Download geometry module 1 lesson 23 base angles of isosceles triangles

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Transcript
GEOMETRY
MODULE 1 LESSON 23
BASE ANGLES OF ISOSCELES TRIANGLES
OPENING EXERCISE
Describe the additional piece of information needed for each pair of triangles to satisfy the SAS
triangle congruence criteria.
ο‚·
Given: 𝐴𝐡 = 𝐷𝐢
Additional Info Necessary:
We need information to show congruent angles.
Prove: βˆ†π΄π΅πΆ β‰… βˆ†π·πΆπ΅
ο‚·
Μ…Μ…Μ…Μ… βˆ₯ 𝑅𝑆
Μ…Μ…Μ…Μ…
Given: 𝐴𝐡 = 𝑅𝑆 and 𝐴𝐡
Additional Info Necessary:
We need information to show congruent bases.
Prove: βˆ†π΄π΅πΆ β‰… βˆ†π‘…π‘†π‘‡
DISCUSSION
Consider the isosceles triangle. We accept that an isosceles triangle, which
has (at least) two congruent sides, also has congruent base angles.
We can prove that π‘šβˆ π΅ = π‘šβˆ πΆ in two ways: Transformations and SAS.
What transformation can we use to map ∠𝐡 onto ∠𝐢?
Reflection on the line of symmetry.
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1
Let’s prove ∠𝐡 β‰… ∠𝐢 through SAS. To help with our proof, we
construct an angle bisector.
STEP
JUSTIFICATION
𝐴𝐡 = 𝐴𝐢
Given
𝐴𝐷 = 𝐴𝐷
Reflexive Property
π‘šβˆ π΄π΅π· = π‘šβˆ π΄πΆπ·
Definition of Angle Bisector
βˆ†π΄π΅π· β‰… βˆ†π΄πΆπ·
SAS
∠𝐡 β‰… ∠𝐢
Corresponding angles of congruent triangles are
congruent.
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2
PRACTICE
1. Given: 𝐽𝐾 = 𝐽𝐿 and Μ…Μ…Μ…
𝐽𝑅 bisects Μ…Μ…Μ…Μ…
𝐾𝐿.
Μ…Μ…Μ… βŠ₯ 𝐾𝐿
Μ…Μ…Μ…Μ…
Prove: 𝐽𝑅
STEP
JUSTIFICATION
Μ…Μ…Μ… bisects 𝐾𝐿
Μ…Μ…Μ…Μ….
𝐽𝐾 = 𝐽𝐿 and 𝐽𝑅
Given
∠𝐾 = ∠𝐿
Base angles of an isosceles triangle are
congruent.
𝐾𝑅 = 𝐾𝐿
Definition of segment bisector
βˆ†π½π‘…πΎ β‰… βˆ†π½π‘…πΏ
SAS
βˆ π½π‘…πΎ β‰… βˆ π½π‘…πΏ
Corresponding angles of congruent triangles
are congruent.
MOD1 L23
π‘šβˆ π½π‘…πΎ + π‘šβˆ π½π‘…πΏ = 180°
Linear pairs are supplementary.
2(π‘šβˆ π½π‘…πΎ) = 180°
Substitution
π‘šβˆ π½π‘…πΎ = 90°
Division
Μ…Μ…Μ…
𝐽𝑅 βŠ₯ Μ…Μ…Μ…Μ…
𝐾𝐿
Definition of perpendicular lines
3
2. Given: 𝐴𝐡 = 𝐴𝐢, 𝑋𝐡 = 𝑋𝐢.
Μ…Μ…Μ…Μ… bisects ∠𝐡𝐴𝐢
Prove: 𝐴𝑋
1
2
STEP
JUSTIFICATION
𝐴𝐡 = 𝐴𝐢
Given
π‘šβˆ π΄π΅πΆ = π‘šβˆ π΄πΆπ΅
Base angles of an isosceles triangle are equal in
measure.
𝑋𝐡 = 𝑋𝐢
3
4
π‘šβˆ π‘‹π΅πΆ = π‘šβˆ π‘‹πΆπ΅
Given
Base angles of an isosceles triangle are equal in
measure.
5
π‘šβˆ π΄π΅πΆ = π‘šβˆ π΄π΅π‘‹ + π‘šβˆ π‘‹π΅πΆ
Angle Addition
π‘šβˆ π΄πΆπ΅ = π‘šβˆ π΄πΆπ‘‹ + π‘šβˆ π‘‹πΆπ΅
6
π‘šβˆ π΄π΅π‘‹ = π‘šβˆ π΄π΅πΆ βˆ’ π‘šβˆ π‘‹π΅πΆ
Subtraction
π‘šβˆ π΄πΆπ‘‹ = π‘šβˆ π΄πΆπ΅ βˆ’ π‘šβˆ π‘‹πΆπ΅
7
π‘šβˆ π΄π΅π‘‹ = π‘šβˆ π΄π΅πΆ βˆ’ π‘šβˆ π‘‹π΅πΆ
Substitution from lines 2 and 4
π‘šβˆ π΄πΆπ‘‹ = π‘šβˆ π΄π΅πΆ βˆ’ π‘šβˆ π‘‹π΅πΆ
8
π‘šβˆ π΄π΅π‘‹ = π‘šβˆ π΄πΆπ‘‹
Transitive
9
βˆ†π΄π΅π‘‹ β‰… βˆ†π΄πΆπ‘‹
SAS
10
Corresponding angles of congruent triangles are
βˆ π΅π΄π‘‹ β‰… βˆ πΆπ΄π‘‹
congruent.
11
Μ…Μ…Μ…Μ…
𝐴𝑋 bisects ∠𝐡𝐴𝐢
Definition of Angle Bisector
SUMMARY
Today’s lesson used properties of isosceles triangles to complete proofs.
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4