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Chapter 3 Quiz 1 – REVIEW NON-CALCULATOR PORTION For the quiz, you should be able to: Pre-Calculus 1. Write the equation for each graph B. A. 2. Write the equation for a given table y X -2 -1 0 1 2 Y 108 36 12 4 4/3 x 1 y 12 or y 12(3) x 3 x a. y = 3x b. y = 4-x or (¼) x 3. Identify whether a function is exponential. If it is, be able to state the initial value and base, and if it is growth or decay. If it is not exponential, be able to state why it isn’t. a. 7-3x b. 3e2x c. 6(0.23x) d. 7x – 5 exponential exponential exponential not exponential initial value = 1 initial value = 3 initial value = 6 exponent is constant or base is variable base = 7 base = e base = 0.2 decay growth decay 4. Know the properties of logs a. log10 = 1 b. eln22= 22 2 11 c. log8 11 64 = d. log1 = 0 5. Be able to describe how to transform the graph of an exponential function and sketch the graph. f(x) = 2x g(x) = 3(2-2x) – 1 y Vertical stretch 3 Horizontal shrink 1/2 Reflect over y-axis Down 1 Start points (0,1) and (1,2) Key points become (- ½ , 5) and (0,2) Horizontal asymptote at y= -1 x CALCULATOR PORTION 6. Be able to solve equations. a. 10x = 23,587 log1023587 = x x = 4.373 b. lnx = 5.29 e5.29 = x x = 198.343 7. Be able to solve problems with logistic models. Four students start a rumor where the number of students who have heard the rumor by the end of t days is modeled by: 1200 S (t ) 1 39e0.9t a. How many students have heard the rumor by the end of day 0? S(0) = 12000/(1+39) = 1200/40 = 30 students b. How long does it take for 1000 students to hear the rumor? Put equation into y1 and 1000 into y2, find point of intersection. Answer: 5.859 days c. What is the maximum number of students who can hear the rumor? 1200 (just the numerator, remember it represents the limit of growth) 8. Be able to solve word problems with log models. The time t, in minutes, for a small plane to climb to an altitude of h feet is given by 18, 000 t 50 log 18, 000 h Find the time for the plane to climb to an altitude of 4,000 feet. Substitute 4000 in for h and calculate t = 5.457 minutes