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Transcript
CIRCULAR MOTION Chapter 5 – Section 5.2 to 5.5 5-2 Uniform Circular Motion—Kinematics Uniform circular motion: motion in a circle of constant radius at constant speed Instantaneous velocity is always tangent to the circle. SPEED/VELOCITY IN A CIRCLE Consider an object moving in a circle around a specific origin. The DISTANCE the object covers in ONE REVOLUTION is called the CIRCUMFERENCE. The TIME that it takes to cover this distance is called the PERIOD. scircle d 2r T T Speed is the MAGNITUDE of the velocity. And while the speed may be constant, the VELOCITY is NOT. Since velocity is a vector with BOTH magnitude AND direction, we see that the direction o the velocity is ALWAYS changing. We call this velocity, TANGENTIAL velocity as its direction is draw TANGENT to the circle. DERIVATION OF CENTRIPETAL ACCELERATION Initially, the object is at a position given by vector ri and has velocity vi. The final position and velocity vectors are rf and vf These are similar triangles DERIVATION- CONTINUED Initial velocity and position vectors vi and ri are perpendicular, as are the final vectors vf and rf. This means the angle θ between vi and vf is the same as the angle between ri and rf. Since we have two isosceles triangles, and the angle between the equal sides is identical, the two triangles must be similar. STEP BY STEP DERIVATION DRAWING THE DIRECTIONS CORRECTLY So for an object traveling in a counter-clockwise path. The velocity would be drawn TANGENT to the circle and the acceleration would be drawn TOWARDS the CENTER. To find the MAGNITUDES of each we have: 2r vc T 2 v ac r 5-2 Uniform Circular Motion—Kinematics Looking at the change in velocity in the limit that the time interval becomes infinitesimally small, we see that . 5-2 Uniform Circular Motion—Kinematics This acceleration is called the centripetal, or radial, acceleration, and it points toward the center of the circle. 5-2 Uniform Circular Motion—Kinematics Example 5-8: Acceleration of a revolving ball. A 150-g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.600 m. The ball makes 2.00 revolutions in a second. What is its centripetal acceleration? 5-2 Uniform Circular Motion—Kinematics Example 5-9: Moon’s centripetal acceleration. The Moon’s nearly circular orbit about the Earth has a radius of about 384,000 km and a period T of 27.3 days. Determine the acceleration of the Moon toward the Earth. 5-2 Uniform Circular Motion—Kinematics A centrifuge works by spinning very fast. This means there must be a very large centripetal force. The object at A would go in a straight line but for this force; as it is, it winds up at B. 5-2 Uniform Circular Motion—Kinematics Example 5-10: Ultracentrifuge. The rotor of an ultracentrifuge rotates at 50,000 rpm (revolutions per minute). A particle at the top of a test tube is 6.00 cm from the rotation axis. Calculate its centripetal acceleration, in “g’s.” CIRCULAR MOTION AND N.S.L 2 Recall that according to Newton’s Second Law, the acceleration is directly proportional to the Force. If this is true: v FNET ma ac r 2 mv FNET Fc r Fc Centripetal Force Since the acceleration and the force are directly related, the force must ALSO point towards the center. This is called CENTRIPETAL FORCE. NOTE: The centripetal force is a NET FORCE. It could be represented by one or more forces. So NEVER draw it in an F.B.D. 5-3 Dynamics of Uniform Circular Motion For an object to be in uniform circular motion, there must be a net force acting on it. We already know the acceleration, so can immediately write the force: 5-3 Dynamics of Uniform Circular Motion We can see that the force must be inward by thinking about a ball on a string. Strings only pull; they never push. EXAMPLES 2r vc T The blade of a windshield wiper moves through an angle of 90 degrees in 0.28 seconds. The tip of the blade moves on the arc of a circle that has a radius of 0.76m. What is the magnitude of the centripetal acceleration of the tip of the blade? 2 (.76) vc 4.26 m / s (.28 * 4) v 2 (4.26) 2 ac 23.92 m / s 2 r 0.76 EXAMPLES Top view What is the minimum coefficient of static friction necessary to allow a penny to rotate along a 33 1/3 rpm record (diameter= 0.300 m), when the penny is placed at the outer edge of the record? F f Fc FN mg Side view mv r mv 2 mg r v2 rg FN Ff 2 rev 1 min 33.3 * 0.555 rev sec min 60 sec 1sec 1.80 sec T rev 0.555 rev 2r 2 (0.15) vc 0.524 m / s T 1.80 v2 (0.524) 2 0.187 rg (0.15)(9.8) EXAMPLES The maximum tension that a 0.50 m string can tolerate is 14 N. A 0.25-kg ball attached to this string is being whirled in a vertical circle. What is the maximum speed the ball can have (a) the top of the circle, (b)at the bottom of the circle? mv 2 FNET Fc mac r mv 2 T mg r (T mg ) mv 2 r r (T mg ) 0.5(14 (0.25)(9.8)) v m 0.25 v 5.74 m / s T mg EXAMPLES mv 2 FNET Fc mac r mv 2 T mg r (T mg ) mv 2 r r (T mg ) 0.5(14 (0.25)(9.8)) v m 0.25 v 4.81 m / s At the bottom? T mg 5-3 Dynamics of Uniform Circular Motion Example 5-12: Revolving ball (vertical circle). A 0.150-kg ball on the end of a 1.10-m-long cord (negligible mass) is swung in a vertical circle. (a) Determine the minimum speed the ball must have at the top of its arc so that the ball continues moving in a circle. (b) Calculate the tension in the cord at the bottom of the arc, assuming the ball is moving at twice the speed of part (a). 