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					MA4266 Topology Lecture 16 Wayne Lawton Department of Mathematics S17-08-17, 65162749 [email protected] http://www.math.nus.edu.sg/~matwml/ http://arxiv.org/find/math/1/au:+Lawton_W/0/1/0/all/0/1 Separation Properties or axioms, specify the degree by which points and/or closed sets can be separated by open sets & continuous functions T0 Kolmogorov space Ex. Sierpinski space 1 point from a pair separated from the other by OS T1 Frechet space Ex. Finite Comp. Top. on Z each point from a pair separated from the other by OS ~ 2 T2 Hausdorf space Ex. Double Origin Top. on R  { 0 } pairs of points jointly separated by OS T2 1 completely Hausdorf space (called Urysohn in book) 2 PP sep. by CN Ex. Half-Disc Top. on R  [0,  ) T3 points & closed sets jointly separated by OS Ex. Tychonov & Hewitt & Thomas’s Corkscrew Top., Ostaszewski T3 1 points & closed sets jointly separated by CF 2 T4 Ex. Sorgenfrey plane pairs of closed sets jointly separated by OS Combinations of Separation Properties X is Completely Hausdorff or T2 12 if a, b  X , a  b   open U  a,V  b,U  V  . Regular if it is T1 and T3 , Completely Regular or T3 1 2 if it is T1 and a  X , a  closed C  X  Definition A space  continuous f:X  R, f (a)  0, f (C )  1, Normal if it is Theorem 8.1 T1 and T4 . T1  finite subsets are closed. Metrizable Normal  Completely Regular  Regular  T2 1  T2  T1  T0 2 Theorem 8.2 Products of Ti spaces are Ti , i  0,1, 2. Regular Spaces X is a T1 space. Then X is T3 (and therefore regular) if and only if for every a  X and open U  a there exists open W  a with W  U . Proof If X is regular and a  U open  X then C  X \U is closed and a  C hence there exist disjoint open W  a and V  C. Hence W  X \V . Theorem 8.3 Assume that W  X \ V (why?) so W  X \ C  U . Conversely, if the latter condition holds and C is a closed set with a  C. Then there exists open W  a with W  X \ C (why?) so W and X \ W are disjoint open sets containing a and C respectively. Hence Regular Spaces X is a T1 space. Then X is T3 if and only if for every a  X , a  C closed, there exists open U , V with a U , C  V ,U  V  . Theorem 8.4 Assume that Proof page 235. Theorem 8.5 The product of regular spaces is regular. Proof Let { X  :   A} be a family of regular spaces, X   A X  , a U open  X. Therefore n 1 U  i open  X , i  1,..., n  a   i 1 p (U  )  U . Then  p (a) V open  V  U , i  1,..., n why? n 1 V  p ( V ) Then is open, contains a and    i 1 n n 1 V   i 1 p (V )   i 1 p1 (U  )  U , so X is regular. i i i i i i i i i i i i Examples Double Origin Topology (counterexample # 74, [1]) ( X , ), X  ( R \ {0})  {0 } { 0 } 2   ( R \ {0})usual  0  0  0  has a local basis 2 2 Vn,   { ( x, y) : x  y  n12 ,  y  0} {0 }, n  N Question Why is ( X , ) T2 ? Question Why is ( X , ) NOT T2 1 ? 2 Question Is ( X , ) 2nd countable ? path connected ? Question Is ( X , ) regular ? locally compact ? 2 [1] Counterexamples in Topology by Lynn Arthur Steen and J. Arthur Seebach, Jr., Dover, New York, 1970. Examples Half-Disc Topology (counterexample # 78, [1]) and Example 8.2.1 in Croom’s Principles of Topology. ( X , ), X  R  (0, )  R  {0}   ( R  (0, )) usual  ( R {0})half disk where a local basis at (a,0)  R  {0} is Vn  { ( x, y) : ( x  a) 2  y 2  n12 , y  0} {( a,0)}, n  N Question Why is ( X , ) T2 1 ? 