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Absolute geometry The exterior angle inequality and Saccheri-Legendre Material for this section references College Geometry: A Discovery Approach, 2/e, David C. Kay, Addison Wesley, 2001. In particular, see section 3.4, pp 152-161. Exterior angle inequality An exterior angle of a triangle has angle measure greater than that of either opposite interior angle. [Kay, p 156] This simple theorem is described as “the key theorem of absolute geometry.” The proof on page 156 is straightforward. It relies on the construction of a specific triangle: and most of the proof is justifying that the triangle can be constructed and gives a pair of congruent triangles. After reading the proof, there’s a lemma you need to work through, that claims that the triangle constructed above has one other property - the sum of the measures of its angles is equal to the angle sum of the original triangle (even though none of the individual angles are congruent!) Saccheri-Legendre theorem The angle sum of any triangle cannot exceed 180◦ . [Kay, p 156] The key point here of course is that the sum isn’t necessarily equal to 180◦ , but must be less than or equal to 180◦ . The theorem is simple; the proof is not. There’s some fairly technical stuff going on there, but the idea is interesting, and can be explained somewhat intuitively. See the posted lecture.