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Transcript
1
Diffraction and Interference – Learning
Outcomes
 Demonstrate the wave nature of light.
 HL: Derive the diffraction grating formula.
 Solve problems about diffraction gratings.
 Discuss interference in thin films.
2
Diffraction Gratings
 Diffraction gratings are pieces of transparent
material with lines etched on it.
 The lines prevent light from passing through, so light
passing between the lines behaves as if it passed
through slits (i.e. it diffracts).
 Gratings are usually described as having some
number of lines per mm (e.g. 400 lines per mm).
 The distance between adjacent gaps, d is the
1
inverse of this (e.g.
mm).
400
3
To Demonstrate the Wave Nature of Light
1. Shine a laser at a diffraction grating.
2. Place a screen behind the grating and observe that an
interference pattern is produced on the screen.
3. Only waves interfere with each other, so light must be a
wave.
4
Interference Pattern
 Interference patterns are a series of bright spots
(“fringes”) caused by constructive interference.
 The central fringe (n=0) is the brightest, with fringes
getting dimmer either side as order increases (n=1, 2,
3…)
5
HL: Derive 𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃 (the set-up)
 Consider two sources
of waves next to each
other.
 Constructive
interference occurs
when the waves are
in phase.
 It also occurs when
they are exactly 1
cycle apart (or 2, 3, 4
… cycles)
6
HL: Derive 𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃 (the set-up)
 As we only care about
single directions, go back
to the ray picture.
 Rays are emitted in all
directions.
 We single out the rays
that cause constructive
interference – they are in
phase and travelling in
the same direction.
7
HL: Derive 𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃 (the derivation)
 Consider rays emerging
from a diffraction grating
at an angle 𝜃 from the
normal.
 If the path difference
between the rays is a
whole number of
wavelengths, they will
arrive in phase.
 i.e. constructive
interference occurs if the
path difference is 𝑛𝜆.
8
HL: Derive 𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃 (the derivation)
 Let the distance between
lines be 𝑑.
 By trigonometric identity,
 𝑠𝑖𝑛𝜃 =
𝑛𝜆
𝑑
 Rearranging gives
 𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃
𝑛𝜆 = 𝑑𝑠𝑖𝑛𝜃
9
Solve Problems
 e.g. Red light falls on a diffraction grating with 400 lines
per mm. The second order diffracted image is at 30o
from the central fringe. Find the wavelength of the light.
 e.g. A diffraction grating has 350 lines per mm rules on it.
Light of wavelength 520 nm falls on it. What is the highest
order fringe formed?
 e.g. A monochromatic (single-colour) light source is
shined on a diffraction grating with 100 lines per mm. A
diffraction pattern is formed on a screen 2 m from the
grating. If the distance between the fourth order fringes
is 80 cm, what is the wavelength of the light source?
10
Interference in Thin Films
 Light striking a film will reflect at both boundaries.
 If the reflected rays are a whole number of cycles apart
(i.e. if the path difference of the reflected rays is 𝑛𝜆),
constructive interference will occur.
 Due to the wavelength
dependence, different
colours undergo
interference at different
angles, creating rainbow
effects.
By Anton – CC-BY-SA-2.0
by John Flannery – CC-BY-SA-2.0
Interference in Thin Films
11