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ASTRONOMY 205.1 GENERAL ASTRONOMY I “Solutions” Sheet Student Name Laboratory Exercise 1. The Length of a Sidereal Day Date Experiment Performed Purpose. To determine the length of the sidereal day (the “star” day) from an image of the circumpolar region of the sky. The length of the sidereal day is defined as the time interval between two successive transits of the vernal equinox across the meridian. It is time based upon the Earth’s rotation on its axis with respect to the celestial sphere, or stars, rather than with respect to the Sun, as is the case for solar time. In order to measure the length of the sidereal day, it is necessary to measure the apparent motion of the stars around the sky. Since that is difficult to do for a full day, it is convenient to image the motion of the stars for a shorter, but well-established, time duration. Procedure. See Laboratory Manual. Equipment. image of circumpolar star trails (from Laboratory Manual, see next page) protractor a pocket calculator Data. Angles obtained from careful measurements made with a protractor, with setting precision estimated to be ±0°.1 to ±0°.2. Angle Measurements for Six Star Trails 15m Exposure A Star 1 Star 2 Star 3 Star 4 Star 5 Star 6 20m Exposure B 110m Exposure C 95m Exposure C–A 90m Exposure C–B Image of Circumpolar Star Trails Estimates for Length of Sidereal Day 360 110 m C 360 95 m CA 360 90 m CB Star 1 Star 2 Star 3 Star 4 Star 5 Star 6 Average of “Best” Values Largest – Smallest Value Estimated Length of Sidereal Day = 1 2 ± = minutes Accepted Length of Sidereal Day = 1436 minutes. Accepted Length of Solar Day = 1440 minutes. Earth’s Equatorial Velocity = 2R Sidereal Day = 2 (6378 km) Sidereal Day (seconds) km s km s–1. Conclusions. 1. The estimated length of the sidereal day accepted value for the length of the sidereal day, to within experimental uncertainty. with the 2. The estimated length of the sidereal day accepted value for the length of the solar day day, to within experimental uncertainty. with the 3. The estimated equatorial velocity for the Earth is km s–1. Discussion. (Do you expect the lengths of the solar day to agree with the value obtained for the length of the sidereal day? Why or why not?)