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Skylar Geer – Stats 1040
Objective I
Roll Total
2
3
4
5
6
7
8
9
10
11
12
(Die1, Die2)
(1,1)
(1,2) (2,1)
(1,3) (3,1) (2,2)
(1,4) (4,1)(2,3)(3,2)
(1,5)(5,1) (3,3)(4,2)(2,4)
(1,6)(6,1)(3,4)(4,3)(5,2)(2,5)
(2,6)(6,2)(5,3)(3,5)(4,4)
(3,6)(6,3)(4,5)(5,4)
(5,5)(4,6)(6,4)
(5,6) (6,5)
(6,6)
# of Combo’s
1
2
3
4
5
6
5
4
3
2
1
Total: 36
Probability
1/36
2/36 or 1/18
3/36 or 1/12
4/36 or 1/9
5/36
6/36 or 1/6
5/36
4/36 or 1/9
3/36 or 1/12
2/36 or 1/18
1/36
The Probability of rolling P(7) is: 1/6
Conclusion for objective I:
The simulated probability of rolling a 7 is: (Total '7') / 100 = _14/100 or 7/50___.
The simulated probability or rolling a 4 is 10/100 or 1/10_? Rolling a 12? 5/100 or 1/25_.
Objective II
A. less than 20% B. 20-40 C. 40&-60% D. 60%-80% E. Over 80
Procedure for Objective II
Step A: To generate random numbers for 25 students who birthdays range from Jan 1 to Dec 31 (365
days) I will click on the “data analysis” tab under the “Data” tab. I will select “random number
generator.” I will enter in the following data.
Number of variables: 1
Number of random numbers: 25
Distribution: Uniform
Parameters: 1 to 365
Output range: $A$1
I will repeat this 9 more times to get a total of 10 classes.
Step B: In order to determine if there are duplicate birthdays I will sort all of the 10 classes from smallest
to largest. To do this I will right click on the column, click on “sort”, and then click on “custom sort”, and
then click on “continue with current selection.” I will repeat this 9 more times to sort all the classes.
Then I will compare the numbers to see if anyone has the same birthday.
Step C: I will count up the number of “yes’” and take it out of the total of 10 classes.
Conclusion:
The probability that a class of 25 students will have duplicate birthdays is: __7/10 classes .
A. less than 20% B. 20-40 C. 40&-60% D. 60%-80% E. Over 80. I was close just about 10% off.