statement The MML program requires sheets to give to their prospective student, at a rate of around 1000 per year. Due to the demand, the sheets have almost declines to zero and the program has to reorder new sheets. The objective is to find the economic order quantity that minimizes the cost for the program. At a rate of $1157 to reorder without changes and $1532 to reorder with changes for 500 sheets and any additional 500 sheets is $174 for both, the reorder quantity has to be calculated so that the company orders so that the cheapest alternative is bought. The rate in which the changes occur to the sheets is .255, this has to be taken into account so the correct amount is ordered. It is assumed that the MML program orders sheets once a year. With having a demand of 1000 each year it is also assumed that the MML program will only order in quantities of 1000. Starting at 1000 and going as high as they feel necessary. With this model in mind the total cost for each group of orders (1000, 2000, 3000, 4000, etc) were calculated. This would then be plotted to find where the price dipped lowest and then began trending back upwards. The lowest part of this U-shaped graph would be the economic order quantity (EOQ). To calculate these costs a steady state diagram was drawn for each possible order quantity. From these diagrams the probability matrix were calculated. Having this matrix allowed for the calculation of the steady state probabilities or the long term probabilities. Once these were calculated the total costs were calculated using the probabilities for reordering new designed sheets and reordering sheets of the same design. These were then plotted to find the EOQ. Solution procedure The Markov chain model was the same model used throughout the case study for every order quantity. Each higher order quantity of a 1000 had one more state added but nothing else changed. For all models state 1 was the state where the step sheets were redesigned and another order of quantity n (n = 1000, 2000, 3000, 4000, 5000) was ordered. State 2 was also the same for each Markov chain. This state was the state where the inventory level was at zero and the quantity n was reordered without any changes. Every other state (3-6) was the previous years inventory level minus 1000 sheets. There were two transition probabilities for each model. Each time a state went to state 1 the probability was always 0.225. Every other transition in the diagram had the probability of 0.745. For the full state transition diagrams and steady state probabilities refer to the appendix. Figure 1. Order Amount vs. Cost Computational results The MML program is a two semester academic program held at Penn State University. This program focuses on marketing to current Penn State Juniors and Seniors. They find that these groups are where a large number of their applicants come from. The MML program created a new program brochure two years ago. The MML program estimates there is a 25.5% chance that the brochure will change after a year of use. With new brochure sets costing $1532 per 500 sheets and reusing the old brochure costing $1157 per 500 sheets the MML program wants to know the economic order quantity. After creating a Markov chain model for the situation and finding the steady state probabilities for each possible order quantity it was found that the MLL program should order 4000 sets of sheets at a time. With this order quantity the yearly cost of sheets will be $ 968.26 cents. This is cheaper than 3000 