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§4 - velocity-dependent forces [HRW §6.4, Y&F §5.3, F §2.5] • velocity-dependent forces: fluid resistance and terminal velocity normal fluid resistance: F(v) = - c1v - c2v | v | where coefficients c1 and c2 depend on size, shape, surface roughness and fluid properties (Reynolds number). c1 ≈ 1.55 10-4 D, c2 ≈ 0.22 D2 For sphere in air: with D diameter in m [SI] • vertical fall through fluid: dv - mg - c1v = m dt a) linear case c2 ≈ 0 v m dv t = - mg - c v 1 integrate m mg + c1v = c ln mg + c v 1 1 o vo or mg mg v = - c + c + vo e - t/ 1 1 m where time constant = c 1 mg The first term is the limiting value known as the terminal velocity vt = c = g . 1 v = - vt (1 - e - t/) So v increases from zero at t = 0, but never exceeds the terminal velocity. The time constant is a measure of how quickly this velocity is approached. After 3 time constants (t = 3) the projectile will be at 95% of its terminal speed. b) quadratic case (c2 only) = rising: falling: m c2g vt = mg c2 vo to - t v = vt tan + tan-1 v t t t ' vo o v = - vt tanh + tanh-1 v t t falling from rest at to' = 0: v = - vt tanh NOTE: in both linear and quadratic cases we have Spherical drop falling vertically under gravity: Given: Derived drop diameter D=2r blood density falling height h gravity g 4 r3 3 volume Vo mass m Vo 4 r3 3 Determine drag coefficients: c1 ≈ 1.55 10-4 D c2 ≈ 0.22 D2 Determine terminal speed: v1 mg c1 Drag-free case: Loss of momentum: Mean force during impact: or mg c2 speed at impact Time interval: v2 v 2gh p mv m 2 g h 2r 2r t v 2gh Fmean Fmean p mv 2 t 2r 4 g h r2 3 mgh r Solid object falling vertically under gravity: Given: mass m falling height h gravity g Determine drag coefficients: (depends on shape but probably neglibile) Drag-free case: speed at impact Loss of momentum: Time interval: Mean force during impact: v 2gh p mv m 2 g h difficult to derive from theory (?) easier to measure ??? e.g. using video capture (Ralph has a HD camera at 60 fps) [Ian at CFS has one with 1000 fps] p Fmean t RNJ 2-Dec-11