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Name_________________________________ Algebra 2 Lesson 2-5 Absolute Value Functions and Graphs An absolute value function is a function that contains an absolute value expression. This function is also a parent function that has the form of π¦ = π₯ . Graphed, it has a distinctive βVβ shape with a minimum point or maximum point depending on the expression. The following examples are variations of absolute value functions (more next section). Examples: π π₯ = π₯ + 3 π π₯ = π₯+1 β4 π π₯ = β2 π₯ + 6 An absolute value function graph is characterized by a v-shape. When we throw in other numbers wh Like all other parent functions, absolute value functions can have variations that move left, right, up, down. compress, stretch, or a combination of several variations. When absolute value functions move up or down (translate), they will have the form of π π = π + π π π₯ = π₯ β3 π π₯ = π₯ +2 Absolute value functions that move left or right have the form: π π = ππ + π + π. π π₯ = π₯+3 π π₯ = π₯β4 +2 π Notice the βvertexβ, the maximum or minimum point, of the graphs above is located at the point (β π , π) . page 2 of 2 Algebra 2 Lesson 2-5 Absolute Value Functions and Graphs Important: the vertex may also be found by understanding that the vertex occurs when the contents inside the absolute value equals 0. So for example: π π₯ = π₯β4 +2: 1. set the contents of the absolute value equal to zero. 2. Solve for s π₯ β 4 = 0, π₯=4 3. Here at π₯ = 4 the absolute value goes to zero π¦ = 4β4 +2 4. Now plug in π₯ = 4 into the original equation and π¦=2 solve for y Vertex is at (4,2) graph and verify! Graphing 1. Graphing an absolute value function can be accomplished using the tried and true method by selecting x or y values and solving the equation for the remaining variable and graph the x-y coordinates. 2. Absolute value functions can also be graphed on a graphing calculator: 1. Y= 2. MATH β NUM <enter> 3. type equation 4. ZOOM 5 your graph should appear! 3. An absolute value function may also be graphed by using the two linear equation method, and yes, you are expected to understand and know this method!: Solve: π¦ = π₯β3 +5 1. isolate the absolute value (get it by itself) on the π¦β5 = π₯β3 right side of the equal sign 2. using the definition of absolute value write 2 when π₯ β 3 β₯ 0 when π₯ β 3 β€ 0 equations: CASE 1 CASE 2 CASE1 β βas isβ and CASE 2 β bring down and take βas-isβ negative of abs. val. the negative of the absolute value. π¦β5=π₯β3 π¦ β 5 = β(π₯ β 3) 3. solve for y π¦ = π₯ + 2 π¦ β 5 = βπ₯ + 3 4. graph each equation for the appropriate domain π¦ = βπ₯ + 8 (remember the domain comes from the definition) domains: π₯β₯3 π₯β€3 domains are also found by solving each equation for x The key is to understand that the βstuffβ inside the abs. π₯ β 3 β₯ 0, πππ π₯ β 3 β€ 0 val. may be negative or positive, such as: 5 = 5 πππ β5 = 5. So, for our example π₯ β 3 = + # πππ π₯ β 3 = β #, πππππ π‘ππ β₯ 0 πππ β€ 0 for the domains. You will need to be comfortable using each of the above described methods.