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Unit 2 Polynomial and Rational Functions Do Now Given the following function, f (x) 2x 5x 2 2 find f (2) f (0) f (2) Unit 2 Lesson 1 2.1 Quadratic Functions 2.2 Polynomial Functions Lesson Objectives In this lesson presentation, you will learn how to: define, sketch & analyze graphs of quadratic & polynomial functions. define and identify the vertex, minimum and maximum values of a quadratic& polynomial functions. use the LEADING COEFFICENT TEST to determine how a polynomial function rises or falls. identify the zeros of both of quadratic & polynomial functions. use the Intermediate Value Theorem to help identify the real zeros of a polynomial function. 2.1 Quadratic Functions a, b, and c are real numbers where a0 f (x) ax bx c 2 When graphed called a Parabola Axis of Symmetry – all parabolas are symmetric (line where it’s cut in half) Vertex – axis intersects the parabola If a is positive… opens up If a is negative… opens down f ( x) ax , a 0 f ( x) ax , a0 2 2 Minimum: (0,0) Maximum: (0,0) Axis of Symmetry for both: x=0 f (x) ax bx c 2 f ( x) ax bx c, a 0 2 If a is positive…opens up f ( x) 2 x 2 x 1 2 Vertex is lowest point. Axis of symmetry f ( x) ax 2 bx c, a0 If a is negative…opens down f ( x) x 2 Vertex is highest point. Base function or squaring function. f (x) ax 2 How does each function change? 1) f ( x) x 2 5 2) f ( x) x 5 3) f ( x) 5 x 2 Up 5 units 2 Left 5 units Get’s skinny Summarize: How do they change? If c>0, then move up. If c<0, then move down. If (x+#), then move left. If (x-#), then move right. If “a” is integer, then get skinny. If “a” is fraction, then get wide. Practice Given the following functions, graph each on your graph paper and identify the following: a) Domain: b) Range: c) Decreasing on: d) Increasing on: e) Turn up or down: Example 1. f ( x) x 6 Example 2. f ( x) ( x 2)2 4 2 Practice Given the following function, identify the following: Domain: Range: Decreasing on: Increasing on: Turn up or down: Standard Form of a Quadratic f ( x ) a ( x h) k 2 Vertex is (h, k) and a0 Axis is the vertical line x = h If a < 0, then the parabola opens down If a > 0, then the parabola opens up Identify the vertex of a Quadratic Given a function f ( x) 2 x 8 x 5 2 Write the function in Standard Form by completing the square to find the vertex. f ( x) 2 x 2 8 x 5 Example 1. 2( x 2 4 x) 5 *Factor out the 2 2( x 4 x 4 4) 5 *b=4, add & 2( x 2 4 x 4) 2(4) 5 *Regroup terms 2 2( x 2) 3 2 The vertex is (-2,-3) subtract (4/2)2 =4 *Write in Standard Form. Identify the Minimum & Maximum Values Given a function f (x) ax 2 bx c b You can find the minimum if a>0, x 2a b You can find the maximum if a<0 x 2a Example: Given the following quadratic equation find coordinates of the relative minimum or maximum point. f ( x) 4 x 2 24 x 2 2.2 Graphs of Polynomial Functions Features of Polynomial Functions: Continuous Smooth Curves NOT Features of Polynomial Functions: NOT Continuous NOT Smooth Functions with 1 degree are Linear. Functions with 2 degrees are Quadratic. Functions with 3rd or greater are Polynomial. f ( x) x 2 f ( x) x 3 Functions with an even degree will look like our quadratics. (e.g.) 4 8 f ( x) x f ( x) x Functions with an odd degree will look like our 11 5 cubic. (e.g.) f ( x) x f ( x) x A polynomial of the nth degree has the form: f ( x) an x an 1 x n n 1 ... a2 x a1 x a0 2 n is a positive integer The greater the value of n the flatter the graph near (0,0) The Leading Coefficient Test A functions ability to rise or fall can be determined by the functions degree (even or odd) and by it’s leading coefficient. f ( x) an x an 1 x n n 1 ... a2 x a1 x a0 2 When n is odd: When an 0 f ( x) as f ( x) as x x When n is odd: When an 0 f ( x) as x f ( x) as x When n is even: When an 0 f ( x) as f ( x) as x x When n is even: When an 0 f ( x) as f ( x) as x x Independent Practice: Take a minute to see if you can develop four different polynomial functions that would behave as we just discussed. Write down your functions and check your work in you calculator. Practice Use the Leading Coefficient Test to determine the right and left side behavior of the function. Example 1. Example 2. f ( x) x 5 x 4 4 2 f ( x) x x 5 Finding Zeros of Polynomial Functions Set the function equal to zero and factor. 