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Algebra 1 β Unit 2 REVIEW 1). What is the solution to the equation 8x + 5(4x β 6) β 8 = 8x β 14? MGSE9.A.REI.3 8π₯ + 20π₯ β 30 β 8 = 8π₯ β 14 Distribute the 5 28π₯ β 38 = 8π₯ β 14 Combine like terms on the same side of the equals 28π₯ = 8π₯ + 24 Add 38 to both sides 20π₯ = 24 Subtract 8x from both sides π = π. π Divide each side by 20 2). What is the solution to the inequality 4x β 16 < 2x + 4? 7 MGSE9.A.REI.3 4π₯ 7 < 2π₯ + 20 Add 16 to each side 4π₯ < 14π₯ + 140 Multiply 7 on each side ο 7(2x+20) β10π₯ < 140 Subtract 14x from each side π > βπππ Divide each side by -10. Flip the sign because you divided by a negative. 3). It costs $5 to have a tote bag monogrammed with up to 16 letters and $.50 for each additional letter. A club has a budget of $9.00 maximum per tote bag. How many additional letters can the club at most put on the tote without exceeding their budget? MGSE9.A.REI.3 5 + .50π = 9 The first 16 letters cost $5 and each additional letter costs $.50 . 50π = 4 Subtract 5 from each side to solve for l π=π Divide each side by .50 to find out how many additional letters you can have. 4). What is the solution to the system? 3x + 6y = 45 2x + y = 9 MGSE9.A.REI.6 3π₯ + 6π¦ = 45 Multiply the second equation by -6 if you are solving β12π₯ β 6π¦ = β54 by elimination β9π₯ = β9 Add the two equations together π₯ = 1 Divide each side by -9 2(1) + π¦ = 9 Plug 1 in for x in one of the equations 2 + π¦ = 9 Subtract 2 from each side π =7 (1,7) 3π₯ + 6π¦ = 45 If solving by substitution subtract 2x from each side in the second equation π¦ = β2π₯ + 9 3π₯ + 6(β2π₯ + 9) = 45 plug the second equation in for y in the first equation 3π₯ β 12π₯ + 54 = 45 Distribute the 6 β9π₯ + 54 = 45 Combine like terms on the same side of the equals β9π₯ = β9 Subtract 54 from each side π₯ = 1 Divide each side by -9 π¦ = β2(1) + 9 Plug x=1 into the new equation you created π = π (1,7) 5). What is the solution to the system? x + 4y = 3 -5x β 20y = -15 MGSE9.A.REI.6 5π₯ + 20π¦ = 15 Multiply the first equation by 5 if you are solving β5π₯ β 20π¦ = β15 by elimination 0 = 0 Add the two equations together INFINITE SOLUTIONS π = β4π¦ + 3 If solving by substitution subtract 4y from each side in the first equation β5π₯ β 20π¦ = β15 β5(β4π¦ + 3) β 20π¦ = β15 plug the first equation in for x in the second equation 20π¦ β 15 β 20π¦ = β15 Distribute the -5 β15 = β15 Combine like terms on the same side of the equals INFINITE SOLUTIONS 6). What is the solution to the system? -3x + 3y = 4 MGSE9.A.REI.6 -5x + 5y = 15 15π₯ β 15π¦ = β20 Multiply the first equation by 5 if you are solving β15π₯ + 15π¦ = β45 by elimination 0 = β65 Add the two equations together NO SOLUTION β3π₯ + 3π¦ = 4 If solving by substitution subtract 5x from each side in the second equation, then divide π¦ = π₯+3 everything by 5 in the second equation β3π₯ + 3(π₯ + 3) = 4 plug the second equation in for y in the first equation β3π₯ + 3π₯ + 9 = 4 Distribute the 3 9 = 4 Combine like terms on the same side of the equals NO SOLUTION 7). The sum of two numbers is 76. Nine less than four times the smaller is the same as the larger. Find the two numbers. MGSE9.A.REI.6 π₯ + π¦ = 76 You can substitute because the second equations is already in y= 4π₯ β 9 = π¦ π₯ + 4π₯ β 9 = 76 5π₯ β 9 = 76 5π₯ = 85 π = ππ 17 + π¦ = 76 π = ππ 8). In five years, twice Jennyβs age will be three more than Willowβs age. The sum of their ages now is 26. How old is Willow? MGSE9.A.REI.6 2(π + 5) + 3 = π€ + 5 Set up the two equations first π + π€ = 26 2π + 10 + 3 = π€ + 5 Distribute the 2 π + π€ = 26 2π + 8 = π€ Combine like terms π + π€ = 26 π + 2π + 8 = 26 Plug the first equation in the second equation for w 3π = 18 Combine like terms π = π Divide each side by 3 π = ππ 26 minus 6 is 20 9). Which graph represents the solution to the system? 