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CHAPTER 7 Quantitative Composition of Compounds 7.1 THE MOLE Used to count incredibly small objects, like atoms Avogadro’s Number 6.02 x 1023 = 1 Mole Practice 7.1 How many atoms are in 1.00 mole of: a) Fe b) H2 c) H2SO4 7.2 MOLAR MASS OF COMPOUNDS Molar Mass – atomic mass of an element in grams containing Avogadro's number of atoms Practice 7.2 Can be used as a conversion factor What is the mass of 2.50 moles of He? Practice 7.3 How many atoms are present in 0.025 mol of iron? Practice 7.4 Practice 7.5 Calculate the molar mass of KNO3 What is the mass of 0.150 mol Na2SO4? Practice 7.6 How many moles and molecules are there in 500.0 g of HC2H3O2? 7.3 PERCENT COMPOSITION OF COMPOUNDS Mass percent of each element in a compound Practice 7.7 Found from the formula or experimental data Calculate the percent composition of Ca(NO3)2 Practice 7.8 Calculate the percent composition K2CrO4 Practice 7.9 Aluminum chloride is formed by reacting 13.43g aluminum with 53.18g of chlorine. What is the percent composition of the compound? 7.4 EMPIRICAL FORMULA VS. MOLECULAR FORMULA Empirical Formula – simplest formula – the smallest whole number ratio of atoms present in a compound Molecular Formula – true formula – represents the total number of atoms of each element present in one molecule of a compound 7.5 CALCULATING EMPIRICAL FORMULAS Assume a definite starting quantity (usually 100.0g) of the compound, if not given, and express the mass of each element in grams. Convert the grams of each element into moles using each element's molar mass. (This step will usually not give whole numbers.) Divide each value by the smallest value obtained in step 2. If these values aren’t whole numbers, go on to the next step. Multiply by the smallest number needed to make all of the numbers from step 3 whole numbers. Practice 7.10 Calculate the empirical formula of a compound containing 52.14% C, 13.12% H, and 34.73% O. Practice 7.11 Calculate the empirical formula of a compound that contains 43.7% P and 56.3% O by mass. 7.6 CALCULATING THE MOLECULAR FORMULA FROM THE EMPIRICAL FORMULA The molecular formula will be equal to, or some multiple of, the empirical formula. The molar mass of the compound must be given to solve for the molecular formula. Divide the molar mass of the compound by the molar mass of the empirical formula to find the factor to multiply the coefficients by. Example If a compound has an empirical formula of NO2 and a molar mass of 92.00g, determine the molecular formula. Practice 7.12 Calculate the empirical and molecular formulas of a compound that contains 80.0% C, 20.0% H and has a molar mass of 30.00g. HOMEWORK Required: Paired Exercises 2-44, even Suggested: Paired Exercises 1-43, odd