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Chapter 25 Current & Resistance Electric Current ● ● Electric current is the rate of flow of charge through some region of space (or a wire). The SI unit of current is the ampere (A) ● ● 1A=1C/s The symbol for electric current is I dQ I= dt Direction of Current ● ● ● The charges passing through the area could be positive or negative or both It is conventional to assign to the current the same direction as the flow of positive charges Convention: direction of current flow is opposite the direction of the flow of electrons #thanksbenfranklin Charge Motion in a Conductor ● Electric field forces cause the electrons to move in the wire and create a current • Most electron motion in a conductor is random, caused by collisions. • The net “drift velocity” is very slow. Current and Drift Speed ̣ ̣ ̣ ̣ Wire of cross-section area A n = charge carriers per Volume nAΔx = number of charges that move through A in time Δt Total charge is ΔQ = (nAΔx)e Drift Velocity dQ I= = n q Avd dt Electron drift is SLOW Current: I ' 1 A = 1 C/s Density of electrons in wire: Electron charge: Area of wire: A ⇠ 10 Definition of current: v= q ⇠ 10 6 n ⇠ 1029 /m3 19 C m2 Drift Velocity dQ I= = nqAv dt I 1C/s = 29 nqA 10 · 10 19 · 10 6 C/m = 10 4 m/s wikipedia slower than a snail faster than continental drift Why is the current flow nearly instantaneous? If drift velocities are ~10-4 m/s, why do the lights turn on instantly? Answer: a conductor has mobile charges all along its length. Turning on a switch establishes an electric field through the conductor almost instantaneously, which means all mobile charges start drifting immediately. •A charge doesn’t need to travel from the switch to the light-bulb for the light-bulb to turn on – there are already charges inside the light-bulb, and the light-bulb turns on as soon as they start drifting, which happens almost instantly. Current and Work We just showed that the kinetic energy of the charges does not increase appreciably. So Where does the energy go? •Due to the frequent collisions of the moving charges, the energy is transferred to the (stationary) ions of the material, increasing their vibrational energy, and thus their temperature. Bulk of the work done by the electric field goes into heating the conductor. (this is ‘wasted’ energy, lots of room to increase efficiency) Quiz: current These four wires are made of the same metal. Rank in order, from largest to smallest, the electron currents ia to id: A.id>ia>ib>ic B.ib=id>ia=ic C.ic>ib>ia>id D.ic>ia=ib>id E.ib=ic>ia=id dQ I= = n q Avd dt Quiz: current These four wires are made of the same metal. Rank in order, from largest to smallest, the electron currents ia to id: A.id>ia>ib>ic dQ I= = n q Avd dt B.ib=id>ia=ic C.ic>ib>ia>id D.ic>ia=ib>id E.ib=ic>ia=id (πr )v 2 (πr )2v 2 (π 4r )v 2 ⎛ 1 2⎞ ⎜⎝ π r ⎟⎠ 2v 4 Quiz: current and drift speed Two copper wires of different diameter are joined end to end, and a current flows in the wire combination. When electrons move from the larger-diameter wire into the smaller-diameter wire, A.their drift speed increases. B.their drift speed decreases. C.their drift speed stays the same. D.not enough information given to decide Quiz: current and drift speed Two copper wires of different diameter are joined end to end, and a current flows in the wire combination. When electrons move from the larger-diameter wire into the smaller-diameter wire, A.their drift speed increases. B.their drift speed decreases. C.their drift speed stays the same. D.not enough information given to decide Analogy: water is a pipe (when radius of pipe decreases, the speed increases). The current I is constant for the whole wire. If A decreases, v has to decrease to compensate. dQ I= = nqAv dt Current density Current: dQ I= = n q Avd dt Take out the area factor => current density: J = I = n q vd ⎡ A 2 ⎤ ⎣ m⎦ A In some cases, it is useful to treat the current density as a vector: • q > 0, vd same direction as E • q < 0, vd opposite direction as E Total current through a surface: J describes how charges flow at a certain point • Direction of J changes around the circuit • Magnitude of J = I/A can change along the circuit (e.g. when A changes) Lecture 8 Conductivity, Resistance, & Circuits Announcements — Ch 24 HW due Thursday @ 8am — Ch 25 HW (yet to be assigned) will be due next week — Quiz tomorrow will cover Ch 23 and Ch 24 — Keep an eye out for a future email (from me) regarding a survey worth extra credit… Conductivity ● Currents flow in response to electric fields. ● For some materials (e.g. metals), the current density is [nearly] directly proportional to the electric field ● The constant of proportionality, σ, is called the conductivity of the conductor J=σE “Ohm’s Law” current density: Ohm’s Law ● ● ● ● I = n q vd A Ohm’s law : for many materials, the current density is proportional to the electric field: J = σ E Most metals obey Ohm’s law - Materials that obey Ohm’s law are called ohmic Not all materials follow Ohm’s law ● ● J=σE J= Materials that do not obey Ohm’s law are said to be nonohmic Ohm’s law is not a fundamental law of nature Ohm’s law is an empirical relationship valid only for certain materials ● Specifically when conduction properties are determined by collisions of electrons with atoms ● ● ● ● Ohm (1789 -1854) German physicist Formulated idea of