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10.4 Angular Overlap - an approach to bonding that is useful for making estimates of E of orbitals in coordination complexes - estimate the strength of interaction b/w ligand orbitals & metal d orbitals based on the overlap - Why this term ?? : amount of overlap depends strongly on the angular arrangement of the M orbitals & the angles of ligand 10.4.1 Sigma Sigma--Donor Interactions - Strongest interaction: b/w M-dz2 & ligand-p reference interaction for other σ-interaction bonding orbital: larger ligand component decreased MO E by eσ antibonding orbital: larger M component increased MO E by eσ Fig.10.21 Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.1 Sigma –Donor Interactions - Table 10.10: changes in orbital E due to other interactions b/w M d orbitals & ligand orbitals need to justify the # qualitatively Inorganic Chemistry 2 2011 Fall T.-S.You 1 10.4.1 Sigma –Donor Interactions - Example on p.390) [M(NH3)6]n+ , octahedral only σ-interaction (NH3 → no π orbital) donor orbital on NH3 → pz → px, py: used in bonding w/ H - calculation of the orbital E in a complex,, 1) d orbital: ∑ of # for the appropriate ligands in the vertical column 2) ligand orbital: ∑ of # for all d orbitals in the horizontal row Fig.5.31 Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.1 Sigma –Donor Interactions - Metal d orbitals - 1) dz2: strongest w/ 1 & 6 – raise E by eσ : weak w/ 2, 3, 4, 5 – raise E by 1/4 eσ increase by total 3 eσ 2) dx2-y2: position 1, 6 – no interaction position 2, 3, 4, 5 – raise E by 3/4 eσ increased by total 3 eσ 3) dxy, dxz, dyz: no interaction w/ ligands remains unchanged - Ligand orbitals - 1) ligand 1, 6 w/ dz2: lowered by eσ w/ other d: no interaction 2) ligands 2, 3, 4, 5 w/ dz2: lowered by 1/4 eσ w/ dx2-y2: lowered by 3/4 eσ ∴ Each ligand orbital is lowered by eσ !! Inorganic Chemistry 2 2011 Fall T.-S.You 2 10.4.1 Sigma –Donor Interactions - Fig.10.22: resulting E pattern decribe how the M complex is stabilized (X 2) d orbitals of M: increase E (X 3) d orbitals of M: remains unchanged (X 6) ligand orbitals: lower E * net stabilization: 12 eσ for the bonding pair Fig.10.22 Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.2 Pi Pi--Acceptor Interactions - CO, CN-, PR3 (phosphine): π acceptors w/ empty orbitals - Strongest π interaction: b/w dxz of M & π* of ligand - Fig.10.23: - eπ < eσ → ∵ π overlap is weaker than σ-overlap Inorganic Chemistry 2 2011 Fall T.-S.You 3 10.4.2 Pi Pi--Acceptor Interactions - Table 10.11: Pi interaction 1) M d orbital dz2, dx2-y2: no π interaction at all (1-6) dxy, dxy, dyz: stabilized by 4eπ 2) ligand orbitals → raise E - d e- → occupy the bonding MO w/ - 4eπ - Fig. 10.24: σ-donor & π-acceptor ligands ∆o = 3eσ + 4eπ Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.2 Pi Pi--Acceptor Interactions - Example on p. 394) [M(CN)6]n- M’s dxy, dxz, dyz lowered by 4eπ X 6 ligands → increased by 2eπ ∆o (t2g - eg split) = 3eσ + 4eπ Inorganic Chemistry 2 2011 Fall T.-S.You 4 10.4.3 Pi Pi--Donor Interactions - Interaction b/w occupied ligand p, d or π-orbitals & metal d-orbitals - Similar to π-acceptor π acceptor case except the reversed E b/w M & ligands M d orbitals: E ↑ ligand π-orbitals: E ↓ - Fig.10.26: - Fig.10.25: Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.3 Pi Pi--Donor Interactions - Example on p.395) [MX6]nhalide ion: σ-interaction → donate e- via py : π-interaction → donate e- via px, pz both σ- & π-donor dz2 & dx2-y2 orbitals: no π-interaction no effect on the E of these d orbitals dxy, dxz and dyz orbitals: π-interaction w/ four ligands dxy → w/ 2, 3, 4, 5 → by total 4eπ ↑ Inorganic Chemistry 2 2011 Fall T.-S.You 5 10.4.4 Types of Ligands and the Spectrochemical Series - Ligands can be classified by their donor & acceptor capabilities - NH3: σ-donors only, no π-interactions simple bonding (Fig.10.4) - ∆ (ligand field split): depends on the relative E of M & ligand the degree of overlap - ∆ (en) > ∆ (NH3) strongest effect = order of proton basicity - Ligand field strength of halide ions F- > Cl- > Br- > I= order of proton basicity - Ligands Li d w/ / occupied i d p orbitals: bit l π-donors d ( σ-bonding (+ b di e-) ∆ ↓ (section 10.4.3) most halide complexes: high-spin configuration - ex) the order of other examples: H2O > F- > RCO2- > OH- > Cl- > Br- > IInorganic Chemistry 2 2011 Fall T.