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By C.K.Cheung Fluid Dynamics Fluid Flow 1/ Steady flow: The fluid velocity, v, at a fixed point of a section is constant in time. v 2/ Non-steady flow: The fluid velocity at a fixed point depends on time. 3/ Streamline Path taken by fluid particles. V streamline V 1 By C.K.Cheung V2 P2A2 Density = L2 V1 Y2 P1A1 L1 Y1 Reference level Assume: Nonviscous, steady, incompressible flow of fluid through the pipeline. Consider the shaded portion: 1/ net W.D. on fluid = P1A1L1 – P2A2L2 2/ (K.E.) = 1 1 mv22 mv12 2 2 3/ ( P.E. ) = mg(y2 – y1 ) Since, (1) = (2) + (3) 1 1 mv22 mv12 + mg(y2 – y1 ) 2 2 P1A1L1 – P2A2L2 = For incompressible fluid: m A1L1 = A2L2 = P1( m ) + mgy1 + m 1 1 mv12 = P2( ) + mgy2 + mv 22 2 2 Multiply both side by ( ): m 2 By C.K.Cheung P1 + gy1 + 1 2 1 v1 = P2 + gy2 + v 22 2 2 Since, “1” & “2” refers to any two sections At any section along the pipeline: P + gy + 1 2 v = constant 2 ( Bernoulli’s equation ) Note : 1/ P called static pressure 2/ 1 2 v called the dynamic pressure 2 94’ MC 12. B 0.4 m A The figure above shows part of a pipe having circular cross-sections. The area of the cross-section at B is double that at A and the centre of the cross-section at B is 0.4 m higher than that at A. If an ideal liquid flows steadily through the pipe with speed 4 m/s at A, what is the difference in static pressure between A and B? (Given: density of the liquid is 1200 kg/m³) A. B. C. D. 2 400 N/m² 4 200 N/m² 4 800 N/m² 7 200 N/m² E. 12 000 N/m² A AaVa = AbVb Aa(4) = (2Aa)Vb Vb = 2 ms-1 Also, Pa + (1/2) (1200)(4)2 = Pb + (1200)(10)(0.4) + (1/2) (1200)(2)2 Static pressure difference = Pb - Pa = 2400 Nm-1 3 By C.K.Cheung Application of Bernoulli’s Equation 1/ Spinning ball (moving leftwards) V+V ' V’ V 1 w w=0 V-V ' 2 V’ V Consider points ‘ 1 ‘ & ‘ 2 ‘ P + gy + 1 2 v = constant 2 Assume small ball y ~ 0 P+ 1 2 v = constant 2 Since V1 > V2 P1 < P2 net upward force. 2/ Air foil V1 V1 > V2 V2 P2 > P1 upward lift 4 By C.K.Cheung 3/ Against the wind: Force on sail Fast moving air Yacht 4/ Filter pump Water from water- tape air Air from apparatus (Water + air) The high velocity of water at constriction produces a drop in air pressure air flows in from the side tube, and together with water is expelled through the lower part of the pump. 5 By C.K.Cheung 5/ Bunsen burner jet air gas 6 By C.K.Cheung 6/ Carburettor Petrol + air mixture e air float Petrol level A float mechanism maintain the petrol level just below the top of a fine jet. When the engine is running, air is swept past the jet swiftly drop in air pressure, the greater atmospheric pressure on the petrol in the reservoir then forces petrol out of the jet in the form of fine spray. This occurs when the accelerator pedal is pressed down. 7/ Spray 7 By C.K.Cheung Pitot – static tube To measure gases flow speed. 1 2 Density of P1 gas = ’ P2 h Density of liquid = Assume the probe is small ( not to disturb the fluid flow ) Apply Bernoulli’s eqt., to “1 “ P2 = P1 + 1 'v2 2 & “2” (1) Also: P2 = P1 + gh (2) (1) = (2): 1 ' v 2 gh 2 v= 2 gh ' 8 By C.K.Cheung More e.g. about Bernoulli’s principle: 1/ 2/ The 2 boats will draw together & collide 9 By C.K.Cheung 3/ Umbrella in windy day 4/ 10 By C.K.Cheung 4/ Wharfs are made with pilings that permit the free passage of water. 11 By C.K.Cheung e.g. P1 P2 v h H X=? Given: 1/ A large open tank 2/ A small hole is punched at a depth h below water surface. Find: 1) x = ? 2) Could a hole be punched at another depth so that this second stream would have the same range? If so, at what depth? 1) P1 + gh = P2 + (1/2)v2 P1 = P2 gh = 2/ (1/2)v2 v = (2gh)1/2 ~ free fall Since (H-h) = (1/2)gt2 t = (2(H-h)/g)1/2 X = vt = (4h(H-h))1/2 For another hole at a depth h’ X’ = (4h’(H-h’))1/2 h’ = h (reject) or h’ = (H-h) 12 By C.K.Cheung 93’ MC 15. fluid flow speed v h The above figure shows a Pitot-static tube situated in a moving fluid. Which of the following graphs best shows the relation between the speed v of the fluid and the difference in manometer levels h? A. v h B. v h C. v h D. v h E. 13 By C.K.Cheung v h A 90’ MC 11. In fluid dynamics, which of the following assumptions is/are used in deriving Bernoulli’s equation? (1) The fluid undergoes streamline flow. (2) The fluid is compressible. (3) Viscous forces act on the fluid. A. (1), (2) and (3) B. (1) and (2) only C. (2) and (3) only D. (1) only E. (3) only D 84’MC 42. The above figure shows the stream lines for air flowing past the wing of an aeroplane. Which of the following is/are correct? (1) The pressure above the wing is greater than that below the wing. (2) The speed of the air flow above the wing is greater than that below the wing. (3) The pressure difference between locations above and below the wing increases when the density of air increases. (Assume the same speed of air flow.) 14 By C.K.Cheung A. (1), (2) and (3) B. C. D. E. (1) and (2) only (2) and (3) only (1) only (3) only C 87’MC 12. fluid flow S T The above diagram shows a Pitot-static tube situated in a moving fluid. shows a difference h in the liquid levels. A manometer connected to S and T If v = the velocity of the