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1 Remarks about conditional expectation. ⋆ For a given event A with P (A) > 0 and a random variable X, the conditional expectation, also called conditional mean, of X given A can be def ined as E(X|A) = E(X1{A} )/P (A) where 1 if A happens 0 otherwise. Notice that 1{A} , called indicator function, is a random variable. This is a very commonly used mathematical trick to transform an event into a random variable. Example. Let X be the total number of dots of two dice and A be the event that both dots are even numbers. Then A consists of (2, 2), (4, 4), (6, 6) three outcomes out of 36 outcomes. Therefore P (A) = 3/36 = 1/12. 4 for outcome (2,2) with probability 1/36 8 for outcome (4,4) with probability 1/36 X1{A} = 12 for outcome (6,6) with probability 1/36 0 else with probability 1-3/36=11/12 1{A} = n So E(X1{A} ) = (4 + 8 + 12)/36 = 2/3, as a result, E(X|A) = E(X1{A} )/P (A) = (2/3)/(1/12) = 8. The above definition is in my view easier and more helpful in understanding the following derivation in Example 3.6: E(T1 1{X2 =0} |X1 = 0) = E(T1 |X2 = 0, X1 = 0)P (X2 = 0|X1 = 0) because the right hand side, by definition, is = E(T1 1{X2 =0,X1 =0} ) E(T1 1{X2 =0,X1 =0} ) P (X2 = 0, X1 = 0) × = P (X2 = 0, X1 = 0) P (X1 = 0) P (X1 = 0) E(T1 1{X2 =0} 1{X1 =0} ) = E(T1 1{X2 =0} |X1 = 0) P (X1 = 0) again by the definition of conditional expectation. We note that 1A∩B = 1A 1B for any two events A and B. An alternative but equivalent way of defining conditional expectation is to use conditional distribution. Define the conditional distribution as F (x) = P (X ≤ x|A). The conditional expectation of X given A is then Z ∞ E(X|A) = xdF (x). −∞ Conditional expectation is a very important concept is probability, which is further generalized in advanced probability.