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Lesson 2 COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY Name_____________________________ Date__________________________ Lesson 2: Circles, Chords, Diameters, and Their Relationship Classwork Opening Exercise Construct the perpendicular bisector of line Μ Μ Μ Μ π΄π΅ below (as you did in Module 1). Draw another line that bisects Μ Μ Μ Μ π΄π΅ but is not perpendicular to it. List one similarity and one difference between the two bisectors. Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 1 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY Now do another construction: 2. Mark point P above before using your compass. Construct a circle of any radius, and identify the center as point π. Draw a chord, and label it Μ Μ Μ Μ π΄π΅ . 3. Construct the perpendicular bisector of Μ Μ Μ Μ π΄π΅ . 4. What do you notice about the perpendicular bisector of Μ Μ Μ Μ π΄π΅ ? 5. Draw another chord and label it Μ Μ Μ Μ πΆπ· . 6. Construct the perpendicular bisector of Μ Μ Μ Μ πΆπ· . 7. What do you notice about the perpendicular bisector of Μ Μ Μ Μ πΆπ· ? 8. What can you say about the points on a circle in relation to the center of the circle? 9. Look at the circles, chords, and perpendicular bisectors created by your neighbors. What statement can you make about the perpendicular bisector of any chord of a circle? Why? 1. 10. How does this relate to the definition of the perpendicular bisector of a line segment? Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 2 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY How does a circle help us simplify triangle proofs? Given for Case 1 & Case 2: Μ Μ Μ Μ is a chord. 1. π¨π© 2. C is the center of circle C. Letβs write down what we know from the picture and what is given (mark up your diagram): Μ Μ Μ Μ , and Μ Μ Μ Μ Μ Μ Μ Μ . Case 1: Given: Circle πͺ with diameter Μ Μ Μ Μ π«π¬, chord π¨π© π¨π = ππ© Μ Μ Μ Μ , and Μ Μ Μ Μ Μ Μ Μ Μ Case 2: Given: Circle πͺ with diameter Μ Μ Μ Μ π«π¬, chord π¨π© π«π¬ β₯ π¨π© Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 3 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY Remember how we proved triangles are congruent: (SAS, ASA, HL, SSS, AAS). Exercises 1β6 1. Prove the theorem: If a diameter of a circle bisects a chord, then it must be perpendicular to the chord. You can use the diagram shown below. 2. Prove the theorem: If a diameter of a circle is perpendicular to a chord, then it bisects the chord. You can use the diagram shown below Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 4 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY 3. The distance from the center of a circle to a chord is defined as the length of the perpendicular segment from the center to the chord. Note that since this perpendicular segment may be extended to create a diameter of the circle, the segment also bisects the chord, as proved in Exercise 2. Theorem: In a circle, if two chords are congruent, then the center is equidistant from the two chords. Given: Circle πΆ with chords Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ πͺπ«; π¨π© = πͺπ«; π is the midpoint of Μ Μ Μ Μ π¨π© and π¬ is the Μ Μ Μ Μ . midpoint of πͺπ« Prove: πΆπ = πΆπ¬ 4. Prove the theorem: In a circle, if the center is equidistant from two chords, then the two chords are congruent. Use the diagram below. Μ Μ Μ Μ ; πΆπ = πΆπ¬; π is the midpoint of π¨π© Μ Μ Μ Μ Μ Μ Μ Μ and πͺπ« Μ Μ Μ Μ and π¬ is the midpoint of πͺπ« Given: Circle πΆ with chords π¨π© Prove: π¨π© = πͺπ« Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 5 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY 5. A central angle defined by a chord is an angle whose vertex is the center of the circle and whose rays intersect the circle. The points at which the angleβs rays intersect the circle form the endpoints of the chord defined by the central angle. Prove the theorem: In a circle, congruent chords define central angles equal in measure. Use the diagram below. 