2x + y = 6 π¦ = β2π₯ + 6 Make both equations in the -x + 3y = 1 1 π¦ = 3π₯ + 1 form y=mx+b D MGSE9.A.REI.6 a. b. c. d. 10). Describe the graph that represents the solutions of the inequality y < 8x - 15. MGSE9.A.REI.6 C β€ and β₯ mean all points that lie ____ AND on a. All of the points that lie above c. All of the points that lie below the line y = 8x - 15. the line y = 8x - 15. b. All of the points that lie on and d. All of the points that lie on and above the line y = 8x - 15. below the line y = 8x - 15. 11). Which graph represents the solution to the inequality 4x β y < 5 ? MGSE9.A.REI.12 βπ¦ < β4π₯ + 5 π¦ > 4π₯ β 5 C a. b. c. d. 12). Jenny manages two departments at a printer plant: one department assembles the printers and one packages them for shipment. Jenny knows that it takes 0.25 hours to assemble each inkjet printer and 2 hours to assemble each laser printer. She has allotted no more than 120 hours for assembly. She also knows that it takes 0.25 hours to pack each inkjet printer and 0.5 hours to pack each laser printer. She has allotted no more than 40 hours for packing. Write a system of inequalities represents the time Jenny has for her staff to assemble and package the printers. MGSE9.A.REI.12 . 25π + 2π β€ 120 . 25π + .50π β€ 40 13). MGSE9β12.F.IF.2 hn Find f(5).= -1 At x=5 what does y equal? Algebra 1 β Unit 2 REVIEW ANSWERS Name: ______________________________ Date: _____________ Period: ______ For each problem, you MUST SHOW EACH STEP in getting your solution. Students will be awarded 0 points if the question is not answered or if the student's response does not relate to the question being asked, 1 point for organized relevant information resulting in an incorrect final answer or the correct answer only and 2 points for the correct answer with supporting documentation. 1). Graph the solution to the following system of linear inequalities. MGSE9.A.REI.12 3x β 4y β€ 16 -3x -3x -4y β€ -3x + 16 -4 -4 -4 βπ yβ₯ π πβπ 4x + 3y < 9 -4x -4x 3y < -4x + 9 3 3 3 βπ y< π π+π 2). A math teacher wants to buy 20 new scientific calculators for the classroom. Acme and Zenith make two different types of calculators. Acme calculators cost $15 each. Zenith calculators cost $12 each. The math teacher has $276 to spend. Write and solve a system of equations to find how many of each calculator she can buy. MGSE9.A.REI.6 π΄ + π = 20 A= -Z + 20 -15Z+300+12Z=276 -3Z = -24 15π΄ + 12π = 276 15(-Z + 20) + 12Z = 276 -3Z + 300 = 276 Z = 8 A= 12 3). You have 18 coins that are all quarters and dimes. If you have a total of $2.55, how many of each do you have? MGSE9.A.REI.6 π + π = 18 . 25π + .10π = 2.55 d= -q +18 .25q + .10(-q+18)=2.55 .25q - .10q + 1.80=2.55 .15q=.75 .15q + 1.80=2.55 q=5 d=13 Use the following functions to answer 4-7. g(x)= ππ + π f(x)= 2x + 9 h(x)= -3x + 1 4. g(7) π(7) = 72 +7 π(7) = 56 5. h(-15) 6. Find x if j(x) = -4 12 β(β15) = β3(β15) + 1 β4 = π₯ β(β15) = 46 π₯ = β3 MGSE9β12.F.IF.2 j(x)= ππ π 7. Find x if f(x)= 51 51 = 2π₯ + 9 π₯ = 21