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Page 1 of 7 Chapter 6: Normal Distribution • Section 6.1 Continuous Random Variables Measurements of weight, height and temperature are represented by continuous random variables. Definition: f(x) is called a probability density function of a continuous random variable X if (1) ∫ ∞ −∞ f ( x)dx = 1 (2) f ( x) ≥ 0 For continuous random variable X • P(a ≤ X ≤ b) = • P(X = b) = 0 ∫ b a f ( x)dx = area under the density curve between a and b. f(x) a b x P(a ≤ X ≤ b) = P(a < X ≤ b) = P(a ≤ X < b) = P(a < X < b) Because of symmetry P(Z > 0) = P(Z < 0) = 0.5 and P(Z < − a) = P(Z > a) Page 2 of 7 • Section 6.2 – 6.3 Normal Probability Distribution Definition: A random variable X is said to have a normal distribution if its probability density function is given by f ( x) = 1 σ 2π e 1 x−µ − 2 σ 2 , for −∞ < x < ∞ . The mean and variance of X are µ and σ 2 . They both characterize the normal density. The above is bell - shaped or mound – shaped. Definition: A random variable Z is said have a standard normal distribution if its probability density function is given by f ( z) = 1 2π e− z 2 /2 , for − ∞ < z < ∞ . The mean and variance of Z are µ = 0 and σ 2 = 1. Note that Z = X −µ σ . Page 3 of 7 P(a ≤ X ≤ b) = P(a < X ≤ b) = P(a ≤ X < b) = P(a < X < b) A table exists for the computation of the above integral (see the inside cover of our textbook) To find any (standard normal) probability: • Sketch the normal curve • Shade the required area • Use the table accordingly Example: a) P( Z < 1.5 ) b) P( Z > -2.42) c) P( Z > 3.02) d) P( Z >-2.33) e) P( -2.50 < Z < -1.17) f) ( -1.20 < Z < 2.40) Page 4 of 7 Computing Percentiles Example: Find b so that a) P( Z < b ) = 0.9803 b) P( Z > b) = 0.9960 c) P( Z < b) = 0.0166 d) P( Z > b ) = 0.0017 Suppose we want to find the probability of any random variable X X −µ • Standardized the random variable X to obtain Z = • Follow previous method to find required probability. σ Example: If X is normally distributed with µ = 38 and σ = 5, find: a) P( X > 46 ) b) P( X < 36) Page 5 of 7 c) P( 31 < X < 41) Examples Ex 6.11 page 225 Ex 6.26 page 227 Ex 6.32 page 228 Page 6 of 7 Supplementary #10, #11, #12 Page 7 of 7 • Section 6.4 Normal Approximation to the Binomial (optional) Recall that a binomial random variable X has mean µ = np and standard deviation σ = npq . If n for a binomial distribution is large and p is not too close to 0 or 1, we may use normal approximation to the binomial. X − np npq • We standardized X to obtain Z = • We compute P(X ≥ a) as in the normal distribution Note: Since the original binomial random variable is discrete and we want to use a continuous normal distribution to approximate it, we apply a continuity correction. Continuity correction is the addition or subtraction of 0.5. Binomial Normal Approximation P(X ≤ b) P(X ≤ b + 0.5) P(X ≥ a) P(X ≥ a – 0.5) P(a ≤ X ≤ b) P(a – 0.5 ≤ X ≤ b + 0.5) P(X = a) P(a – 0.5 ≤ X ≤ a + 0.5) For any other inequality < (or >), first change < to ≤ (or > to ≥ ). You may add to the given probability, but do not take away. For a binomial random variable X, P(X < 4) = P(X ≤ 3) and P(X > 7) = P(X ≥ 8). Example: Ex 6.44 page 235