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Transcript
Whites, EE 320
Lecture 37
Page 1 of 10
Lecture 37: CMOS Digital Logic Inverter.
The basic circuit element for digital circuit design is the logic
inverter. This element is used to build logic gates and more
complicated digital circuits.
The basic CMOS logic inverter is shown in Fig. 14.22. We’ll
assume the body and source terminals are connected together, so
there’s no body effect to consider. We’ll also assume that the
MOSFETs are matched transistors.
(Fig. 14.22)
The operation of this circuit can be summarized as:
 When vI is “low,” QN is “off,” QP is “on”  vO is “high”
 When vI is “high,” QN is “on,” QP is “off”  vO is “low”
Conceptually, this CMOS circuit is intended to function as
“complementary switches” shown in Fig. 14.18(a):
© 2016 Keith W. Whites
Whites, EE 320
Lecture 37
Page 2 of 10
(Fig. 14.18a)
The directions of the arrows indicate the complementary nature
of the two switches: when one is closed the other is open, and
vice versa.
Graphical Analysis of the CMOS Logic Inverter
A more complete analysis of this CMOS logic inverter can be
performed graphically, as shown in Figs. 14.23 and 14.24. Here,
QP is treated as an active load for QN, though the converse
would produce identical results. We’ll consider the two
extremes of the input: vI  0 (“low”) and vI  VDD (“high”).
With QN considered the driving transistor and QP the active load,
then for a graphical solution we’ll be plotting characteristic and
load curves in the iDN-vDSN plane.
For this digital logic inverter circuit in Fig. 14.22, we see that
iDP  iDN .
Whites, EE 320
Lecture 37
Page 3 of 10
The vDS values are different for the two transistors, of course. By
KVL,
(1)
VDD  vSDP  vDSN
How we interpret this equation can give us the answers on how
to plot the QP characteristic curve in the iDN-vDSN plane:
 The minus sign in (1) tells us to flip the QP characteristic
curve about the vertical axis ( iDN  iDP ).
 The VDD term tells us to shift this flipped curve VDD units to
the right.
(This is the same process we used for the graphical solution of
the CMOS common source amplifier discussed in Lecture 33.)
Whites, EE 320
Lecture 37
Graphical solution when vI is “high”:
Page 4 of 10
Whites, EE 320
Lecture 37
Graphical solution when vI is “low”:
Page 5 of 10
Whites, EE 320
Lecture 37
Page 6 of 10
Summary of the CMOS Digital Logic Inverter
1. The output voltage levels are ~10 mV and ~VDD-10mV, thus
the output signal swing is nearly the maximum possible.
(Gives rise to the so-called noise margins.)
2. The static power dissipation is nearly zero (a fraction of a
W) in both states. The dynamic power dissipation is not zero
as the gates are changing states.
3. Low output resistance in either state: low resistance to ground
in the “low” output state, and low resistance to VDD in the
“high” state.
4. Input resistance of the inverter is very large (ideally infinite).
The inverter can drive a very large number of similar inverters
with little loss in signal level.
5. The gate input capacitance is not negligible, so it will take
time to “charge” up. Low output resistance helps to keep the
time constant   Rout Cin small when driving similar inverters.
Characteristic Curve for the CMOS Logic Inverter
Rather than using a graphical solution, it is fairly straightforward
to numerically construct the characteristic curve vO versus vI.
Whites, EE 320
Lecture 37
Page 7 of 10
To obtain an equation to plot for the inverter characteristic
curve, we will use the equations for the MOSFET current in the
triode and saturation regions of operation.
The iD-vDS characteristic curve for QN is given by



1
W  
iDN  kn    vI  Vtn  vO  vO2 


2
 L  n  v
2
vDS
 vDS
 GS

iDN

1 W  


 kn   vI  Vtn 

2  L  n  v
 GS

vO  vI  Vtn
 
vDS
(14.28),(2)
vGS
2
vO  vI  Vtn
 
vDS
(14.29),(3)
vGS
while the iD-vDS characteristic curve for QP is given by
iDP

W  

 k p   VDD  vI  Vtp


 L  p  
 vGS
iDP
1 W  
 k p    VDD  vI  Vtp


2  L p  
 vGS



 VDD  vO   1  VDD  vO 


  2  
vSD

 vSD 




2

 v v V
I
tp
 O

(14.30),(4)
2
vO  vI  Vtp
(14.31),(5)
For the digital logic inverter circuit, these two currents must be
equal:
iDN  iDP
(6)
To construct the complete characteristic curve for this logic
inverter, we solve (6) for vO using (2) through (5) as vI varies
from 0 to VDD.
In the case of symmetrical MOSFETs in which Vtn  Vtp and
kn W L n  k p W L  p , the voltage transfer characteristic
curve will also be symmetrical, as shown below in Fig. 14.25.
Whites, EE 320
Lecture 37
Page 8 of 10
14.24
(14.37)
(14.38)
Noise Margins
We can observe from this characteristic curve that there is a
range of input values (from 0 to VIL) that produce a high output
Whites, EE 320
Lecture 37
Page 9 of 10
voltage, and a range of input values (from VIH to VDD) that
produce a low output voltage. This is one advantage that digital
circuits have over analog ones.
These ranges of input voltages are called noise margins. In
particular, the noise margin for high input NMH is defined as:
(14.37),(7)
NM H  VOH  VIH
and the noise margin for low input NML is defined as:
NM L  VIL  VOL
(14.38),(8)
Referring to Fig. 14.25, the voltages VIH and VIL are defined
where the slope of the characteristic curve is -1. Solving (6) at
these two points, it’s shown in the text that
1
VIH   5VDD  2Vt 
(14.35),(9)
8
1
VIL   3VDD  2Vt 
(14.36),(10)
and
8
Using (9) and (10) in (7) and (8) we can determine expressions
for the two noise margins to be
1
NM H   3VDD  2Vt 
(14.37),(11)
8
1
NM L  NM H   3VDD  2Vt 
and
(14.38),(12)
8
These two noise margins are equal because we assumed the two
MOSFETs in the inverter circuit to be symmetrical.
Whites, EE 320
Lecture 37
[Add material on propagation delay? Section 14.4]
Page 10 of 10