sheets costing $ 976.92 per year and 5000 sheets costing $995.70 per year. Q = 1000 sets P= .255 .745 .255 .745 steady state probabilities (π1 π2 ) = (π1 π2 ) X P EQ1: π1 = .255π1 + .255π2 EQ2: π2 = .745π1 + .745π2 π1 = .34228188π2 π1 + π2 = 1 .34228π2 + π2 = 1 π2 = .745 π1 = .255 Cost analysis for Q = 1000 re-order with redesign C(1000) = 1532 + 1X174 = 1706 re-order without redesign C(1000) = 1157 + 1X174 = 1331 C(1000) = 2054Xπ1 + 1679Xπ2 => 1706(.255) + 1331(.745) C(1000) = 1426.625 Q = 2000 sets P= .255 0 .745 .255 0 .745 .255 .745 0 steady state probabilities (π1 π2 π3) = (π1 π2 π3) X P EQ1: π1 = .255π1 + .255π2 + .255π3 EQ2: π2 = .745π3 EQ3: π3 = .745π1 + .745π2 .745π1 = .255(.745π3) + .255π3 => π1 = .59728188π3 π2 = .745π3 π1 + π2 + π3 = 1 .59728π3 + .745π3 + π3 = 1 π3 = .4269 π1 = .2251 π2 = .318 Cost analysis for Q = 2000 re-order with redesign C(2000) = 1532 + 3X174 = 2054 re-order without redesign C(2000) = 1157 + 3X174 =1679 C(2000) = 2054Xπ1 + 1679Xπ2 => 2054(.2551) + 1679(.318) C(2000) = 1057.897 Q = 3000 sets P= .255 0 .745 0 .255 0 .745 0 .255 0 0 .255 .745 0 .745 0 steady state probabilities (π1 π2 π3 π4) = (π1 π2 π3 π4) X P EQ1: π1 = .255π1 + .255π2 + .255π3 + .255π4 EQ2: π2 = .745π4 EQ3: π3 = .745π1 + .745π2 EQ4: π4 = .745π3 π3 = .745π1 + .745(.745π4) => .745π1 + .555025π4 π3 = .7733π4 + .555025π4 π3 = 1.3283π4 .745π1 = .255(.745π4) + .255( .745π1 + .555025π4) + .255π4 .565025π1 = .5865π4 => π1 = 1.038π4 π1 + π2 +π3 + π4 = 1 1.038π4 + .745π4 + 1.3283π4 + π4 = 1 π4 = .2413 π1 = .2550 π2 = .1798 π3 = .3240 Cost analysis for Q = 3000 re-order with redesign C(3000) = 1532 + 5X174 = 2402 re-order without redesign C(3000) = 1157 + 5X174 =2027 C(3000) = 2402Xπ1 + 2027Xπ2 => 2402(.2524) + 2027(.1814) C(3000) = 976.9198 Q = 4000 sets P= .255 0 .745 0 0 .255 0 .745 0 0 .255 0 0 .745 0 .255 0 0 0 .745 .255 .745 0 0 0 steady state probabilities (π1 π2 π3 π4 π5) = (π1 π2 π3 π4 π5) X P EQ1: π1 = .255π1 + .255π2 + .255π3 + .255π4 + .255π5 EQ2: π2 = .745π5 EQ3: π3 = .745π1 + .745π2 EQ4: π4 = .745π3 EQ5: π5 = .745π4 π4 = π4 π5 = .745π4 π3 = 1.342π4 π2 = .555π4 π1 = .255π1 + .255(.555π4) + .255(1.342π4) + .255π4 + .255(.745π4) = 1.24π4 π1 + π2 +π3 + π4 + π5 = 1 1.24π4 + .555π4 + 1.342π4 + π4 + .745π4 = 1 π1 = 0.2539 π2 = 0.1137 π3 = 0.2748 π4 = 0.2048 π5 = 0.1526 Cost analysis for Q = 3000 re-order with redesign C(4000) = 1532 + 7X174 = 2750 re-order without redesign C(4000) = 1157 + 7X174 =2375 C(4000) = 2750Xπ1 + 2375Xπ2 => 2750(.2539) + 2375(.1137) C(4000) = 968.26 Q = 5000 sets P= .255 0 .745 0 0 0 .255 0 .745 0 0 0 .255 0 0 .745 0 0 .255 0 0 0 .745 0 .255 0 0 0 0 .745 .255 .745 0 0 0 0 steady state probabilities (π1 π2 π3 π4 π5 π6) = (π1 π2 π3 π4 π5 π6) X P EQ1: π1= .255π1 + .255π2 + .255π3 + .255π4 + .255π5 + .255π6 EQ2: π2 = .745π6 EQ3: π3= .745π1 + .745π2 EQ4: π4= .745π3 EQ5: π5= .745π4 EQ6: π6= .745π5 π6 = 1.342 π2 π6 = 0.754π5 → 1.342 π2 = 0.754π5 → π5 = 1.801π2 π5 = 0.754π4 → 1.801 π2 = 0.754π4 → π4 = 2.417π2 π4 = 0.754π3 → 1.342 π2 = 0.754π3 → π3 = 3.244π2 π3 = 0.754π1 + 0.754π2 → 3.244 π2 = 0.754π1 + 0.754π2 → π1 = 3.35π2 1 = π1 + π2 + π3 + π4 + π5 + π6 1= 3.35π2 + π2 + 3.244π2 + 2.417π2 + 1.801π2 + 1.342π2 π1 = .2546 π2 = .076 π3 = .247 π4 = .184 π5 = .137 π6 = .102 Cost analysis for Q = 5000 re-order with redesign C(5000) = 1532 + 9X174 = 3098 re-order without redesign C(5000) = 1157 + 9X174 =2723 C(5000) = 3098Xπ1 + 2723Xπ2 => 3098(.2546) + 2723(.076) C(5000) = 995.70 Appendix Q = 1000 sets Q = 2000 sets Q = 3000 sets Q = 4000 sets Q = 5000 sets