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Chapter 6 Rational Expressions and Equations Section 6.1 Multiplying Rational Expressions HW #6.1 Pg 248 1-37Odd, 40-43 Chapter 6 Rational Expressions and Equations Section 6.2 Addition and Subtraction 9. 10. 11. 12. 13. 14. 15. 16. 9. 13. 11. 10. 14. 15. 12. 16. LOGICAL REASONING Tell whether the statement is always true, sometimes true, or never true. Explain your reasoning. 1. The LCD of two rational expressions is the product of the denominators. • Sometimes 2. The LCD of two rational expressions will have a degree greater than or equal to that of the denominator with the higher degree. • Always Simplify the expression. 17. 18. 19. 20. HW #6.2 Pg 253-254 3-30 Every Third Problem 31-45 Odd Chapter 6 Rational Expressions and Equations 6.3 Complex Rational Expressions HW 6.3 Pg 258 1-23 Odd, 26-28 HW Quiz 6.3 Thursday, May 4, 2017 f ( x h) f ( x ) 1 Evaluate for f ( x) h x Chapter 6 Rational Expressions and Equations 6.4 Division of Polynomials • Do a few examples of a poly divided by a monomial • Discuss the proof of the remainder theorem HW #6.4 Pg 262 1-25 Odd, 26-32 Chapter 6 Rational Expressions and Equations Section 6.5 Synthetic Division Part 1 Dividing using Synthetic Division Objective: Use synthetic division to find the quotient of certain polynomials • Algorithm – A systematic procedure for doing certain computations. • The Division Algorithm used in section 6.4 can be shortened if the divisor is a linear polynomial – Synthetic Division Part 1 Dividing using Synthetic Division EXAMPLE 1 To see how synthetic division works, we will use long division to divide the polynomial 2 x 3 x 2 3 by x 3 Dividing Polynomials Using Synthetic Division Synthetic Division There is a shortcut for long division as long as the divisor is x – k where k is some number. (Can't have any powers on x). Set divisor = 0 and 3 2 1 x 6 x 8x 2 solve. Put answer here. x3 x + 3 = 0 so x = - 3 -3 1 6 8 -2 up3these Bring number down below Addupthese line up - 3 firstAdd - 9theseAdd Multiply Multiply these these and and 2 +3 x - 1 This is the remainder 1 x 1 put answer put answer above line above line Put variables back in (one was of divided outthe in Sonext the Listanswer all coefficients is: (numbers in xfront x's) and in in next process so first number is one less power than 2 top. If a term is missing, put in a 0. constant along the column column original problem). 1 x 3x 1 x3 Let's try another Synthetic Division Set divisor = 0 and solve. Put answer here. 4 1 0 x3 0x 1 x 4x 6 4 2 x4 x - 4 = 0 so x = 4 0 -4 0 6 up48 Bring number down these below Add upthese line Add up these up 4 firstAdd 16theseAdd 192 Multiply Multiply Multiply these these and and 3 + 4 x2 + 12 x + 48 198 This is the these and 1 x put answer put answer remainder put answer above line above line Now put variables back in (remember one x was above lineanswer Sonext the List all coefficients is: (numbers in front of x's) and the in in next divided out 3in process2so first number is one less in next constant along the top. Don't forget the 0's for missing column column power than original problem so x3). column terms. 198 x 4 x 12 x 48 x4 Let's try a problem where we factor the polynomial completely given one of its factors. 4 x 3 8 x 2 25 x 50 -2 4 factor : x 2 You want to divide the factor into the polynomial so set divisor = 0 and solve for first number. 8 -25 -50 up Bring number down below Addupthese line up - 8 firstAdd 0theseAdd 50these Multiply Multiply these No remainder so x + 2 these and and 2 4 x + 0 x - 25 0 put IS a factor because it put answer answer above line divided in evenly above line Put variables back in (one x was divided outthe in Sonext the Listanswer all coefficients is the divisor (numbers times in thefront quotient: of x's) and in in next process sothe first number is one less power You could check this byIf a term constant along top. is missing, putthan in a 0. column 2 column original problem). multiplying them out and getting original polynomial x 24 x 25 HW #6.5 Pg 265 1-19 . . . And Why To solve problems using rational equations A rational equation is an equation that contains one or more rational expressions. These are rational equations. To solve a rational equation, we multiply both sides by the LCD to clear fractions. Multiplying by the LCD Multiplying to remove parentheses Simplifying 2 x= 3 120 x=11 The LCD is x - 5, We multiply by x - 5 to clear fractions 5 is not a solution of the original equation because it results in division by 0, Since 5 is the only possible solution, the