moving fluid, d = the density of the moving fluid, = the density of the liquid in the manometer, then v² is equal to A. 2gh/d. B. 2dgh/. C. gh/d. D. dgh/. E. dgh. 94’ essay 3. (a) (i) (ii) A Solids can be thought of as networks of atoms connected by ‘small springs’. Explain how this method can be deduced from solids’ observed resistance to deformation. ( out of syllabus ) Sketch the curve of potential energy against interatomic separation and use it to explain the phenomenon of thermal expansion of solids. (6 marks) 15 By C.K.Cheung (b) Glass is a strong, stiff and brittle material. Sketch the stress-strain graph for glass and briefly explain why it is so described. (3 marks) (c) With suitable diagrams, use the Bernoulli principle to explain (i) how a yacht can sail against the wind; (ii) the curved flight of a spinning ball. Also suggest one design feature which increases the curvature of the ball’s flight. (7 marks) 91’ IIB 8. Figure 8.1 shows a petrol pump in a garage. The pump delivers petrol with a density of 750 kg/m3 at a rate of 1.2 10-2 m3/s. The input to the pump is from a pipe with a cross-sectional area A1 of 4 10-3 m2 at a suction pressure P1 of 1 104 Pa. The discharge of the pump is at a gauge pressure P2 of 2.8 105 Pa into a pipe with a cross-sectional area A2 of 8 10-4 m2. The pipes at the entrance and exit are at the same horizontal level and the temperature of the petrol remains constant throughout the flow. Suction pressure Gauge pressure P1 = 1 x 10 4 Pa P2 = 2.8 x 10 5 Pa Input Output v1 v2 Pump rotor Figure 8.1 (a) Find the average flow speeds v1 and v2 of the petrol into and out of the pump. (2 marks) (b) Find the change in kinetic energy per unit mass of petrol. (2 marks) (c) By considering the work done per unit mass of petrol at the entrance and exit of the pump, find the work done by the pump in delivering a unit mass of petrol. (4 marks) (d) Find the mechanical power developed in the pump in order to maintain the above flow 16 By C.K.Cheung conditions. (2 marks) (e) Explain why, in reality, the mechanical power of the pump required is higher than that calculated in (d). (2 marks) 89” Essay 2. (a) Discuss qualitatively the motion of a small metal ball allowed to drop downwards into a long vertical tube of liquid so that it moves along the axis of the tube (radius of tube >> radius of ball). (3 marks) (b) Derive Bernoulli’s equation, P + hg + ½v² = a constant for the flow of a fluid through a tube of varying cross-sectional area. Clearly explain all the physical parameters used in this equation. (6 marks) (c) In practice, discuss the likely sources of error in applying Bernoulli’s equation to the flow of (i) liquids, and Due to viscosity the velocity of the liquid at any particular cross-section of the tube will vary from a maximum at the center to zero on the sides of the tube. Even if the cross-section and the height remained constant the pressure would drop due to energy dissipation against viscous (ii) gases in tubes. (3 marks) The fluid is compressible so that the density would vary with the pressure P, affecting the ‘hg’ term in the equation. 17 By C.K.Cheung 88’ IIB 8. (a) direction of ball Figure 8.1 (i) Figure 8.1 shows the streamlines around a tennis ball when it is projected in a straight line through still air. In Figure 8.2, sketch the streamlines in the vicinity of the ball if; apart from the forward motion, it is also spinning about an axis, through its centre, perpendicular to the plane of paper in an anti-clockwise direction.(2 marks) forward motion Pattern correct: lines crowded on L.H.S.-----1M Arrows inserted---------1M Figure 8.2 (ii) Describe, with reasons, the subsequent motion of the ball. (4 marks) 18 By C.K.Cheung Ball rotates; drags surrounding air Air on LHS flows faster than that on RHS Pressure on LHS less Ball deflected towards the left (b) (i) One end of an open tube is put vertically into water. By blowing strongly across the open end, water can be drawn up the tube. Suppose a few centimetres of the tube is above the water surface. What should be the air velocity at the open end for water in the tube to rise up by 1 cm? Explain your working. (Surface tension effects may be ignored.) (3 marks) ( Density of air Density of water Acceleration due to gravity = 1.29 kg/m3, = 1 000 kg/m3, = 10 m/s2 ) Pressure at upper end reduced due to air-flow 1 ' v 2 gh 2 (1/2)(1.29)v2=1000x10x0.01 v = 12.5 ms-1 (ii) Mention one daily application making use of the principle described in (b)(i). mark) (1 84’Essay 1. (a) (i) Using a practical example, demonstrate what is meant by ‘the conservation of mechanical energy’. (ii) By means of a further practical example, show that in ‘real-life’ situations mechanical energy is often not conserved. (b) Derive Bernoulli’s equation for fluid flow: 1 2 v a constant . 2 (c) Explain why Bernoulli’s equation is not strictly applicable to (i) a gas, and (ii) a viscous liquid flowing through a narrow tube. (d) With the aid of diagrams and Bernoulli’s equation, explain the observed effects of (i) the motion of a spinning ball, and (ii) the mixing of coal gas and air in a bunsen burner. P hg 19