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Math 2413 Section 1.5 – The Intermediate Value Theorem Section 1.5 Notes Theorem 1.5.1: The Intermediate Value Theorem If f is a continuous function on the closed interval [a,b], and N is a real number such that f (a) ≤ N ≤ f (b) or f (b) ≤ N ≤ f (a), then there is at least one number c in the interval (a,b) such that f (c) = N . That is, if a function is continuous on a closed interval, it does not skip any values; it has no breaks or jumps. In geometric terms, this theorem says that if y = N is a horizontal line between y = f (a) and y = f (b), then the graph of f must intersect y = N somewhere (at least once). There is a hole on the graph of function f(x) at x = -2. We say this function is NOT continuous at x = -2. This theorem can be used to prove the existence of the zeros of a function. If f (a) < 0 and f (b) > 0 (or vice versa), then f (a) < 0 < f (b) and by the Intermediate Value Theorem, there is at least one c such that f (c) = 0 . That is, the function has at least one root between the numbers a and b. f (a) < 0 < f (b) f (b) < 0 < f (a) 1 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) Math 2413 Example 1: Show that the equation x 3 x 2 5 x 2 0 has a root between 0 and 1. Section 1.5 Notes Theorem 1.5.2: The Extreme-Value Theorem If f is continuous on a bounded interval [a,b], then f takes on both a maximum value and a minimum value. Examples: For each function, determine whether the function attains the extreme value on the specified interval. 1. f ( x ) x on its domain. 2 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) Math 2413 2. Section 1.5 Notes if x 0 5 f ( x) x if 0 x 3 on the interval [0, 3] 5 if 3 x Examples: x2 if 1. Find A given that the function f ( x) Ax 42 if x6 x6 is continuous at 6. 3 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) Math 2413 Section 1.5 Notes 2. In Exercises 15-26, state whether it is possible to have a function f defined on the indicated: a. f is defined on [2, 5]; f is continuous on [2, 5], minimum value 2, maximum value f (2) = 5 b. f is defined on [4, 5]; f is continuous on [4, 5) , minimum value f (5) = 4, and no maximum value. c. f is defined on [3, 6]; f is continuous on [3, 6], maximum value of 6 and a minimum value of 6. d. f is defined on [2, 5]; f is continuous on [2, 5], is non-constant, and takes on only integer values. 4 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/)