equation has no solution. y = 57 No Solution The LCD is x - 2. We multiply by x - 2. The number -2 is a solution, but 2 is not since it results in division by O. The solutions are 2 and 3. e. x = 3 f. x = -3, 4 g. x = 1, -½ h. x = 1, -½ This checks in the original equation, so the solution is 7. x=7 x = -13 HW #6.6 Pg 269 1-25 Odd, 26-34 Warm Up Solve the following equation knows he canmower mow IfTom Perry getsthat a larger a golf in mow 4 hours. so thatcourse he can theHe also knows thatinPerry takes 5 course alone 3 hours, hourslong to mow same how will itthetake Tom course. Tom complete and Perry tomust complete the the together? job in 2! hours. Can he job and Perry get the job done in time? How long will it take them to complete the job together? Solving Work Problems If a job can be done in t hours, then 1/t of it can be done in one hour. This is also true for any measure of time. Objective: Solve work problems using rational equations. Tom can mow a lawn in 4 hours. Perry can mow the same lawn in 5 hours. How long would it take both of them, working together with two lawn mowers, to mow the lawn? UNDERSTAND the problem Data: Tom takes 4 hours to mow the lawn. Perry takes 5 Question: How long will it take hours to mow the lawn. the two of them to mow the lawn together? Tom can do 1/4 of the job in one hour Perry can do 1/5 of the job in one hour Objective: Solve work problems using rational equations. Tom can mow a lawn in 4 hours. Perry can mow the same lawn in 5 hours. How long would it take both of them, working together with two lawn mowers, to mow the lawn? Develop and carryout a PLAN Translate to an equation. Let t represent the total number of hours it takes them working together. Then they can mow 1/t of it in 1 hour. Tom can do 1/4 of the job in oneTogether hour they can do 1/t of the job in one hour Perry can do 1/5 of the job in one hour 1 1 1 4 5 t Objective: Solve work problems using rational equations. Tom can mow a lawn in 4 hours. Perry can mow the same lawn in 5 hours. How long would it take both of them, working together with two lawn mowers, to mow the lawn? knows he canmower mow IfTom Perry getsthat a larger a golf in mow 4 hours. so thatcourse he can theHe also knows thatinPerry takes 5 course alone 3 hours, hourslong to mow same how will itthetake Tom course. Tom complete and Perry tomust complete the the together? job in 2! hours. Can he job and Perry get the job done in 1 long 1 will it take time?1 How 3 t them4to complete the job together? 5 t = 1 hours 12 2 t 2 hours 5 Objective: Solve work problems using rational equations. At a factory, smokestack A pollutes the air twice as fast as smokestack B.When the stacks operate together, they yield a certain amount of pollution in 15 hours. Find the time it would take each to yield that same amount of pollution operating alone. 1/x is the fraction of the pollution produced by A in 1 hour. 1/2x is the fraction of the pollution produced by B in 1 hour. 1/15 is the fraction of the total pollution produced by A and B in 1 hour. 1 1 1 + = x 2x 15 Objective: Solve work problems using rational equations. A 32 hours,B 96 hours An airplane flies 1062 km with the wind. In the same amount of time it can fly 738 km against the wind. The speed of the plane in still air is 200 km/h. Find the speed of the wind. Objective: Solve motion problems using rational equations. r = 36 km/h Objective: Solve motion problems using rational equations. Try This d. A boat travels 246 mi downstream in the same time it takes to travel 180 mi upstream. The speed of the current in the stream is 5.5 mi/h. Find the speed of the boat in still water. a. 35.5 mi/h e. Susan Chen plans to run a 12.2 mile course in 2 hours. For the first 8.4 miles she plans to run at a slower pace, then she plans to speed up by 2 mi/h for the rest of the course. What is the slower pace that Susan will need to maintain in order to achieve this goal? e. about 5.5 mi/h Try This Jorge Martinez is making a business trip by car. After driving half the total distance, he finds he has averaged only 20 mi/h, because of numerous traffic tie-ups. What must be his average speed for the second half of the trip if he is to average 40 mi/h for the entire trip? Answer this question using the following method. 1. Let d represent the distance Jorge has traveled so far, and let r represent his average speed for the remainder of the trip. Write a rational function, in terms of d and r, that gives the total time Jorge’s trip will take. Try This Jorge Martinez is making a business trip by car. After driving half the total distance, he finds he has averaged only 20 mi/h, because of numerous traffic tie-ups. What must be his average speed for the second half of the trip if he is to average 40 mi/h for the entire trip? Answer this question using the following method. 