-S.You 10.4.4 Types of Ligands and the Spectrochemical Series - Ligands w/ π* or d orbitals: π back-bonding is possible becomes π acceptors ∆↑ ex)) CO, CO CN- > phenanthroline h th li > NO2- > NCS- When these lists are combined,, spectrochemical series (from strong π-acceptor to strong π-donor) CO, CN- > phen > NO2- > en > NH3 > NCS- > H2O > F- > RCO2- > OH- > Cl- > Br- > ILow spin High spin Strong field Weak field Large ∆ donor only Small ∆ π acceptors π donors Strong interactions w/ TM’s orbitals Inorganic Chemistry 2 2011 Fall T.-S.You 6 10.4.5 Magnitudes of eσ, eπ, and ∆ ▪ Charge on metal - Changing the ligands or the M → affects the magnitudes of eσ, eπ, ∆ result in a change in the # unpaired e- ex) H2O: weak field ligand w/ Co2+ in Oh → [Co(H2O)6]2+, high-spin, 3 unpaired ew/ Co3+ in Oh → [Co(H2O)6]3+, low-spin, no unpaired e- Fig.10.27 Inorganic Chemistry 2 2011 Fall T.-S.You 10.4.5 Magnitudes of eσ, eπ, and ∆ ▪ Different Ligands - ex) [Fe(H2O)6]3+ vs [Fe(CN)6]3+ high-spin low-spin balance among ∆, Πc, Πe → determine high- or low-spin - Tetrahedral complex: ∆t is small low-spin tetrahedral complex is unlikely!! instead,, low-spin octahedral complex!! - Table 10.12, Table 10.13: angular overlap parameters observed trends 1) eσ > eπ ∵ σ interaction: more direct orbital overlap b/w nuclei π interaction: small overlap, no direct toward each other 2) σ , π ↓ as size ↑ ∵ bond length ↑ → overlap ↓ as EN of halide ion ↓ ∵ the pull ↓ Inorganic Chemistry 2 2011 Fall T.-S.You 7 10.4.5 Magnitudes of eσ, eπ, and ∆ - Table 10.12: ligands – listed in the spectrochemical series order ex) for Cr3+ → CN- is listed first highest in the spectrochemical series ∵ π-acceptor (eπ is ‘-’) en →e → NH3 : affected only by eπ values (σ-donor ability) → halide ions: ∵ at the bottom of the series π-donor & σ-donor ▪ Special Cases - The angular overlap model: can describe the electronic E of complexes w/ diff. shapes or w/ combinations of diff. diff ligands : estimate the magnitudes of eg & eπ w/ diff. ligands - ex) [Co(NH3)4Cl2]+: low-spin ∴ magnetic property does not depend on ∆o but, ∆o effect on the visible spectrum (Chapter 11) - Helpful to compare E of diff. geometries ex) for 4-coordinate complex → tetrahedral or sqaure-planar?? (section 10.6) Inorganic Chemistry 2 2011 Fall T.-S.You 10.5 The John John--Teller Effect - There can not be unequal occupation of orbitals w/ identical E. molecules distorted no longer degenerate orbitals!! ex) Cu(Ⅱ), d9, Oh - Fig.10.28 3 e- in the two eg w/o J-T effect J-T effect → slight shape change of a complex change in E of the orbitals distortion 1) elongation (along one axis) or 2) compression (along one axis) → in Oh,, eg*: direct toward ligands larger effect on E level t2g: No direct overlap small effect Inorganic Chemistry 2 2011 Fall T.-S.You 8 10.5 The John John--Teller Effect - strong J-T effect: when eg* are unequally occupied weak J-T effect: when t2g are unequally occupied - Expected J-T effect - ex) significant J-T effects, Cr(Ⅱ) (d4) high-spin Mn(Ⅲ) (d4) Cu(Ⅱ) (d9) Ni(Ⅲ) ( ) ((d7) low-spin Co(Ⅱ) (d7) - low-spin Cr(Ⅱ): distorted from Oh → to D4h : 2 absorption bands one in Vis one in near IR : if pure Oh → only one d-d transition (Chapter 11) Inorganic Chemistry 2 2011 Fall T.-S.You 10.5 The John John--Teller Effect - ex) - Cu(Ⅱ): significant J-T effects → elongation : affect equilibrium constant : [Cu(NH3)4]2+ → distorted Oh w/ 2 H2O at greater distance → putting the 5th & 6th NH3 is difficult see the formation constant the bond distance of two axial position: longer!! smaller equilibrium constant for these positions!! ∴ Cu(Ⅱ) complexes prefer square-planar geometry!! [Cu(H2O)6]2+ + NH3 [Cu(NH3)(H2O)5 ]2+ [Cu(NH3)(H2O)5]2+ + H2O + NH3 [Cu(NH3)2(H2O)4]2+ [Cu(NH3)3(H2O)3]2+ [Cu(NH3)4(H2O)2]2+ + NH3 K1 = 20,000 + H2O K2 = 4,000 [Cu(NH3)3(H2O)3 ]2+ + H2O K3 = 1,000 + NH3 [Cu(NH3)4(H2O)2 ]2+ + H2O K4 = 200 + NH3 [Cu(NH3)5(H2O)]2+ K5 = 0.3 [Cu(NH3)(H2O)]2+ + NH3 Inorganic Chemistry 2 [Cu(NH3)2(H2O)4]2+ [Cu(NH3)6]2+ + H2O 2011 Fall + H2O K6 = very small T.-S.You 9