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Solving equations using factorisation Example 1:x²+6x-16=0 Put the equation equal to 0 8, -2 Find two number that add to make 6 and times to make 16: Then put them into double brackets: (x+8) (x-2) Finally put both brackets equal to 0 and work out the value of x x+8=0 x= -8 X-2=0 x=2 Example 2:2x²-7x-15=0 -30 Then times the number in front of x²; 2, by the last number; -15 which equals -30. Two numbers that add to make -7 and times to make -30 are -10 and +3 Rewrite the formula as: 2x²-10x+3x-15=0 Treat the formula as two: 2x²-10x and 3x-15 2x²-10x 3x-15 Take out the biggest factor that goes into both, 2x. Take out the biggest factor that goes into both again, 3. Then we write it as 2x(x-5x) So we write it as 3(x-5) Put both equal to 0. Then put together everything outside the brackets and 2x(x-5)+3(x-5)=0 everything inside the brackets. Both brackets should be (2x+3)(x-5)=0 the same. - 2x+3=0 X=-3 - X-5=0 X=5