6. Prove the theorem: In a circle, if two chords define central angles equal in measure, then they are congruent. Lesson Summary Theorems about chords and diameters in a circle and their converses: 1. If a diameter of a circle bisects a chord, then it must be perpendicular to the chord. 2. If a diameter of a circle is perpendicular to a chord, then it bisects the chord. 3. If two chords are congruent, then the center is equidistant from the two chords. 4. If the center is equidistant from two chords, then the two chords are congruent. 5. Congruent chords define central angles equal in measure. 6. If two chords define central angles equal in measure, then they are congruent. Relevant Vocabulary EQUIDISTANT: A point π΄ is said to be equidistant from two different points π΅ and πΆ if π΄π΅ = π΄πΆ. Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 6 Lesson 2 COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY Diagram Explanation of Diagram Theorem or Relationship Diameter of a circle bisecting a chord If a diameter of a circle bisects a chord, then it must be perpendicular to the chord. If a diameter of a circle is perpendicular to a chord, then it bisects the chord. Two congruent chords equidistant from center If two chords are congruent, then the center of a circle is equidistant from the two chords. If the center of a circle is equidistant from two chords, then the two chords are congruent. Congruent chords Congruent chords define central angles equal in measure. If two chords define central angles equal in measure, then they are congruent. Problem Set 1. In this drawing, π΄π΅ = 30, ππ = 20, and ππ = 18. What is πΆπ? Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 7 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY 2. In the figure to the right, Μ Μ Μ Μ π΄πΆ β₯ Μ Μ Μ Μ π΅πΊ , Μ Μ Μ Μ π·πΉ β₯ Μ Μ Μ Μ πΈπΊ , and πΈπΉ = 12. Find π΄πΆ. 3. In the figure, π΄πΆ = 24 and π·πΊ = 13. Find πΈπΊ. Explain your work. 4. In the figure, π΄π΅ = 10 and π΄πΆ = 16. Find π·πΈ. 5. In the figure, πΆπΉ = 8, and the two concentric circles have radii of 10 and 17. Find π·πΈ. Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 8 COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY 6. In the figure, the two circles have equal radii and intersect at points π΅ and π·. π΄ and πΆ are centers of the circles. Μ Μ Μ Μ . Find π΅π·. Explain your work. π΄πΆ = 8, and the radius of each circle is 5. Μ Μ Μ Μ π΅π· β₯ π΄πΆ 7. In the figure, the two concentric circles have radii of 6 and 14. Chord Μ Μ Μ Μ π΅πΉ of the larger circle intersects the smaller Μ Μ Μ Μ β₯ Μ Μ Μ Μ circle at πΆ and πΈ. πΆπΈ = 8. π΄π· π΅πΉ . 8. a. Find π΄π·. b. Find π΅πΉ. In class, we proved: Congruent chords define central angles equal in measure. EXAMPLE β proof using transformations: a. Give another proof of this theorem based on the properties of rotations. Use the figure from Exercise 5. Μ Μ Μ Μ ) are congruent. Therefore, a rigid motion exists that carries Μ Μ Μ Μ and πͺπ« We are given that the two chords (π¨π© Μ Μ Μ Μ . The same rotation that carries π¨π© Μ Μ Μ Μ also carries π¨πΆ Μ Μ Μ Μ to πͺπΆ Μ Μ Μ Μ and π©πΆ Μ Μ Μ Μ Μ to π«πΆ Μ Μ Μ Μ Μ . The angle of Μ Μ Μ Μ to πͺπ« Μ Μ Μ Μ to πͺπ« π¨π© rotation is the measure of β π¨πΆπͺ, and the rotation is clockwise. b. Give a rotation proof of the converse: If two chords define central angles of the same measure, then they must be congruent. Using the same diagram, we are given that β π¨πΆπ© β β πͺπΆπ«. Therefore, a rigid motion (a rotation) carries Μ Μ Μ Μ to πͺπΆ Μ Μ Μ Μ and π©πΆ Μ Μ Μ Μ Μ to π«πΆ Μ Μ Μ Μ Μ . The angle of rotation is the measure β π¨πΆπ© to β πͺπΆπ«. This same rotation carries π¨πΆ of β π¨πΆπͺ, and the rotation is clockwise. Lesson 2: Date: Circle, Chords, Diameters, and Their Relationships 3/15/15 9