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Chapter 2 Complexity Analysis Data Structures and Algorithms in Java Objectives Discuss the following topics: • Computational and Asymptotic Complexity • Big-O Notation • Properties of Big-O Notation • Ω and Θ Notations • Examples of Complexities • Finding Asymptotic Complexity: Examples • Amortized Complexity • The Best, Average, and Worst Cases • NP-Completeness Data Structures and Algorithms in Java 2 Computational and Asymptotic Complexity • Computational complexity measures the degree of difficulty of an algorithm • Indicates how much effort is needed to apply an algorithm or how costly it is • To evaluate an algorithm’s efficiency, use logical units that express a relationship such as: – The size n of a file or an array – The amount of time t required to process the data Data Structures and Algorithms in Java 3 Computational and Asymptotic Complexity (continued) • This measure of efficiency is called asymptotic complexity • It is used when disregarding certain terms of a function – To express the efficiency of an algorithm – When calculating a function is difficult or impossible and only approximations can be found f (n) = n2 + 100n + log10n + 1,000 Data Structures and Algorithms in Java 4 Computational and Asymptotic Complexity (continued) Figure 2-1 The growth rate of all terms of function f (n) = n2 + 100n + log10n + 1,000 Data Structures and Algorithms in Java 5 Big-O Notation • Introduced in 1894, the big-O notation specifies asymptotic complexity, which estimates the rate of function growth • Definition 1: f (n) is O(g(n)) if there exist positive numbers c and N such that f (n) ≤ cg(n) for all n ≥ N Figure 2-2 Different values of c and N for function f (n) = 2n2 + 3n + 1 = O(n2) calculated according to the definition of big-O Data Structures and Algorithms in Java 6 Big-O Notation (continued) Figure 2-3 Comparison of functions for different values of c and N from Figure 2-2 Data Structures and Algorithms in Java 7 Properties of Big-O Notation • Fact 1 (transitivity) If f (n) is O(g(n)) and g(n) is O(h(n)), then f(n) is O(h(n)) • Fact 2 If f (n) is O(h(n)) and g(n) is O(h(n)), then f(n) + g(n) is O(h(n)) • Fact 3 The function ank is O(nk) Data Structures and Algorithms in Java 8 Properties of Big-O Notation (continued) • Fact 4 The function nk is O(nk+j) for any positive j • Fact 5 If f(n) = cg(n), then f(n) is O(g(n)) • Fact 6 The function loga n is O(logb n) for any positive numbers a and b ≠ 1 • Fact 7 loga n is O(lg n) for any positive a ≠ 1, where lg n = log2 n Data Structures and Algorithms in Java 9 Ω and Θ Notations • Big-O notation refers to the upper bounds of functions • There is a symmetrical definition for a lower bound in the definition of big-Ω • Definition 2: The function f(n) is Ω(g(n)) if there exist positive numbers c and N such that f(n) ≥ cg(n) for all n ≥ N Data Structures and Algorithms in Java 10 Ω and Θ Notations (continued) • The difference between this definition and the definition of big-O notation is the direction of the inequality • One definition can be turned into the other by replacing “≥” with “≤” • There is an interconnection between these two notations expressed by the equivalence f (n) is Ω(g(n)) iff g(n) is O(f (n)) (prove?) Data Structures and Algorithms in Java 11 Ω and Θ Notations (continued) • Definition 3: f(n) is Θ(g(n)) if there exist positive numbers c1, c2, and N such that c1g(n) ≤ f(n) ≤ c2g(n) for all n ≥ N • When applying any of these notations (big-O,Ω, and Θ), remember they are approximations that hide some detail that in many cases may be considered important Data Structures and Algorithms in Java 12 Examples of Complexities • Algorithms can be classified by their time or space complexities • An algorithm is called constant if its execution time remains the same for any number of elements • It is called quadratic if its execution time is O(n2) Data Structures and Algorithms in