2. Write a rational expression, in terms of d and r, that gives his average speed for the entire trip. Try This Jorge Martinez is making a business trip by car. After driving half the total distance, he finds he has averaged only 20 mi/h, because of numerous traffic tie-ups. What must be his average speed for the second half of the trip if he is to average 40 mi/h for the entire trip? Answer this question using the following method. 3. Using the expression you wrote in part (b), write an equation expressing the fact that his average speed for the entire trip is 40 mi/h. Solve this equation for r if you can. If you cannot, explain why not. HW #6.7 Pg 273 1-27 Odd, 29-33 PV T K We solve the formula for the unknown resistance r2. We solve the formula for the unknown resistance r2. HW #6.8 Pg 278 1-30 What you will learn 1. Find the constant and an equation of variation for direct and joint variation problems. 2. To find the constant and an equation of variation for inverse variation problems 3. To solve direct, joint, and inverse variation problems Objective: Find the constant of variation and an equation of variation for direct variation problems. Direct Variation Whenever a situation translates to a linear function f(x) = kx, or y = kx, where k is a nonzero constant, we say that there is direct variation, or that y varies directly with x. The number k is the Constant of Variation Objective: Find the constant of variation and an equation of variation for direct variation problems. The constant of variation is 16. The equation of variation is y = 16x. Objective: Find the constant of variation and an equation of variation for direct variation problems. Objective: Find the constant of variation and an equation of variation for joint variation problems. Joint Variation y varies jointly as x and z if there is some number k such that y = kxz, where k 0, x 0, and z 0. Objective: Find the constant of variation and an equation of variation for joint variation problems. EXAMPLE 2 Suppose y varies jointly as x and z. Find the constant of variation and y when x = 8 and z = 3, if y = 16 when z = 2 and x = 5. Find k y = kxz 16 = k(2)(5) 16 8 k 10 5 8 y xz 5 8 y 8 3 5 y 192 5 Objective: Find the constant of variation and an equation of variation for joint variation problems. Try This Objective: Find the constant of variation and an equation of variation for inverse variation problems. Inverse Variation y varies inversely as x if there is some number k such that y = k/x, where k 0 and x 0. Objective: Find the constant of variation and an equation of variation for inverse variation problems. EXAMPLE 3 Objective: Find the constant of variation and an equation of variation for inverse variation problems. EXAMPLE 3 Objective: Find the constant of variation and an equation of variation for inverse variation problems. Try This 1 30 Describe the variational relationship between x and z and demonstrate this relationship algebraically. 1. x varies directly with y, and y varies inversely with z. 2. x varies inversely with y, and y varies inversely with z. 3. x varies jointly with y and w, and y varies directly with z, while w varies inversely with z. The weight of an object on a planet varies directly with the planet’s mass and inversely with the square of the planet's radius. If all planets had the same density, the mass of the planet would vary directly with its volume, which equals 4 3 r 3 1. Use this information to find how the weight of an object w varies with the radius of the planet, assuming that all planets have the same density. 2. Earth has a radius of 6378 km, while Mercury (whose density is almost the same as Earth’s) has a radius of 4878 km. If you weigh 125 lb on Earth, how much would you weigh on Mercury? HW #6.9 Pg 283-284 1-32 Chapter 6 Review Two Parts Part 1 • • • • • Add/Subtract/Multiply/Divide Rational Expressions Solve Rational Equations Long Division/Synthetic Division Direct/Joint/Inverse Variation Challenge Problems Part 2 • • • • Work Problems Distance Problems Problems with no numbers Challenge Problems Simplify 32 x 64 x 24 x 4 4x 6 5 4 Simplify Simplify Simplify Simplify Simplify Simplify Simplify x 1 x 1 7 Solve Solve Divide Divide Compute the value of f x h f x h for 1 f x x2 Find the value of k if (x + 2) is a factor of x kx 5 x 6 3 2 HW # R-6 Pg 287-288 1-29