Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
CHEMISTRY 2012 HJH ROSSITA RADZAK CHAPTER 11: CARBON COMPOUND 1. Hydrocarbon – chemical compound containing carbon and hydrogen atom only. 2. Alkene – chemical compound containing carbon and hydrogen atom and at least one carbon-carbon double bond ( C = C ) 3. Isomers are molecules with the same molecular formula, but with different structural formula. Example: C4H10 – butane n-butane 2-methylpropane C6H12O6 Fermention C2H4Br2 C2H6 C2H5OH Hydroxyl -OH Br2 C2H5OH C2H5Br - CH2- CH2- CH3COOH Carboxyl -COOH Oxidation H2 C2H4 Double bond between C atoms, C=C + C2H4(OH)2 KMnO4/ H+, K2Cr2O7/ H+ KMnO4/ H , K2Cr2O7/ H+ H2O HX A d d i t i o n Esterification H2SO4 CH3COO C2H5 Ethyl ethanoate CnH 2n+ 2 , n = 1,2 alkane CnH2n , n = 2, 3 alkene CnH 2n+ 1 OH, n = 1, 2 alcohol CnH 2n+1 COOH , n=0,1.. Carboxylic acid KMnO4/H+ / K2Cr2O7/ H+ 1. C2H4 + [O] + H2O C2H4(OH)2 [ purple turns colourless] //[ orange turns green] 22 CHEMISTRY 2012 HJH ROSSITA RADZAK 2. CH3COOH + C2H5OH H 2SO4, cons CH3COO C2H5 + H2O H 3 PO4, 60 atm, 300 oC 3. C2H4 + H2O 4. C6H12O6 C2H5OH Yeast 2C2H5OH + 2CO2 Homologous series Alkane General formula Functional group CnH2n + 2 , n = 1,2.. Single covalent bond between carbon atoms. C- C Ethane Alkene CnH2n , n = 2.. Double covalent bond between carbon atoms. C=C Ethene Alcohols CnH2n + 1 OH, n = 1,2.. Hydroxyl group / - OH Ethanol Carboxylic acid CnH2n + 1 COOH, n = 0,1,2.. Carboxyl group , -COOH Ethanoic acid CH3COOH 23 Member , example CHEMISTRY 2012 HJH ROSSITA RADZAK 4. Your are required to prepare one namely ester by using ethanoic acid is one of the reactants. By using a namely alcohol, describe one experiment to prepare the ester. In your description include the chemical equation and observation involved. Ester: ethylethanoate Material: ethanol, etahanoic acid, water, concentrated sulphuric acid Apparatus: Boiling tube / test tube, Bunsen burner, test tube holder, beaker Procedure: 1. Pour 2 cm3 of ethanol into a boiling tube / test tube 2. Add 1 cm3 of ethanoic acid 3. Add 2 to 4 drops of concentrated sulphuric acid 4. Heat the mixture gently for about two minutes 5. Pour the mixture into a beaker containing water. Observation: Sweet/ pleasant / fruity smell // insoluble in water Chemical equation: CH3COOH + C2H5OH CH3COO C2H5 + H2O 4. Dehydration of alcohol Diagram of set up of apparatus 1. Complete and functional 2. Labels of set up of apparatus correct 24 CHEMISTRY 2012 HJH ROSSITA RADZAK Procedure: a) Place some glass wool in a boiling tube b) Use a dropper to add propan-1-ol to wet the glass wool. c) Clamp the boiling tube horizontally and placed unglazed porcelain chips in the mid section of the boiling tube. d) Heat the unglazed porcelain chips strongly. e) Then heat the glass wool gently to vaporize the propanol. f) [Description of the chemical test to the gas collected in the test tube.] Add 1 cm3 of bromine water and shake well. [Observation]: Reddish brown colour of bromine decolourised Or, Add 1 cm3 of acidified potassium manganate(VII) solution and shake well. [Observation]: Purple colour of potassium manganate(VII) solution decolourised Chemical equation: C3H7OH à C3H6 + H2O Industrial extraction of palm oil 25 CHEMISTRY 2012 HJH ROSSITA RADZAK 5. Table shows results of latex coagulation Procedure Propanoic acid (weak acid) is added to latex Latex is left under natural conditions Protein membranes - - Observation Latex coagulates immediately Latex coagulates slowly Rubber particles - Rubber molecules Explain why there is a difference in these observations Answer: 1. Acid ionizes in water to produce high concentration of / a lot of hydrogen ions 2. Hydrogen ions, H+ neutralize the negative charges on the protein membranes 3. The rubber particles collide and the protein membranes break 4. Rubber molecules are released and combine with one another and entangle. 