Java 13 Examples of Complexities (continued) Figure 2-4 Classes of algorithms and their execution times on a computer executing 1 million operations per second (1 sec = 106 μsec = 103 msec) Data Structures and Algorithms in Java 14 Examples of Complexities (continued) Figure 2-4 Classes of algorithms and their execution times on a computer executing 1 million operations per second (1 sec = 106 μsec = 103 msec) (continued) Data Structures and Algorithms in Java 15 Examples of Complexities (continued) Figure 2-5 Typical functions applied in big-O estimates Data Structures and Algorithms in Java 16 Finding Asymptotic Complexity: Examples • Asymptotic bounds are used to estimate the efficiency of algorithms by assessing the amount of time and memory needed to accomplish the task for which the algorithms were designed for (i = sum = 0; i < n; i++) sum += a[i] • Initialize two variables • Execute two assignments – Update sum – Update i Total 2+2n assignments for the complete execution Asymptotic complexity is O(n) Data Structures and Algorithms in Java 17 Finding Asymptotic Complexity: Examples • Printing sums of all the sub-arrays that begins with position 0 for (i = 0; i < n; i++) { for (j = 1, sum = a[0]; j <= i; j++) sum += a[j]; System.out.println ("sum for subarray 0 through "+i+" is" + sum); } n 1 1+3n+ 2i =1+3n+2(1+2+….n-1) i 1 =1+3n+n(n-1)=O(n)+ O(n2)= O(n2) Data Structures and Algorithms in Java 18 Examples Continued • Printing sums of numbers in the last five cells of the sub-arrays starting in position 0 for (i = 4; i < n; i++) { for (j = i-3, sum = a[i-4]; j <= i; j++) sum += a[j]; System.out.println ("sum for subarray "+(i - 4)+" through "+i+" is"+ sum); } • n-4 times for outer loop • For each i, inner loop executes only four times 1+8.(n-4)= O(n) Data Structures and Algorithms in Java 19 Finding Asymptotic Complexity: Examples • • Finding the length of the longest sub-array with the numbers in increasing order For example [1 2 5 ] in [1 8 1 2 5 0 11 12] for (i = 0, length = 1; i < n-1; i++) { for (i1 = i2 = k = i; k < n-1 && a[k] < a[k+1]; k++, i2++); if (length < i2 - i1 + 1) length = i2 - i1 + 1; System.out.println ("the length of the longest ordered subarray is" + length); } Data Structures and Algorithms in Java 20 • If all numbers in the array are in decreasing order, the outer loop is executed n-1 times • But in each iteration, the inner loop executes just one time. The algorithm is O(n) • If the numbers are in increasing order, the outer loop is executed n- 1 times and the inner loop is executed n-1-i times for each i in {0,…, n-2}. The algorithm is O(n2) Data Structures and Algorithms in Java 21 Finding Asymptotic Complexity: Examples int binarySearch(int[] arr, int key) { int lo = 0, mid, hi = arr.length-1; while (lo <= hi) { mid = (lo + hi)/2; if (key < arr[mid]) hi = mid - 1; else if (arr[mid] < key) lo = mid + 1; else return mid; // success } return -1; // failure } • O(lg n) Data Structures and Algorithms in Java 22 The Best, Average, and Worst Cases • The worst case is when an algorithm requires a maximum number of steps • The best case is when the number of steps is the smallest • The average case falls between these extremes Cavg = Σip(inputi)steps(inputi) Data Structures and Algorithms in Java 23 • The average complexity is established by considering possible inputs to an algorithm, • determining the number of steps performed by the algorithm for each input, • adding the number of steps for all the inputs, and dividing by the number of inputs • This definition assumes that the probability of occurrence of each input is the same. It is not the case always. • The average complexity is defined as the average over the number of steps executed when processing each input weighted by the probability of occurrence of this input Data Structures and Algorithms in Java 24 Consider searching sequentially an unordered array to find a number • The best case is when the number is found