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RC, RLC circuit and Magnetic field RC Charge relaxation RLC Oscillation Helmholtz coils RC Circuit • The charge on the capacitor varies with time – q = Ce(1 – e-t/RC) = Q(1 – e-t/RC) t is the time constant • t = RC • The current can be found I( t ) ε e t RC R Discharging Capacitor • At t = t = RC, the charge decreases to 0.368 Qmax – In other words, in one time constant, the capacitor loses 63.2% of its initial charge • The current can be found I t dq Q t RC e dt RC • Both charge and current decay exponentially at a rate characterized by t = RC Oscillations in an LC Circuit • A capacitor is connected to an inductor in an LC circuit • Assume the capacitor is initially charged and then the switch is closed • Assume no resistance and no energy losses to radiation Time Functions of an LC Circuit • In an LC circuit, charge can be expressed as a function of time – Q = Qmax cos (ωt + φ) – This is for an ideal LC circuit • The angular frequency, ω, of the circuit depends on the inductance and the capacitance – It is the natural frequency of oscillation of the circuit ω 1 LC RLC Circuit A circuit containing a resistor, an inductor and a capacitor is called an RLC Circuit. Assume the resistor represents the total resistance of the circuit. d 2Q dQ Q L 2 R 0 dt dt C RLC Circuit Solution • When R is small: – The RLC circuit is analogous to light damping in a mechanical oscillator – Q = Qmax e-Rt/2L cos ωdt – ωd is the angular frequency of oscillation for the circuit and 1 R ωd LC 2 L 2 1 2 RLC Circuit Compared to Damped Oscillators • When R is very large, the oscillations damp out very rapidly • There is a critical value of R above which no oscillations occur R 4L / C C • If R = RC, the circuit is said to be critically damped • When R > RC, the circuit is said to be overdamped Biot-Savart Law • Biot and Savart conducted experiments on the force exerted by an electric current on a nearby magnet • They arrived at a mathematical expression that gives the magnetic field at some point in space due to a current Biot-Savart Law – Equation • The magnetic field is dB at some point P • The length element is ds • The wire is carrying a steady current of I μo I ds ˆr dB 4π r 2 B for a Circular Current Loop • The loop has a radius of R and carries a steady current of I • Find B at point P Bx 0IR 2 2 2 32 2 x R Helmholtz Coils (two N turns coils) If each coil has N turns, the field is just N times larger. Bx 0IR 2 2 2 x R 2 32 N 0IR 2 1 B Bx1 Bx2 2 2 2 x R N 0IR 2 1 B 2 2 2 x R dB 0 dx 32 3 2 R x 2 R 2 1 32 3 2 2R 2 x2 2xR d2B 0 2 dx 1 At x=R/2 B is uniform in the region midway between the coils.