3 2 (e.g) f ( x) 2 x 4 x 16 x 0 2 x 4 x 16 x 2 0 2 x( x 2 x 8) 0 2 x( x 2)( x 4) 3 2x 0 x0 2 x2 0 x2 x40 x 4 Check on the graphing calculator. 2.3 Real Zeros of Polynomial Functions Disclaimer: There are many ways for us to determine the zeros of a polynomial function. Please be patient and as the lesson progresses through the various topics the math should become easier for you! Topics will include: *Long Division of Polynomials *Synthetic Division *Remainder & Factor Theorems *Rational Zero Test *Descartes's Rule of Signs Long Division of Polynomials f ( x) 6 x 19 x 16 x 4 3 2 Graph the function to identify a zero that is an integer. You can see that x=2 is a zero, as a result (x-2) is a factor of the polynomial. We will divide the entire function by (x-2). 6x 7x 2 2 2 Divide! 1) Multiply: 6 x 2 ( x 2) 2 2) Subtract. x 2 (6 x 19 x 16 x 4) 3 6 x 12 x 3 7 x 16 x 3) Multiply: 7 x( x 2) 7 x 14 x 4) Subtract. 2 2 2x 4 2x 4 0 5) Multiply: 2( x 2) 6) Subtract. Now we know that: 6 x 19 x 16 x 4 ( x 2)(6 x 7 x 2) 3 2 2 So we factor and solve for zero! 0 ( x 2)(6 x 7 x 2) 0 ( x 2)(2 x 1)(3x 2) 2 0 x2 x2 0 2x 1 1 x 2 We have three x-intercepts at: 0 3x 2 2 x 3 1 2 x 2, x , x 2 3 Synthetic Division (the shortcut to long division) We will use Synthetic Division to divide the following: x 10 x 2 x 4by( x 3) 4 Solve to get divisor: 2 Leading coefficients (NOTE: zero because there is no x cubed. x3 0 -3 1 1 0 -10 -3 9 -3 -1 -2 4 3 -3 1 1 Remainder: 1 1) Add terms in first column, and multiply the result by -3. 2) Repeat this process until the last column. -3 1 1 Quotient: 0 -3 -3 -10 9 -1 -2 4 3 -3 1 1 x 3x x 1 3 2 Remainder: 1 ( x 3) original problem = quotient + remainder x 10 x 2 x 4 1 3 2 x 3x x 1 ( x 3) ( x 3) 4 2 Remainder & Factor Theorems The Remainder Theorem (the remainder from synthetic division): If a polynomial f ( x ) is divided by x-k, the remainder is r f ( k ) . Practice 1. Use the Remainder Theorem to evaluate the given function at x = -2. f ( x) 3 x 8 x 5 x 7 3 2 Start by doing synthetic division! -2 3 3 8 5 -6 -4 2 1 -7 -2 -9 Remainder is -9, f (2) 9 . (-2,-9) is a point on the graph of our polynomial. Check by substituting in -2 into our original function. Rational Zero Test If the polynomial f ( x) an x an 1 x n n 1 ... a2 x a1 x a0 2 has integer coefficients, every rational zero of f has the form: p Rational Zero q p: factor of constant term q: factor of leading coefficient Example 1. Find the rational zero(s) of the given function. f ( x) x x 1 3 p 1 q 1 The factors of 1 are +1 and -1 Therefore: Rational Zeros: +1 or -1 Test each possible zero algebraically. f (1) (1) (1) 1 1 3 f (1) (1) (1) 1 3 3 Since -1, and 3 are not zero, this polynomial does not have a rational zero. If the leading coefficient is not 1 our possible zeros will increase significantly. *We will use our graphing calculators to plot the zeros for these situations. If you would like to see a problem working out please reference pg.119 in your textbook. Practice. Using your graphing calculator find the rational zeros of the following function. f ( x) 2 x 3 x 8 x 3 3 2 Variation in sign: Two consecutive (nonzero) coefficients have opposite signs. Example: Do the given functions have a difference of signs? + to + + to + f ( x) 3 x 2 x 6 x 9 3 2 NO!!! + to + + to - + to - f ( x) 7 x 8 x 6 x 5 3 2 - to + YES!!! Descartes's Rule of Signs Let f ( x) an x an 1 x n n 1 ... a2 x a1 x a0 2 Be a polynomial with real coefficients and a0 0 . 1. The number of positive real zeros of f is either equal to the number of variations in sign of f(x) or less than the number by an even integer. 