in the first cell • The worst case is when the number is in the last cell or not in the array at all • The average case? Data Structures and Algorithms in Java 25 • • • • • • Assuming the probability distribution is uniform The probability equals to 1/n for each position To find a number in one try is 1/n To find a number in two tries is 1/n etc… The average steps to find a number is 1+2+…+n n+1 = n 2 Data Structures and Algorithms in Java 26 • If the probabilities differ, the average case gives a different outcome • If the probability of finding a number in the first cell is ½ , the probability in the second cell is ¼ and the probability is the same for remaining cells 1-½-¼ n-2 = 1 4(n - 2) • the average steps 1 2 3 ...n n(n 1) 6 n3 1 1 2 4 4(n 2) 8(n 2) 8 Data Structures and Algorithms in Java 27 Summation Formulas Let N > 0, let A, B, and C be constants, and let f and g be any functions. Then: N N k 1 k 1 N N N k 1 k 1 k 1 Cf (k ) C f (k ) ( f (k ) g (k )) f (k ) g (k ) S1: factor out constant S2: separate summed terms C NC N ( N 1) k 2 k 1 k2 S3: sum of constant S4: sum of k S5: sum of k squared N N k 1 N 2 2 k N 1 k 0 S6: sum of 2^k 1 N k 1 N ( N 1)( 2 N 1) 6 N k 1 N k 2 ( N 1 ) 2 1 k 1 S7: sum of k2^(k-1) Data Structures and Algorithms in Java 28 Logarithms Let b be a real number, b > 0 and b 1. Then, for any real number x > 0, the logarithm of x to base b is the power to which b must be raised to yield x. That is: log b ( x) y if and only if b y x For example: log 2 (64) 6 because 26 64 log 2 (1 / 8) 3 because 23 1 / 8 log 2 (1) 0 because 20 1 If the base is omitted, the standard convention in mathematics is that log base 10 is intended; in computer science the standard convention is that log base 2 is intended. Data Structures and Algorithms in Java 29 Logarithms Let a and b be real numbers, both positive and neither equal to 1. Let x > 0 and y > 0 be real numbers. L1: log b (1) 0 L2: log b (b) 1 L3: log b ( x) 0 for all 0 x 1 L4: log b ( x) 0 for all x 1 L5: log b (b y ) y L6: b logb ( x ) x Data Structures and Algorithms in Java L7: log b ( xy) log b ( x) log b ( y) L8: x log b log b ( x) log b ( y ) y L9: log b ( x y ) y log b ( x) L10: log a ( x) log b ( x) log a (b) 30 Limit of a Function Definition: Let f(x) be a function with domain (a, b) and let a < c < b. The limit of f(x) as x approaches c is L if, for every positive real number e, there is a positive real number d such that whenever |x-c| < d then |f(x) – L| < e. The definition being cumbersome, the following theorems on limits are useful. We assume f(x) is a function with domain as described above and that K is a constant. C1: lim K K x c C2: lim x c x c C3: lim x r c r for all r 0 xc Data Structures and Algorithms in Java 31 Limit of a Function Here assume f(x) and g(x) are functions with domain as described above and that K is a constant, and that both the following limits exist (and are finite): lim g ( x) B lim f ( x) A x c x c Then: C4: lim Kf ( x) K lim f ( x) x c C5: C6: C7: x c lim f ( x) g ( x) lim f ( x) lim g ( x) x c x c x c lim f ( x) * g ( x) lim f ( x) * lim g ( x) x c x c x c lim f ( x) / g ( x) lim f ( x) / lim g ( x) provided B 0 x c x c Data Structures and Algorithms in Java x c 32 Limit as x Approaches Infinity Definition: Let f(x) be a function with domain [0, ). The limit of f(x) as x approaches is L if, for every positive real number e, there is a positive real number N such that whenever x > N then |f(x) – L| < e. The definition being cumbersome, the following theorems on limits are useful. We assume f(x) is a function with domain [0, ) and that K is a constant. C8: lim K K x C9: 1 0 x x lim C10: 1 lim r 0 for all r 0 x x Data Structures and Algorithms in Java 33 Limit of a Rational Function Given a rational function the last two rules are sufficient if a little algebra is employed: 5 10 2 7 x 2 5 x 10 x x lim lim x 3 x 2 2 x 5 x 2 5 3 2 x x 5 10 lim 7 lim lim 2 x x x x x 2 5 lim 3 lim lim 2 x x x x x 700 3 0 0 7 3 7 Data Structures and Algorithms in Java Divide by highest power of x from the denominator. Take limits term by term. Apply theorem C3. 