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Study Guide for Geometry Mid-Term What are the three undefined terms in geometry? __point____ ______line_________ ____plane_________ The four triangle congruency postulates are: (list them here) ___SSS___ ___ASA____ __AAS_____ ___SAS___ Why could we NOT use SAS to prove these triangles to the left congruent? The congruent angle pair is not the included pair. This would be SSA which is not a congruency postulate You will need to know the reasons we can justify that triangles are similar. List them here: __AA_______ ___SAS_______ ____SSS______ Which reason could we use to justify these triangles similar? AA. Note that β πΆπΈπ· β β π΄πΈπ΅ because they are vertical. Write the similarity statement here: βπΆπΈπ·~βπ΄πΈπ΅ You will need to know the properties of special quadrilaterals. List them here: 1. Parallelogram: quadrilateral with both pairs of opposite sides congruent and parallel; opposite angles are congruent; diagonals bisect each other 2. Rectangle: parallelogram with all angles 90 degrees, diagonals are congruent 3. Rhombus: parallelogram with all sides congruent; diagonals are perpendicular; diagonals bisect opposite angles 4. Square: rectangle with all sides congruent; rhombus with all angles 90 degrees; has all properties of parallelograms, rhombi and rectangles You will need to know the formula for finding slope of a line given two points AND you will need to know how to use to solve problems. Given two points (π₯1 , π¦1 ) πππ (π₯2 , π¦2 ) π= πππ π π¦2 β π¦1 = ππ’π π₯2 β π₯1 To find a line parallel to this line, the slope must be the same, but the y-intercept must be different. To find a line perpendicular to this line, the slope must be a negative reciprocal compared to the original slope. Practice: Given the points (1, 2) and (-1,-1) write an equation for a line parallel to this line. Slope is 3/2. A parallel line could be y = 1.5X + 2. Note the y-intercept could be any number except ½ since that is the intercept of the original line. Now write the equation of a line perpendicular to this line. Slope of perpendicular must be -2/3. A perpendicular line could be y = (-2/3)X +1. Note the y-intercept could be anything. You will need to know the special triangle segments and points of concurrency on page 339. You also need to know whether the points of concurrency can occur on the exterior of a triangle. Congruence Transformations: page 296 Reflection translation rotation The above terms are all congruence transformations. This means that while the position of the image may change, the two figures remain congruent. When two polygons are congruent their corresponding parts are all congruent. Is dilation a congruence transformation? Why or why not? No it is not because while the angles remain congruent, the length of the sides may change. This means that all corresponding parts may no longer be congruent. Is this dilation an enlargement or a reduction? This is an enlargement What is the scale factor? Scale factor is 2 Is βπ΄π΅πΆ~βπ΄β²π΅β²πΆβ²? Yes because the same scale factor applies Given that L1 is parallel to L2: 1. Name all pairs of corresponding angles: a & aβ ; b & bβ ; c & cβ ; d & dβ 2. Name all pairs of alternate interior angles: c & aβ ; d & bβ 3. Name all pairs of alternate exterior angles: b & dβ ; a & cβ What is the difference between the Alternate Interior Angles Theorem and the Converse of the Alternate Interior Angles Theorem? Alternate Interior Angles Theorem states that if lines are parallel & cut by a transversal, then alternate interior angles are congruent. The Converse states that if alternate interior angles are congruent, then the lines are parallel. Given that the lines are parallel, which theorem would we use to show that alternate interior angles are congruent? When we know the lines are parallel we use the Alternate Interior Angles Theorem to show the angles are congruent. List all pairs of vertical angles in the diagram above. What is special about ALL vertical angle pairs? Vertical angles are ALWAYS congruent. Vertical angle pairs above are: β π β β π; β πβ² β β πβ²; β πβ² β β πβ²; β π β β π You will need to know the following constructions. Practice in this packet. Bring questions and concerns to class. Bisect a Segment page 30 Bisect an Angle page 40 Perpendicular through a point not on the line page 55 bottom of the page Find X in each of the figures below: (5π₯ + 4) + (π₯ β 2) + (3π₯ + 7) = 180 9π₯ + 9 = 180 9π₯ = 171 π₯ = 19 π₯ = 180 β 113 π₯ = 67 2π₯ β 45 = π₯ + 30 π₯ β 45 = 30 π₯ = 75