resistance Discovered Ohm’s Law Conductivity & Resistivity J=σE Conductivity (σ) has units of [A/Vm] = •Good conductors have high conductivity •Insulators have low conductivity. ρ =1/σ [Ωm]-1 • V/A = Ω “ohm” • V = “volt” • A = “amp” ρ = E/J Resistivity (ρ) of a material is the ratio of the magnitudes of J and E •The greater the resistivity, the larger the electric field required to produce a given current density. When a material obeys Ohm’s Law it means that the resistivity (and/or conductivity) of a material is a constant (independent of E at a given temperature) ρ = E/J Resistivity Enormous differences in resistivity of conductors and insulators •Good conductors have low resistivity •Insulators have high resistivity •Bigger resistivity => larger E-field needed to produce a given current density Resistivity & Temperature Resistivity of materials depends on temperature. •Metallic materials: When you heat something up, the atoms jiggle around more – harder for electrons to get through. In some cases, resistivity follows a linear relation with temperature: ρ (T ) = ρ0 ⎡⎣1 + α (T − T0 )⎤⎦ • ρ0: resistivity at reference T0 (commonly 0oC or 20oC) • α: temperature coefficient of resistivity depends on the material •The resistivity of a metal typically increases with temperature •For semiconductor, resistivity decreases with temperature, in a non-linear way. •For special materials called superconductors, the resistivity goes to zero below a certain “critical temperature” (Tc). Superconductivity => resistivity becomes zero below a certain temperature Tc. 1911: discovered in mercury (Tc = 4.2 K) 1986: the highest Tc superconductor was ~20 K => need liquid Helium (expensive) or liquid Hydrogen (explosive) to maintain. 1987, an alloy with Tc well above the boiling point of liquid Nitrogen (cheap and safe) was discovered. The current record for highest T at atmospheric pressure is about 138 K. - “Room temperature” superconductivity is a highly sought after goal. ➡ Would revolutionize power-distribution, electronics and transportation. Resistance !" !" Ohm’s law tells us E & J related by resistivity ρ: E = ρJ There is a similar relation between V (~qE) and I (~J x area ) V = IR R = Resistance is related to resistivity ρ via: ρ <= set by material (e.g. copper) ρL R= Ω] [ A ● SI units of resistance are ohms (Ω) ● 1Ω=1V/A ● Resistance in a circuit arises due to collisions between the electrons carrying the current with the fixed atoms inside the conductor L & A <= set by shape (e.g. wire) Resistivity ρ is a property of the material Resistance R depends on material AND shape of resistor. V = IR This formula is more useful than the formal Ohm’s law because V and I are easier to measure than E and J Resistance ● ● ● The voltage applied across the ends of a conductor is proportional to the current through the conductor. The constant of proportionality is called the resistance of the conductor R = ΔV /I SI units of resistance are ohms (Ω) ● ● 1Ω=1V/A € Resistance in a circuit arises due to collisions between the electrons carrying the current with the fixed atoms inside the conductor V = IR R V I Example 15 cm Block of steel 1.2cm×1.2cm×15cm. ρsteel = 20×10-8 Ωm 1.2cm 1.2cm a)Resistance between square ends: ρL (20 ×10 [Ωm])(0.15[m]) R= = = 2.1×10 [Ω ] A (1.2 ×10 ) ⎡⎣m ⎤⎦ −8 −4 −2 2 2 b)Resistance between the two rectangular faces: ( )( ) −8 −2 ρL 20 ×10 [Ωm] 1.2 ×10 [m] −6 R= = = 1.3 ×10 Ω] [ −2 −2 2 A 1.2 ×10 15 . ×10 ⎡⎣ m ⎤⎦ ( )( ) R= ρL Ω] [ A current–voltage relationships V = IR I = (1/R) V current–voltage relationships V = IR I = (1/R) V V ≠ IR Diodes operate like valves! Current flows only in one direction. Important for logic functions circuits. Electric Circuits Current can only flow at a steady rate in a conductor that is part of a closed loop or “circuit”. In an isolated conductor, an electric field could produce a current momentarily, but charge would accumulate at the two ends. •This accumulation of charge would create a second electric field opposite to the one causing the current. •The electric field due to the build-up of charge at the ends would very quickly cancel the original electric field, and the current would stop. Circuits and Electric Potential Energy In moving through a conductor with resistance, the electric field does work on a charge and the charge’s potential energy always decreases: ΔV = IR ΔU = qΔV To keep current going, there must be some part in the circuit where the potential energy increases (e.g. a battery). •This part of the circuit behaves like the pump in a water fountain. •Without it, the water would fall to the bottom of the fountain and stay there. •The pump sends water back to the top of the fountain, so it can fall to the bottom again. Quiz: Resistor and PE Electrons in an electric circuit pass through a resistor. The wire has the same diameter on each side of the resistor. Compared to the potential energy of an electron before entering the resistor, the potential energy of an electron after leaving the resistor is A.greater. B.less. C.the same. D.not enough information given to decide Hint: Potential Energy U = q0V Quiz: Resistor and PE Electrons in an electric circuit pass through a resistor. The wire has the same diameter on each side of the resistor. Compared to the potential energy of an electron before entering the resistor, the potential energy of an electron