34 Infinite Limits In some cases, the limit may be infinite. Mathematically, this means that the limit does not exist. C11: lim x r for all r 0 C12: lim log b x C13: x lim e x x x 7 x 5 x 10 lim x x 2x 5 2 Example: lim 7x 5 10 x 5 2 x 10 lim 7 x lim 5 lim x x x x 5 lim 2 lim x x x Data Structures and Algorithms in Java 35 l'Hôpital's Rule In some cases, the reduction trick shown for rational functions does not apply: 7 x 5 log( x) 10 lim ?? x 2x 5 In such cases, l'Hôpital's Rule is often useful. If f(x) and g(x) are differentiable functions such that lim f ( x) lim g ( x) x c x c This also applies if the limit is 0. then: f ( x) f ( x) lim lim x c g ( x ) x c g ( x) Data Structures and Algorithms in Java 36 l'Hôpital's Rule Examples Applying l'Hôpital's Rule: 5 7 7 x 5 log( x) 10 7 x lim lim x x 2x 5 2 2 Another example: x 3 10 3x 2 6x 6 lim lim x lim x lim x 0 x x x e x e x e e Recall that: D e f ( x ) e f ( x ) D f ( x) Data Structures and Algorithms in Java 37 Mathematical Induction Mathematical induction is a technique for proving that a statement is true for all integers in the range from N0 to , where N0 is typically 0 or 1. First (or Weak) Principle of Mathematical Induction Let P(N) be a proposition regarding the integer N, and let S be the set of all integers k for which P(k) is true. If 1) N0 is in S, and 2) whenever N is in S then N+1 is also in S, then S contains all integers in the range [N0, ). To apply the PMI, we must first establish that a specific integer, N0, is in S (establishing the basis) and then we must establish that if a arbitrary integer, N N0, is in S then its successor, N+1, is also in S. Data Structures and Algorithms in Java 38 Induction Example Theorem: For all integers n 1, n2+n is a multiple of 2. proof: Let S be the set of all integers for which n2+n is a multiple of 2. If n = 1, then n2+n = 2, which is obviously a multiple of 2. This establishes the basis, that 1 is in S. Now suppose that some integer k 1 is an element of S. Then k2+k is a multiple of 2. We need to show that k+1 is an element of S; in other words, we must show that (k+1)2+(k+1) is a multiple of 2. Performing simple algebra: (k+1)2+(k+1) = (k2 + 2k + 1) + (k + 1) = k2 + 3k + 2 Now we know k2+k is a multiple of 2, and the expression above can be grouped to show: (k+1)2+(k+1) = (k2 + k) + (2k + 2) = (k2 + k) + 2(k + 1) The last expression is the sum of two multiples of 2, so it's also a multiple of 2. Therefore, k+1 is an element of S. Therefore, by PMI, S contains all integers [1, ). Data Structures and Algorithms in Java QED 39 Inadequacy of the First Form of Induction Theorem: Every integer greater than 3 can be written as a sum of 2's and 5's. (That is, if N > 3, then there are nonnegative integers x and y such that N = 2x + 5y.) This is not (easily) provable using the First Principle of Induction. The problem is that the way to write N+1 in terms of 2's and 5's has little to do with the way N is written in terms of 2's and 5's. For example, if we know that N = 2x + 5y we can say that N + 1 = 2x + 5y + 1 = 2x + 5(y – 1) + 5 + 1 = 2(x + 3) + 5(y – 1) but we have no reason to believe that y – 1 is nonnegative. (Suppose for example that N is 9.) Data Structures and Algorithms in Java 40 "Strong" Form of Induction There is a second statement of induction, sometimes called the "strong" form, that is adequate to prove the result on the preceding slide: Second (or Strong) Principle of Mathematical Induction Let P(N) be a proposition regarding the integer N, and let S be the set of all integers k for which P(k) is true. If 1) N0 is in S, and 2) whenever N0 through N are in S then N+1 is also in S, then S contains all integers in the range [N0, ). Interestingly, the "strong" form of induction is logically equivalent to the "weak" form stated