Download QQQ-GCSE-Probability (Assessment)

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Statistics wikipedia , lookup

History of statistics wikipedia , lookup

Inductive probability wikipedia , lookup

Birthday problem wikipedia , lookup

Ars Conjectandi wikipedia , lookup

Probability interpretations wikipedia , lookup

Probability wikipedia , lookup

Transcript
QQQ – GCSE – Probability
1. The probability that Bob eats a burger today is 0.3. The probability that his wife Bobette eats a
burger today is 0.6. The probability that they both eat a burger is 0.2. Are the events of Bob and
Bobette eating burgers independent? Give a reason.
___________________________________________________________
___________________________________________________________ (2 marks)
2. The table shows the probability of each outcome on an unfair 4-sided spinner.
Outcome:
Probability:
1
0.5
2
0.2
3
π‘₯
4
2π‘₯
I spin the spinner 200 times. How many times do I expect to see a 4?
_______________________________________________________________
_______________________________________________________________ (3 marks)
3. I spin two 3-sided spinners, each with the numbers 1, 2 and 3 on them. I multiply the numbers
from the two spinners.
a. Draw a sample space diagram to indicate the possible outcomes.
(2 marks)
b. Use your sample space diagram to calculate the probability that the product of the two
numbers is prime (note that 1 is not a prime number).
_______________________________________________________________
_______________________________________________________________
____________________________________________________________ (2 marks)
4. Bart and Bertie go to see a movie. The probability that Bart enjoys the movie is 0.6. The
probability that Bertie enjoys the movie is 0.3. These two events are independent.
a. What’s the probability they both enjoy the movie?
____________________________________________________ (1 mark)
b. What’s the probability that exactly one of them enjoys the movie?
______________________________________________________
________________________________________________________ (3 marks)
5. Here are seven tiles.
Jim takes at random a tile.
He does not replace the tile.
Jim then takes at random a second tile.
(a) Calculate the probability that both the tiles Jim takes have the number 1 on them.
..............................................
(2)
(b) Calculate the probability that the number on the second tile Jim takes is greater than the
number on the first tile he takes.
..............................................
(3)
6. Let 𝐻 be the event that I did my homework and 𝐷 the event that I get a detention next
lesson.
The probability that I do my homework is 0.8. The probability I get a detention next lesson if
I do my homework is 0.05, and 0.9 if I didn’t.
a. Use this information to complete the probability tree: (1 mark)
𝐷
𝐻
𝐷′
𝐷
𝐻′
𝐷′
b. Use your tree to work out the probability that I get a detention next lesson. (2)
________________________________________________________________
________________________________________________________________
Awards: 15/21 Bronze, 17/21 Silver, 19/21 Gold, 21/21 Platinum
Answers
1. No (1 mark), because if they were independent, then the probability of
both eating a burger would be 0.3 × 0.6 = 0.18. (1 mark)
2. Determines that π‘₯ = 0.1 (1mark). Does some multiplication of 200 with
their probability (1 method mark). Answer of πŸ’πŸŽ. (1 mark)
3. a) 1 mark for construction of 2D table with 1, 2, 3 marked across top row
and leftmost column. 1 mark for correct values.
1
2
3
1
1
2
3
2
2
4
6
3
3
6
9
4
b) 2 marks for correct answer of .
9
4. a) 𝑝(π΅π‘œπ‘‘β„Ž π‘’π‘›π‘—π‘œπ‘¦) = 0.6 × 0.3 = 0.18.
b) 𝑝(𝑂𝑛𝑒 π‘’π‘›π‘—π‘œπ‘¦π‘ ) = (0.6 × 0.7) + (0.4 × 0.3) = 0.54
3 marks for fully correct answer.
2 marks if one numerical error.
1 mark for presence of either 0.6 × 0.7 or 0.4 × 0.3.
2
1
2
7
6
42
5. a) × =
2
5
=
3
1
21
(1 method mark, 1 accuracy mark)
2
8
b) ( × ) + ( × ) = (3 marks)
7
6
7
6
21
6. a) 1 mark for all correct probabilities.
0.05 𝐷
0.8
𝐻
0.95 𝐷′
0.9
0.2
𝐷
𝐻′
0.1
𝐷′
b) 𝑝(π·π‘’π‘‘π‘’π‘›π‘‘π‘–π‘œπ‘›) = (0.8 × 0.05) + (0.2 × 0.9) = 0.22 π‘œπ‘Ÿ
(1 mark for method, 1 for correct answer)
Total marks: 21 (15 for Bronze, 17 for Silver, 19 for Gold)
11
50