after leaving the resistor is A.greater. B.less. C.the same. D.not enough information given to decide Hint: Potential Energy U = q0V In general, energy is dissipated in the resistor, so the charge carriers (electrons) must loose energy. Current flows from high-potential to lower-potential, thus the potential is lower at the end of the resistor. However, the electrons move opposite to the current, so they move towards higher electric potential V. The potential energy of an electron is U = −eV , thus it decreases when V increases. Charge is not “used up” It is a common mistake to think that charge is somehow consumed or “used up” as it passes through an electric circuit. The current is the same at every point in a simple loop circuit even if the wire thickness is different at various places. Charge can’t be created or destroyed, and it can’t accumulate anywhere in this simple type of circuit. Just like an ornamental water fountain, the rate of water flowing out of the top is the same as the rate of water flowing into the bottom. Water isn’t “used up” anywhere. emf A 1.5 V flashlight battery is an example of a source of emf - Non-electrostatic forces in the battery do 1.5 J of work on every Coulomb of charge that passes through it An emf converts chemical (or some other form) of energy into electrical energy. It acts like a “pump” in an electric circuit: moves charge from a lower potential to a higher potential. (We avoid the historical, misleading term “electromotive force”) - emf is not a force, but rather something like an electric potential. - emf has same unit as electric potential: Volts - Written as the symbol ε if we want to distinguish it from an electric potential V sources of emf In an ideal source of emf, which is isolated (not connected to a circuit), there is a balance between • the electrostatic force (Fe) on a charge, which tends to move charges to lower electric potential, in the direction of the electric field and • the non- electrostatic forces, Fn, which tend to move charges to higher electric potential, opposite the direction of the electric field If a charge is moved from b (lower potential) to a (higher potential) inside the source, the electric field does negative work, and the charge’s electric potential energy increases by: ΔU = qV e ab The work done by the non-electrostatic force must then equal the change in the electric potential energy: Wn = qε = ΔUe = qVab Thus, in an ideal source: ε = Vab sources of emf and circuits When a source of emf is connected to a circuit the potential difference between the poles of the source creates an electric field in the wire, which results in a current flowing from a to b: Vab = IR When a + charge flows around the circuit: • Potential rises by ε as it passes through the EMF source • Potential drops by Vab=IR as it passes through the rest of the circuit Internal resistance of emf sources In a real (as opposed to ideal) emf source, charges moving from the negative pole to the positive pole inside the source encounter resistance. - use the variable r = “internal resistance” of the source. If this resistance obeys Ohm’s Law, it is constant, and independent of the current. => Flowing charges experience a drop in potential equal to Ir I= ε R+ r Vab = ε − Ir The potential difference between the poles of a source with internal resistance is then: Vab = IR = ε − Ir •Vab is called the “terminal voltage”, and is less than the emf The current in the circuit outside the source is determined by Vab (not ε directly) This depends on I and thus changes depending on the circuit the battery is hooked to. emf source Vab = ε − Ir This is given by the battery An emf source is a source of constant emf - NOT a source of constant current - NOT a source of constant voltage •The current through a source of emf will depend on the resistance of the circuit it is attached to. •The terminal voltage will decrease as the current through the source increases. Vab = ε − Ir Current through external circuit connected to emf source is still given by Vab = IR. This means: Vab = E Ir = IR E I= R+r FYI: Circuit diagram Symbols Example: What is the ammeter reading for I? Vab = E Ir = IR E I= R+r I= 12V = 2A 4⌦ + 2⌦ Quiz: What is the voltmeter reading for Vab? Vab = E Ir = IR E I= R+r I= a)12V b)10V c)8 V d)6V 12V = 2A 4⌦ + 2⌦ Quiz: What is the voltmeter reading for Vab? Vab = E Ir = IR E I= R+r I= a)12V b)10V c)8 V d)6V 12V = 2A 4⌦ + 2⌦ Va0 b0 = IR = (4⌦)(2A) = 8V OR Va0 b0 = Vab = E IR = 12V 2A(2⌦) = 8V Electrical Power 1Joule =1Watt 1sec Charge goes a to b: PE of the system increases: QΔV - chemical energy in the battery must decrease by this same amount ● ● Charge goes c to d: same energy is lost (transformed into heat from the resistor). The rate at which the system loses potential energy as the charge passes through the resistor is equal to the rate at which the system gains internal energy in the resistor The power is the rate at which the energy is delivered to the resistor Power = dU/dt Power Current U = qV ! dU dq = V dt dt ! P = IV Useful Equations for Power P = IV Batteries & Resistors 2 P= I R 2 V P= R Power Delivered to a Resistor (V=IR) Announcements — Ch 24 HW due Thursday @ 8am — Ch 25 HW (yet to be assigned) will be due next week — Quiz tomorrow will cover Ch 23 and Ch 24 — Keep an eye out for a future email (from me) regarding a survey worth extra credit…