earlier; so in principle, anything that can be proved using the "strong" form can also be proved using the "weak" form. Data Structures and Algorithms in Java 41 Using the Second Form of Induction Theorem: Every integer greater than 3 can be written as a sum of 2's and 5's. proof: Let S be the set of all integers n > 3 for which n = 2x + 5y for some nonnegative integers x and y. If n = 4, then n = 2*2 + 5*0. If n = 5, then n = 2*0 + 5*1. This establishes the basis, that 4 and 5 are in S. Now suppose that all integers from 4 through k are elements of S, where k 5. We need to show that k+1 is an element of S; in other words, we must show that k+1 = 2r + 5s for some nonnegative integers r and s. Now k+1 6, so k-1 4. Therefore by our assumption, k-1 = 2x + 5y for some nonnegative integers x and y. Then, simple algebra yields that: k+1 = k-1 + 2 = 2x + 5y + 2 = 2(x+1) + 5y, whence k+1 is an element of S. Therefore, by the Second PMI, S contains all integers [4, ). QED Data Structures and Algorithms in Java 42 Amortized Complexity • Amortized analysis: – Analyzes sequences of operations – Can be used to find the average complexity of a worst case sequence of operations • By analyzing sequences of operations rather than isolated operations, amortized analysis takes into account interdependence between operations and their results Data Structures and Algorithms in Java 43 Amortized Complexity (continued) Worst case: C(op1, op2, op3, . . .) = Cworst(op1) + Cworst(op2) + Cworst(op3) + . . . Average case: C(op1, op2, op3, . . .) = Cavg(op1) + Cavg(op2) + Cavg(op3) + . . . Amortized: C(op1, op2, op3, . . .) = C(op1) + C(op2) + C(op3) + . . . Where C can be worst, average, or best case complexity Data Structures and Algorithms in Java 44 Amortized Complexity (continued) Figure 2-6 Estimating the amortized cost Data Structures and Algorithms in Java 45 NP-Completeness • A deterministic algorithm is a uniquely defined (determined) sequence of steps for a particular input – There is only one way to determine the next step that the algorithm can make • A nondeterministic algorithm is an algorithm that can use a special operation that makes a guess when a decision is to be made Data Structures and Algorithms in Java 46 NP-Completeness (continued) • A nondeterministic algorithm is considered polynomial: its running time in the worst case is O(nk) for some k • Problems that can be solved with such algorithms are called tractable and the algorithms are considered efficient • A problem is called NP-complete if it is NP (it can be solved efficiently by a nondeterministic polynomial algorithm) and every NP problem can be polynomially reduced to this problem Data Structures and Algorithms in Java 47 NP-Completeness (continued) • The satisfiability problem concerns Boolean expressions in conjunctive normal form (CNF) Data Structures and Algorithms in Java 48 Summary • Computational complexity measures the degree of difficulty of an algorithm. • This measure of efficiency is called asymptotic complexity. • To evaluate an algorithm’s efficiency, use logical units that express a relationship. • This measure of efficiency is called asymptotic complexity. Data Structures and Algorithms in Java 49 Summary (continued) • Introduced in 1894, the big-O notation specifies asymptotic complexity, which estimates the rate of function growth. • An algorithm is called constant if its execution time remains the same for any number of elements. • It is called quadratic if its execution time is O(n2). • Amortized analysis analyzes sequences of operations. Data Structures and Algorithms in Java 50 Summary (continued) • A deterministic algorithm is a uniquely defined (determined) sequence of steps for a particular input. • A nondeterministic algorithm is an algorithm that can use a special operation that makes a guess when a decision is to be made. • A nondeterministic algorithm is considered polynomial. Data Structures and Algorithms in Java 51