5-3 Dynamics of Uniform Circular Motion Example 5-13: Conical pendulum. A small ball of mass m, suspended by a cord of length l, revolves in a circle of radius r = l sin θ, where θ is the angle the string makes with the vertical. (a) In what direction is the acceleration of the ball, and what causes the acceleration? (b) Calculate the speed and period (time required for one revolution) of the ball in terms of l, θ, g, and m. 5-3 Dynamics of Uniform Circular Motion Example 5-11: Force on revolving ball (horizontal). Estimate the force a person must exert on a string attached to a 0.150-kg ball to make the ball revolve in a horizontal circle of radius 0.600 m. The ball makes 2.00 revolutions per second. Ignore the string’s mass. 5-5 Nonuniform Circular Motion This concept can be used for an object moving along any curved path, as any small segment of the path will be approximately circular. 5-5 Nonuniform Circular Motion If an object is moving in a circular path but at varying speeds, it must have a tangential component to its acceleration as well as the radial one. UNBANKED & BANKED CURVES Unbanked Curves When a car goes around a curve, there must be a net force toward the center of the circle of which the curve is an arc. If the road is flat, that force is supplied by friction. 5-4 Highway Curves: Banked and Unbanked If the frictional force is insufficient, the car will tend to move more nearly in a straight line, as the skid marks show. 5-4 Highway Curves: Banked and Unbanked As long as the tires do not slip, the friction is static. If the tires do start to slip, the friction is kinetic, which is bad in two ways: 1. The kinetic frictional force is smaller than the static. 2. The static frictional force can point toward the center of the circle, but the kinetic frictional force opposes the direction of motion, making it very difficult to regain control of the car and continue around the curve. Unbanked Curve Example A 1000-kg car rounds a curve on a flat road of radius 50 m at a speed of 15 m/s (54 km/h). Will the car follow the curve, or will it skid? Assume: (a) the pavement is dry and the coefficient of static friction is μs = 0.60; (b) (b) the pavement is icy and μs = 0.25. BANKED CURVES Curves that are tilted at an angle instead of being flat. Why? Allows a car to go around the curve without needing friction to make the turn Normal force provides the necessary centripetal force to complete the turn 5-4 Highway Curves: Banked and Unbanked Banking the curve can help keep cars from skidding. In fact, for every banked curve, there is one speed at which the entire centripetal force is supplied by the horizontal component of the normal force, and no friction is required. This occurs when: BANKED TURNS: FBD oUnlike inclines, keep the axis straight up and down NOT parallel to the surface. oFor ideal banking, FNX serves as the only centripetal force BANKED CURVES: N2L Fc mac FNX mv 2 r mv 2 FN sin r mg mv 2 sin cos r mv 2 mg tan r F y may FNY mg 0 FN cos mg FN mg cos v tan gr 1 2 5-4 Highway Curves: Banked and Unbanked Example 5-15: Banking angle. (a) For a car traveling with speed v around a curve of radius r, determine a formula for the angle at which a road should be banked so that no friction is required. (b) What is this angle for an expressway off-ramp curve of radius 50 m at a design speed of 50 km/h? BANKED CURVES WITH FRICTION A banked curve allows a car to complete the turn at a given speed without the need of friction If a car goes above the ideal speed of a banked curve, friction needs to act in order to allow the car to safely complete the turn. BANKED CURVES W/ FRICTION FBD FfX Friction allows for a range of speeds. Ffy BANKED CURVES W/ FRICTION N2L F y may FNY F fy mg may FfX FN cos F f sin mg FN cos u s FN sin mg mg FN cos s sin Ffy Notice that friction actually increases the normal force the car experiences… BANKED CURVES W/ FRICTION N2L F c FNX mac mv 2 F fx r FfX mv2 FN sin us FN cos r mv2 FN sin s cos r Ffy v sin s cos gr cos s sin v tan s gr 1 s tan sin s cos v 2 g cos s sin r BANKED CURVE: IDEAL VS. MAX SPEED Ideal Banking for 45 mph (~20m/s) and radius of 100 m. 2 20 1 22.2 tan (9.8)(100) With friction between rubber tires and cement road (us=1.00), the max speed becomes 26.6 m/s or about 60 mph. v tan 22.2 1.0 (9.8)(100) 26.6m / s 1 1.0 tan 22.2 5-3 Dynamics of Uniform Circular Motion There is no centrifugal force pointing outward; what happens is that the natural tendency of the object to move in a straight line must be overcome. If the centripetal force vanishes, the object flies off at a tangent to the circle. FICTITIOUS FORCES A perception of a force caused by the acceleration of a reference frame. Looking at a washing machine, it appears there is a centrifugal (center-fleeing) force that causes the clothes to be pressed against the wall of the washing machine. FICTITIOUS FORCES CONT. There is no force pushing outward The normal force from the dryer is pushing them inward. the clothes (no source). walls of the That normal force causes the clothes to accelerate in a circle as opposed to flying off in a straight line. ARTIFICIAL GRAVITY When a spacecraft is far away from Earth or any other body, the force of gravity is near zero. No gravity- astronauts and objects float Rotating the spacecraft creates this artificial gravity with effects similar to true gravity people in rotating spacecraft believe they are indeed experiencing true gravitational force ARTIFICIAL GRAVITY In order to feel like spacecraft has gravity, it must experience a centripetal acceleration of 10 m/s2. 2r v T 2 v ac g 9.8 m s 2 r 2 gT r 2 4