2. The number of negative real zeros of f is either equal to the number of variations in sign of f(-x) or less than the number by an even integer. Example. Describe the possible real zeros of the given function. + to 3 + to + f ( x) 7 x 8 x 6 x 5 2 - to + - to 3 This polynomial has either two or no positive real zeros. - to + f ( x) 7 x 8x 6 x 5 2 - to - This one negative real zeros. 2.4 The Imaginary Unit i i 1 If a and b are real numbers: a + bi is a complex number in standard form If b = 0, a +bi = a If b ≠ 0, a +bi is an imaginary number If b ≠ 0, bi is a pure imaginary number. Addition & Subtraction with Complex Numbers Just like combining like terms in Algebra! Example1: Solve / Simplify. (5 - i) + (9 + 5i) Example2: Solve / Simplify. 10 + (3 + 6i) - (-2 + 2i) Multiplication with Complex Numbers Remember: i Example1: Multiply. Example 2: Multiply. 2 25 1 81 (3 + 2i)(5 + 4i) Complex Conjugates When two complex numbers are multiplied and their solution is a real number. (remember the difference of squares?) Example of Complex Conjugates: (5 + 2i)(5 – 2i) Find the complex conjugate for the following complex number and multiply. (7 - 4i) Division with Complex Numbers Example1: Write the following quotient in standard form. (2 3i) (4 2i) 2.5 The Fundamental Theorem of Algebra The Fundamental Theorem of Algebra If f(x) is a polynomial of degree n, where n > 0, the f has at least one zero in the complex number system. Linear Factorization Theorem If f(x) is a polynomial of degree n where n > 0, f has precisely n linear factors. f ( x) an ( x c1 )( x c2 ) ( x cn ) Where c1 , c2 , , cn are complex numbers. Example 1. Using the Ft of A and LFT, prove that the given 3rd degree polynomial function does indeed have three exact zeros in the complex number system. f ( x) x 9 x 3 Factor completely. Find your zeros. x 9 x x( x 9) 3 2 x( x 3i )( x 3i ) 0 x0 x 3i x 3i Conjugate Pairs (think: difference of squares) (a bi )and (a bi ) FACT: Complex zeros occur in conjugate pairs! (think about the last example!) If a bi is a zero of a function, then the conjugate a bi is also a zero. Example 2. Using you knowledge of the FTofA, LFT, and conjugate pairs find all of the zeros of the given function if 1 + 3i is a zero. f ( x) x 3x 6 x 2 x 60 4 3 2 If 1 +3i is a zero we know that 1 – 3i is a zero. ∴ If x = (1 + 3i), then x – (1 + 3i) is a factor. Multiply. Distribute. x (1 3i) x (1 3i) x 1 3i x 1 3i Multiply. ( x 1) 3i( x 1) 3i ( x 1) 2 9i 2 ( x 1) 9i ( x 1)( x 1) 9i 2 2 2 ( x 2 x 1) 9(1) x 2 x 10 2 2 Now, use long division to divide. x 2 x 10 x 3x 6 x 2 x 60 2 4 3 2 ( x 2 x 10)( x x 6) 2 2 Factor! Remember this… x 1 3i x 1 3i ( x 3)( x 2) x 3, x 2 Please practice this following problems with you partner so that I can walk throughout the room and provide help and assistance as needed. Pg.141 #13, & 47 (use the answers in the back of the book for help!) 2.6 Rational Functions & Asymptotes Rational Function N ( x) f ( x) D( x) Remember: D(x) ≠ 0 As f(x) approaches D(x) = 0 the function will increase or decrease rapidly! Reciprocal Function - most basic rational function. 1 f ( x) x We know that x ≠ 0, so… Use your calculator to complete the following chart as x gets closer to 0 f(x) f(x) x x -1 -.5 -.1 -.01 -.001 ∴ →0 1 .5 .1 .01 .001 ∴ →0 Complete the following for the rational function. Domain: (-∞,0) and (0, ∞) Range: (-∞,0) and (0, ∞) Increasing: NOT Increasing! Decreasing: on(-∞,0) and (0, ∞) Zeros/Intercepts: NONE! Even/Odd/ Neither: Odd Vertical asymptote: y-axis Horizontal asymptote: x-axis Asymptotes Vertical Asymptotes If f(x) → a OR f(x) → -∞ x = a (line) as x→a (from the right or left) Horizontal Asymptotes If f(x) → b OR f(x) → -∞ y = b (line) as x→a Finding Asymptotes for a rational function n 1 N ( x) an x an1 x ... a2 x a1 x a0 f ( x) m m 1 2 D( x) bm x bm1 x ... b2 x b1 x b0 n 2 Vertical asymptotes - at the zeros of D(x) Finding Asymptotes for a rational function n n 1 2 a x a x ... a x a1 x a0 N ( x) n n 1 2 f ( x) m m 1 2 D( x) bm x bm1 x ... b2 x b1 x b0 Horizontal asymptotes – compare degrees of both N(x) and D(x) *If n < m, the x-axis (y=0) is an asymptote *If n > m, there is NO horizontal asymptote an *If n = m, then the line y is an asymptote bm (an and bm are leading coefficinets.) Practice 1. Find all asymptotes of the function. 