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6.1 AND 6.2: LINEAR SYSTEMS OF EQUATIONS; NON-LINEAR SYSTEMS OF EQUATIONS
A system of equations is two or more equations in two or more variables. A
solution of a system is an
ordered pair that satisfies each equation in the system. Finding the set of all
solutions is called solving the
system of equations.
Example 1
Determine whether  4,  1 is a solution of the system
x  2 y  2

x  2 y  6
6
4
x+2y=2
-10
2
-5
5
-2
10
(4, -1)
-4
x-2y=6
-6
-8
As you can see from the graph, the two lines appear to intersect at the point 
4,  1 . Therefore,
it is reasonable to guess that  4,  1 is a solution of the system.
If we don’t have use of a graphing utility, we should be able to check a
solution without
graphing. Here’s how.  4,  1 indicates that x = 4 and y = -1. Substitute these
values into
each equation. If they work for both equations, then the point is a solution of
the system.
x  2 y  2   4   2  1  4  2  2
x  2 y  6   4   2  1  4  2  6
Using the Substitution Method
1. Solve one of the equations for one variable in terms of the other.
2. Substitute the expression found in Step 1 into the other equation to obtain
an equation in one
variable.
3. Solve the equation obtained in Step 2.
4. Back-substitute the variable obtained in Step 3 into the expression obtained
in Step 1 to find the
value of the other variable.
5. Check that the solution satisfies each of the original equations.
Example 2
3, 1
Solve the system:
x  y  4

x  y  2
Example 3
3,  4
Solve the system:
 x  y  1

4 x  3 y  24
Linear Systems Having No Solutions or Infinitely Many Solutions
The following three possibilities exist when graphing two lines:
-10
6
6
6
4
4
4
2
2
2
-5
5
10
-10
-5
5
10
-10
-5
5
-2
-2
-2
-4
-4
-4
-6
-6
-6
-8
-8
-8
10
The two lines intersect
at exactly one point.
The two lines
are parallel.
The two lines
are identical.
One solution
System is CONSISTENT
No Solution
System is INCONSISTENT
Equations are INDEPENDENT
Infinitely Many Solutions
Equations are
DEPENDENT
Example 4
Solve the system:
6  2x

y 
3

6 x  9 y  12
Example 5
Solve the system:
 y  3  2x

2 x  y  3
Solving a nonlinear system by the substitution method
Example 6
Solve by substitution:
 x 2  2 y  10
.

3x  y  9
Graphically, here is the picture of what’s happening:
8
6
4
x2=2y+10
(4, 3)
2
-4
-2
2
4
6
8
10
-2
-4
-6
(2, -3)
3x-y=9
-8
-10
-12
From the graph, you can see that the parabola and the line intersect in two
points: (2, -3) and (4, 3).
Therefore, it would seem that there are two solutions to this system. Let’s see
how to do this algebraically.
Example 7
Solve by the substitution method:
x2  y  1
4 x  y  1
Here’s the graph:
35
30
25
4x-y=-1
x2=y-1
20
15
10
5
-10
-5
5
10
Example 8
Solve by the substitution method:
 y  x 2  14 x  49

 x  y  13
Here’s the graph:
18
16
14
12
10
8
6
4
2
-10
-5
5
-2
-4
10
15
20
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