Download Lesson 2: Circles, Chords, Diameters, and Their Relationship

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Euler angles wikipedia , lookup

Trigonometric functions wikipedia , lookup

Line (geometry) wikipedia , lookup

Problem of Apollonius wikipedia , lookup

History of geometry wikipedia , lookup

Pi wikipedia , lookup

Euclidean geometry wikipedia , lookup

Area of a circle wikipedia , lookup

History of trigonometry wikipedia , lookup

Transcript
Lesson 2
COMMON CORE MATHEMATICS CURRICULUM
M5
GEOMETRY
Name_____________________________
Date__________________________
Lesson 2: Circles, Chords, Diameters, and Their Relationship
Classwork
Opening Exercise
Construct the perpendicular bisector of line Μ…Μ…Μ…Μ…
𝐴𝐡 below (as you did in Module 1).
Draw another line that bisects Μ…Μ…Μ…Μ…
𝐴𝐡 but is not perpendicular to it.
List one similarity and one difference between the two bisectors.
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
1
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
Now do another construction:
2.
Mark point P above before using your compass. Construct a circle of any radius, and identify the center as point 𝑃.
Draw a chord, and label it Μ…Μ…Μ…Μ…
𝐴𝐡 .
3.
Construct the perpendicular bisector of Μ…Μ…Μ…Μ…
𝐴𝐡 .
4.
What do you notice about the perpendicular bisector of Μ…Μ…Μ…Μ…
𝐴𝐡 ?
5.
Draw another chord and label it Μ…Μ…Μ…Μ…
𝐢𝐷 .
6.
Construct the perpendicular bisector of Μ…Μ…Μ…Μ…
𝐢𝐷 .
7.
What do you notice about the perpendicular bisector of Μ…Μ…Μ…Μ…
𝐢𝐷 ?
8.
What can you say about the points on a circle in relation to the center of the circle?
9.
Look at the circles, chords, and perpendicular bisectors created by your neighbors. What statement can you make
about the perpendicular bisector of any chord of a circle? Why?
1.
10. How does this relate to the definition of the perpendicular bisector of a line segment?
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
2
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
How does a circle help us simplify triangle proofs?
Given for Case 1 & Case 2:
Μ…Μ…Μ…Μ… is a chord.
1. 𝑨𝑩
2. C is the center of circle C.
Let’s write down what we know from the picture and what is given (mark up your diagram):
Μ…Μ…Μ…Μ…, and Μ…Μ…Μ…Μ…
Μ…Μ…Μ…Μ….
Case 1: Given: Circle π‘ͺ with diameter Μ…Μ…Μ…Μ…
𝑫𝑬, chord 𝑨𝑩
𝑨𝑭 = 𝑭𝑩
Μ…Μ…Μ…Μ…, and Μ…Μ…Μ…Μ…
Μ…Μ…Μ…Μ…
Case 2: Given: Circle π‘ͺ with diameter Μ…Μ…Μ…Μ…
𝑫𝑬, chord 𝑨𝑩
𝑫𝑬 βŠ₯ 𝑨𝑩
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
3
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
Remember how we proved triangles are congruent: (SAS, ASA, HL, SSS, AAS).
Exercises 1–6
1.
Prove the theorem: If a diameter of a circle bisects a chord, then it must be perpendicular to the chord.
You can use the diagram shown below.
2.
Prove the theorem: If a diameter of a circle is perpendicular to a chord, then it bisects the chord.
You can use the diagram shown below
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
4
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
3.
The distance from the center of a circle to a chord is defined as the length of the perpendicular segment from the
center to the chord. Note that since this perpendicular segment may
be extended to create a diameter of the circle, the segment also bisects
the chord, as proved in Exercise 2.
Theorem: In a circle, if two chords are congruent, then the center is
equidistant from the two chords.
Given: Circle 𝑢 with chords Μ…Μ…Μ…Μ…
𝑨𝑩 and Μ…Μ…Μ…Μ…
π‘ͺ𝑫; 𝑨𝑩 = π‘ͺ𝑫; 𝑭 is the midpoint of Μ…Μ…Μ…Μ…
𝑨𝑩 and 𝑬 is the
Μ…Μ…Μ…Μ….
midpoint of π‘ͺ𝑫
Prove: 𝑢𝑭 = 𝑢𝑬
4.
Prove the theorem: In a circle, if the center is equidistant from two chords, then the two chords are congruent.
Use the diagram below.
Μ…Μ…Μ…Μ…; 𝑢𝑭 = 𝑢𝑬; 𝑭 is the midpoint of 𝑨𝑩
Μ…Μ…Μ…Μ…
Μ…Μ…Μ…Μ… and π‘ͺ𝑫
Μ…Μ…Μ…Μ… and 𝑬 is the midpoint of π‘ͺ𝑫
Given: Circle 𝑢 with chords 𝑨𝑩
Prove: 𝑨𝑩 = π‘ͺ𝑫
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
5
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
5.