2 x2 f ( x) 2 x 1 Find vertical asymptotes by setting denominator equal to zero. 2 x 1 0 ( x 1)( x 1) 0 x 1 x 1 We have two vertical asymptotes at x = -1 and x = 1 Practice 1. Find all asymptotes of the function. 2 x2 f ( x) 2 x 1 Find horizontal asymptotes by checking exponents. Since n = m, we look at the leading coefficients. 2 2 1 y 2 We have one horizontal asymptote at y = 2 Practice 2. The following function will have two horizontal asymptotes. x 10 f ( x) , x 0 x2 1 y 1 1 1 x 10 f ( x) x 2 x 10 f ( x) , x 0 x 2 1 y 1 1 1 We have two horizontal asymptotes at y = 1 for x values less than zero. y = -1 for x values greater than or equal to zero 2.7 Graphs of Rational Functions WHAT DO I DO???? 1. Simplify f, if possible. 2. Find & plot y-intercept *IF ANY?* evaluate f(0) 3. Find zeros *IF ANY?* of numerator solve N(x) = 0 and plot the y-intercepts WHAT DO I DO? Continued… 4. Find zeros *IF ANY?* of denominator solve D(x) = 0 sketch the vertical asymptote(s) 5. Find & sketch the horizontal asymptote(s) *IF ANY?* 6. Plot at least one point between each xintercept and vertical asymptote. 7. Draw smooth curves between the points and asymptotes. Practice 1. Using your knowledge from Chapter 2, follow the previously mentioned steps to sketch a graph of the following rational function by hand. (NO CALCULATORS!) x f ( x) Simplify for later… x x2 2 x f ( x) ( x 1)( x 2) 0 0 Find the y-intercept: f (0) 2 0 02 Find zeros for numerator N(x) = 0 x f ( x) 2 N ( x) x x x2 y-intercept: (0,0) x 0 x-intercept: (0,0) Find vertical asymptotes D(x) = 0 x f ( x) D( x) ( x 1)( x 2) ( x 1)( x 2) 0 ( x 1)( x 2) x 1 x2 Vertical asymptotes are at x = -1 and x = 2 Check the degree of the numerator and denominator to determine if there are horizontal x asymptotes. f ( x) x x2 2 The degree the numerator is less than the degree of the denominator so we have a Horizontal asymptote at y = 0 f(x) x Complete the following to determine other points. -3 -1 -.5 1 2 3 Since we have found the following, sketch a graph. y-intercept: (0,0) x-intercept: (0,0) Vertical Asymptotes: x = -1 and x = 2 Horizontal Asymptotes: y = 0 Extra Points: x f(x) -3 -1 -.0 UND -.5 1 2 .4 .5 UND 3 .75 Slant Asymptotes - if the degree of the numerator is one degree larger than the denominator then you have a slant asymptote. WE USE LONG DIVISON TO HELP US! Example 1. Find the slant (oblique) asymptote. x x2 f ( x) x 1 2 x x 1 x x 2 2 x x 02 2 2 x x 1 When we divide, we end up with x, the line y = x is a oblique asymptote. 2.8 Exploring Data: Quadratic Models Sometimes a linear model is not always the best for a grouping of data... (see pg.161 for more than one example) Given the following set of data, we will plot a scatter plot and use the QuadReg function in our calculators to determine a quadratic equation of the curve. The following table shows monthly average high temperature for Yorktown, VA Month Avg. Monthly Temp. January 47° February 51° March 59° April 69° May 76° June 84° July 87° August 85° September 80° October 70° November 61° December 51° Input the data into L1 & L2. Use 1,2,3,4… to represent the months of the year. Buttons: *Stat *Select EDIT *L1 = Months *L2 = Temperatures Month Avg. Monthly Temp. January 47° February 51° March 59° April 69° May 76° June 84° July 87° August 85° September 80° October 70° November 61° December 51° Buttons: *2nd Function “y=” (Stat Plot) Buttons: *Enter, turn ON, & select mark Buttons: *Window change your widow so that it will fit our data Buttons: *Graph Buttons: *#5 QuadReg Buttons: *Stat, right one to Calc