Download Geo, Chap 2 Practice Test, EV Ver 1

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Geo, Chap 2 Practice Test, EV Ver 1
Multiple Choice
Identify the choice that best completes the statement or answers the question.
____
1. (2-2)
Which biconditional is NOT a good definition?
a. A whole number is odd if and only if the number is not divisible by 2.
b. An angle is straight if and only if its measure is 180.
c. A whole number is even if and only if it is divisible by 2.
d. A ray is a bisector of an angle if and only if it splits the angle into two angles.
Short Answer
2. (2-1)
Identify the hypothesis and conclusion of this conditional statement:
If two lines intersect at right angles, then the two lines are perpendicular.
3. (2-1)
What is the conclusion of the following conditional?
A number is divisible by 3 if the sum of the digits of the number is divisible by 3.
4. (2-1)
What is the converse of the following conditional?
If a point is in the first quadrant, then its coordinates are positive.
5. (2-2)
For the following true conditional statement, write the converse. If the converse is also true,
combine the statements as a biconditional.
If x = 3, then x2 = 9.
6. (2-3)
Use the Law of Detachment to draw a conclusion from the two given statements. If not possible,
write not possible.
I can go to the concert if I can afford to buy a ticket.
I can go to the concert.
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7. (2-3)
If possible, use the Law of Detachment to draw a conclusion from the two given statements. If
not possible, write not possible.
Statement 1: If x = 3, then 3x – 4 = 5.
Statement 2: x = 3
8. (2-3)
Use the Law of Syllogism to draw a conclusion from the two given statements.
If a number is a multiple of 64,then it is a multiple of 8.
If a number is a multiple of 8, then it is a multiple of 2.
Fill in each missing reason.
9. (2-4)
Given: m∠PQR = x − 5, m∠SQR = x − 11, and m∠PQS = 100.
Find x.
m∠PQR + m∠SQR = m∠PQS
x – 5 + x – 11 = 100
2x – 16 = 100
2x = 116
x = 58
a. _____
b. Substitution Property
c. Simplify
d. _____
e . Division Property of Equality
10. (2-4)
Name the Property of Congruence that justifies the statement:
If ∠A ≅ ∠B and ∠B ≅ ∠C, then ∠A ≅ ∠C.
11. (2-4)
BD bisects ∠ABC. m∠ABC = 7x. m∠ABD = 3x + 25. Find m∠DBC.
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12. (2-5)
Find the value of x.
13. (2-5)
m∠3 = 37. Find m∠1.
14. (2-5)
Find the values of x and y.
ID: A
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ID: A
Geo, Chap 2 Practice Test, EV Ver 1
Answer Section
MULTIPLE CHOICE
1. ANS: D
PTS: 1
DIF: L3
OBJ: 2-2.2 Recognizing Good Definitions
REF: 2-2 Biconditionals and Definitions
KEY: biconditional statement
SHORT ANSWER
2. ANS:
Hypothesis: Two lines intersect at right angles. Conclusion: The two lines are perpendicular.
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
OBJ: 2-1.1 Conditional Statements
TOP: 2-1 Example 1
KEY: conditional statement | hypothesis | conclusion
3. ANS:
The number is divisible by 3.
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
OBJ: 2-1.1 Conditional Statements
TOP: 2-1 Example 1
KEY: conditional statement | conclusion
4. ANS:
If the coordinates of a point are positive, then the point is in the first quadrant.
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
OBJ: 2-1.2 Converses
TOP: 2-1 Example 5
KEY: conditional statement | coverse of a conditional
5. ANS:
If x2 = 9, then x = 3. False
PTS: 1
DIF: L2
REF: 2-2 Biconditionals and Definitions
OBJ: 2-2.1 Writing Biconditionals
TOP: 2-2 Example 1
KEY: conditional statement | coverse of a conditional | biconditional statement
6. ANS:
not possible
PTS:
OBJ:
TOP:
7. ANS:
3x – 4
1
DIF: L3
REF: 2-3 Deductive Reasoning
2-3.1 Using the Law of Detachment
STA: CA GEOM 1.0
2-3 Example 3
KEY: deductive reasoning | Law of Detachment
=5
PTS: 1
DIF: L4
REF: 2-3 Deductive Reasoning
OBJ: 2-3.1 Using the Law of Detachment
STA: CA GEOM 1.0
KEY: Law of Detachment | deductive reasoning
1
ID: A
8. ANS:
If a number is a multiple of 64, then it is a multiple of 2.
PTS:
OBJ:
TOP:
9. ANS:
Angle
1
DIF: L2
REF: 2-3 Deductive Reasoning
2-3.2 Using the Law of Syllogism STA: CA GEOM 1.0
2-3 Example 4
KEY: deductive reasoning | Law of Syllogism
Addition Postulate; Addition Property of Equality
PTS: 1
DIF: L2
REF: 2-4 Reasoning in Algebra
OBJ: 2-4.1 Connecting Reasoning in Algebra and Geometry STA: CA GEOM 1.0| CA GEOM 3.0
TOP: 2-4 Example 1
KEY: Properties of Equality | Angle Addition Postulate | deductive reasoning
10. ANS:
Transitive Property
PTS: 1
DIF: L2
REF: 2-4 Reasoning in Algebra
OBJ: 2-4.1 Connecting Reasoning in Algebra and Geometry STA: CA GEOM 1.0| CA GEOM 3.0
TOP: 2-4 Example 3
KEY: Properties of Congruence
11. ANS:
175
PTS: 1
DIF: L4
REF: 2-4 Reasoning in Algebra
OBJ: 2-4.1 Connecting Reasoning in Algebra and Geometry STA: CA GEOM 1.0| CA GEOM 3.0
KEY: Properties of Congruence | Properties of Equality | deductive reasoning
12. ANS:
19
PTS: 1
DIF: L2
OBJ: 2-5.1 Theorems About Angles
TOP: 2-5 Example 1
13. ANS:
37
REF: 2-5 Proving Angles Congruent
STA: CA GEOM 1.0| CA GEOM 2.0| CA GEOM 4.0
KEY: vertical angles | Vertical Angles Theorem
PTS: 1
DIF: L2
OBJ: 2-5.1 Theorems About Angles
TOP: 2-5 Example 1
14. ANS:
x = 15, y = 17
REF: 2-5 Proving Angles Congruent
STA: CA GEOM 1.0| CA GEOM 2.0| CA GEOM 4.0
KEY: Vertical Angles Theorem | vertical angles
PTS:
OBJ:
TOP:
KEY:
1
DIF: L2
REF: 2-5 Proving Angles Congruent
2-5.1 Theorems About Angles
STA: CA GEOM 1.0| CA GEOM 2.0| CA GEOM 4.0
2-5 Example 1
Vertical Angles Theorem | vertical angles | supplementary angles | multi-part question
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