A central angle defined by a chord is an angle whose vertex is the center of the circle and whose rays intersect the
circle. The points at which the angle’s rays intersect the circle form the endpoints of the chord defined by the
central angle.
Prove the theorem: In a circle, congruent chords define central angles equal in measure.
Use the diagram below.
6.
Prove the theorem: In a circle, if two chords define central angles equal in measure, then they are congruent.
Lesson Summary
Theorems about chords and diameters in a circle and their converses:
1.
If a diameter of a circle bisects a chord, then it must be perpendicular to the chord.
2.
If a diameter of a circle is perpendicular to a chord, then it bisects the chord.
3.
If two chords are congruent, then the center is equidistant from the two chords.
4.
If the center is equidistant from two chords, then the two chords are congruent.
5.
Congruent chords define central angles equal in measure.
6.
If two chords define central angles equal in measure, then they are congruent.
Relevant Vocabulary
EQUIDISTANT: A point 𝐴 is said to be equidistant from two different points 𝐡 and 𝐢 if 𝐴𝐡 = 𝐴𝐢.
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
6
Lesson 2
COMMON CORE MATHEMATICS CURRICULUM
M5
GEOMETRY
Diagram
Explanation of Diagram
Theorem or Relationship
Diameter of a circle bisecting a chord
If a diameter of a circle bisects a
chord, then it must be perpendicular
to the chord.
If a diameter of a circle is
perpendicular to a chord, then it
bisects the chord.
Two congruent chords equidistant
from center
If two chords are congruent, then the
center of a circle is equidistant from
the two chords.
If the center of a circle is equidistant
from two chords, then the two chords
are congruent.
Congruent chords
Congruent chords define central
angles equal in measure.
If two chords define central angles
equal in measure, then they are
congruent.
Problem Set
1.
In this drawing, 𝐴𝐡 = 30, 𝑂𝑀 = 20, and 𝑂𝑁 = 18. What is 𝐢𝑁?
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
7
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
2.
In the figure to the right, Μ…Μ…Μ…Μ…
𝐴𝐢 βŠ₯ Μ…Μ…Μ…Μ…
𝐡𝐺 , Μ…Μ…Μ…Μ…
𝐷𝐹 βŠ₯ Μ…Μ…Μ…Μ…
𝐸𝐺 , and 𝐸𝐹 = 12. Find 𝐴𝐢.
3.
In the figure, 𝐴𝐢 = 24 and 𝐷𝐺 = 13. Find 𝐸𝐺. Explain your work.
4.
In the figure, 𝐴𝐡 = 10 and 𝐴𝐢 = 16. Find 𝐷𝐸.
5.
In the figure, 𝐢𝐹 = 8, and the two concentric circles have radii of 10 and 17. Find 𝐷𝐸.
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
8
COMMON CORE MATHEMATICS CURRICULUM
Lesson 2
M5
GEOMETRY
6.
In the figure, the two circles have equal radii and intersect at points 𝐡 and 𝐷. 𝐴 and 𝐢 are centers of the circles.
Μ…Μ…Μ…Μ… . Find 𝐡𝐷. Explain your work.
𝐴𝐢 = 8, and the radius of each circle is 5. Μ…Μ…Μ…Μ…
𝐡𝐷 βŠ₯ 𝐴𝐢
7.
In the figure, the two concentric circles have radii of 6 and 14. Chord Μ…Μ…Μ…Μ…
𝐡𝐹 of the larger circle intersects the smaller
Μ…Μ…Μ…Μ… βŠ₯ Μ…Μ…Μ…Μ…
circle at 𝐢 and 𝐸. 𝐢𝐸 = 8. 𝐴𝐷
𝐡𝐹 .
8.
a.
Find 𝐴𝐷.
b.
Find 𝐡𝐹.
In class, we proved: Congruent chords define central angles equal in
measure. EXAMPLE – proof using transformations:
a.
Give another proof of this theorem based on the properties of rotations. Use the figure from Exercise 5.
Μ…Μ…Μ…Μ…) are congruent. Therefore, a rigid motion exists that carries
Μ…Μ…Μ…Μ… and π‘ͺ𝑫
We are given that the two chords (𝑨𝑩
Μ…Μ…Μ…Μ…. The same rotation that carries 𝑨𝑩
Μ…Μ…Μ…Μ… also carries 𝑨𝑢
Μ…Μ…Μ…Μ… to π‘ͺ𝑢
Μ…Μ…Μ…Μ… and 𝑩𝑢
Μ…Μ…Μ…Μ…Μ… to 𝑫𝑢
Μ…Μ…Μ…Μ…Μ…. The angle of
Μ…Μ…Μ…Μ… to π‘ͺ𝑫
Μ…Μ…Μ…Μ… to π‘ͺ𝑫
𝑨𝑩
rotation is the measure of βˆ π‘¨π‘Άπ‘ͺ, and the rotation is clockwise.
b.
Give a rotation proof of the converse: If two chords define central angles of the same measure, then they must be
congruent.
Using the same diagram, we are given that βˆ π‘¨π‘Άπ‘© β‰… ∠π‘ͺ𝑢𝑫. Therefore, a rigid motion (a rotation) carries
Μ…Μ…Μ…Μ… to π‘ͺ𝑢
Μ…Μ…Μ…Μ… and 𝑩𝑢
Μ…Μ…Μ…Μ…Μ… to 𝑫𝑢
Μ…Μ…Μ…Μ…Μ…. The angle of rotation is the measure
βˆ π‘¨π‘Άπ‘© to ∠π‘ͺ𝑢𝑫. This same rotation carries 𝑨𝑢
of βˆ π‘¨π‘Άπ‘ͺ, and the rotation is clockwise.
Lesson 2:
Date:
Circle, Chords, Diameters, and Their Relationships
3/15/15
9