5. The existence of bacteria in natural conditions 6. The growth of bacteria produce / lactic acid /weak acid / low concentration of H+ ions. 7. Due to the slow bacterial action, the coagulation of latex takes a longer time to occur. [Monomer of natural rubber: 2 – methylbuta-1,3- diene , C5H8 / isoprene ] Explain how to prevent coagulation of latex 1. Add ammonia solution 2. Ammonia solution contains / ionized to produce hydroxide ions , OH3. Hydroxide ions, OH- neutralized the hydrogen ions, H+ / acid produced by the bacteria 4. The rubber particles remain negatively charged and coagulation is prevented. 6. [Paper 3] Aim: To compare the elasticity / strength of vulcanised and unvulcanised rubber Problem statement: Does vulcanised rubber more elastic than unvulcanised rubber Hypothesis: Vulcanised rubber is more elastic than unvulcanised rubber Variable: Manipulated : vulcanised rubber and unvulcanised rubber Responding : length of rubber strip / elasticity Fixed : mass of weight, size of rubber Material and apparatus: Retort stand, bulldog clip, meter ruler, weight, vulcanised and unvulcanised rubber 26 CHEMISTRY 2012 HJH ROSSITA RADZAK Procedure: 1. Hang both rubber strips to the retort stand with bulldog clip. 2. Measure the initial length of both rubber strips and record. 3. Hang 50 g weight to the end of each rubber using bulldog clip. 4. Remove the weight and measure the length of both rubber strips and record.// 5. Record all the data obtained. Unvulcanised rubber Vulcanised rubber Result / Data Type of rubber vulcanised unvulcanised Initial length , cm Length after removal of weight , cm Compares and contrasts the properties of vulcanized rubber Vulcanized rubber Harder More elastic Stronger Can withstand higher temperature Less easily oxidized Does not become soft and sticky easily Elasticity Hardness Elasticity Tensile strength Resistance to heat Resistance to oxidation Effect of organic solvent Unvulcanised rubber Less harder Less elastic Weaker Cannot withstand higher temperature More easily oxidized Become soft and sticky easily Conclusion: 1. Vulcanised rubber is more elastic than unvulcanised rubber due to the presence of cross-linkage of sulfur atoms between the rubber molecules. Vulcanised rubber could return to its original length after removal of the weight. To prepare vulcanised rubber Rubber can be vulcanized by dipping natural rubber sheets into disulphur dichloride solution in methylbenzene or heated with sulphur. Note: Vulcanised rubber is more heat resistance due to the presence of cross-linkage of sulfur atoms increases the size of rubber molecules. Force of attraction between molecules will increase. 27 CHEMISTRY 2012 HJH ROSSITA RADZAK 7. Compare and differentiate between namely alkene and alkane Alkane ( hexane ) 1 2 3 4 5 6 Alkene ( hexene ) Hydrocarbon ( contain C and H atom) Low melting and boiling point Insoluble in water, soluble in organic solvent Cannot conduct electricity Density less than water Completely combustion produce CO2 + H2O 7 Saturated , single covalent bond, C-C Unsaturated , contain at least one double bond C=C 8 Unreactive – undergo substitution with halogen in the presence of sunlight / UV ray Reactive – undergo addition reaction( hydrogenation, halogenations, oxidation, polymerization, with halide, steam(hydration) 9 General formula , CnH2n+2 , n = 1,2 … , CnH2n , n= 2 … 10 Identify test 1. Combustion, burn less soot flame. (% of carbon per molecule is lower) Chemical tests 2. add bromine water , brown colour remains 3. add acidified KMnO4 , purple colour remains 1. More soot flame. ( % of carbon per molecule is higher). 2. decolorized brown bromine water 3. purple colour is decolourized 28