2 Question Why is ( X , ) NOT T3 ? Normal Spaces X is a T1 space. Then X is T4 (and hence normal) iff for every closed A  X and open U  A there exists open W  A with W  U . Theorem 8.7 Assume that X is a T1 space. Then X is T iff for every pair of disjoint closed sets A, B  X 4 there exist open sets U  A, V  B with U V   . Theorem 8.6 Assume that Theorem 8.8 Every compact Hausdorff space is normal. Proof Corollary to Theorem 6.5, pages 165-166. Normal Spaces Theorem 8.9 Every regular Lindelöf space is normal. A, B be disjoint closed sets. First, use regularity to construct an open cover of A by sets whose closures are disjoint with A, likewise for B. Proof Let Second, use the Lindelöf property to obtain countable subcovers U1 ,U 2 ,... of A and n V1 ,V2 ,... B. of n Third, construct U  U n \  i 1 Vn , V  Vn \  i 1 U n ' n and observe that ' n U  V   , for all m, n  N . ' n Fourth, construct U  ' m   ' U , V  V  n1  n1 n and ' n observe they are open sets and A  U , B  V . Normal Spaces Why ? Corollary Every 2nd countable regular space is normal. Definition For a set A, card A  c  A is equipotent with [0,1] X is a separable normal space and E card E  c, then E has a limit point. Proof Assume that such a set E has no limit point. Then for every Y  E the sets Y and E \ Y are closed so there exist disjoint open UY  Y and VY  E \ Y . Let D Be a countable dense subset and construct a Theorem 8.10 If is a subset with function h : P( E )  P( D) by h(Y )  UY  D, Y  P( E). Since h is 1-to-1 (see p. 239) card P( E )  card P( D). But card P( D)  card R  card P( R)  card P( E ). Theorem 8.11 Every metric space is normal. Ex 3.2 p.69 Examples Sorgenfrey Plane (counterexample # 84, [1]) and Example 8.3.1 in Croom’s Principles of Topology. ( R  R,  )   half  open interval topology Question Why is ( R, ) regular ? Question Why is ( R, ) Lindelöf ? Question Why is ( R, ) normal ? Question Why is ( R  R,   ) regular, separable ? Let E  {( x, x) : x  R}  R  R Question What is the subspace topology on E ? Question What are the limit points of E ? Question Why is ( R  R,   ) NOT normal ? Examples Niemytzki’s Tangent Disc Top. (counterexample # 82,[1]) and Ex. 8.3, Q6, p. 242 Croom’s Principles of Topology. ( X , ), X  R  (0, )  R  {0}   ( R  (0, )) usual  ( R  {0}) tangentdisk where a local basis at (a,0)  R  {0} Vn  { ( x, y) : ( x  a)  ( y  )  n12 } {( x,0)}, n  N 2 1 2 n ( X , ) T3 1 ? 2 Question Why is ( X , ) separable ? Question Why is ( X , ) NOT normal ? Question Why is Separation by Continuous Functions Definition Separation by continuous functions. and Ex. 8.4.1, Q6, p. 243 Croom’s Principles of Top. Theorem 8.12 Let X be a T1 space. (a) If points a and b can be separated by a continuous function then they can be separated by open sets. (b) If each point x and closed set C not containing a can be separated by continuous functions then they can be separated by open sets. (c) If disjoint closed sets A and B can be separated continuous functions then they can be separated by open sets. Examples Definition Funny Line : ( X 1 , 1 ), X 1  R,  1  ( R \ {0})discrete  {0} where U  0 is open iff R \ U is finite. (a one-point compactification of an uncountable set) Definition A subset S of a topological space X is a G  set (gee-delta) if it is the intersection of a countable collection of open sets, and a F  set (eff-sigma) if it is the union of a countable collection of closed sets. Theorem If X is a topological space and f : X  R is 1 f (a) is a G  set for every a X . continuous then 1 Proof f (a)  f 1   i 1   B(a, )   i 1 f 1 ( B(a, 1i )). 1 i Corollary Every continuous f : X1  R equals f (0) except at a countable set of points. Examples Thomas’ Plank (counterexample # 93, [1]) ( X , ), X  X1  X 2 \ {( 0,0)}, prod top 1 ( X ,  ), X  { where 2 2 2 k : k  Z \ {0}}  {0}  2  usual subspace topology of R Theorem If f : X  R is continuous then f is constant except at a countable set of points. 1 f R  { } Proof On each set the function is constant k 1 countable. R  { } R \ R on a set k where k k 1 L   kZ \{ 0} Rk L  { f is constant on each k } where and therefore f is constant on ( L \ {0})  {0}. Examples Thomas’ Corkscrew (counterexample # 94, [1]) (Y , ), Y  X  Z  {a }  {a }   where the local bases for points in Y \ {( x,0, m) : x  0, m  Z } is the same as for the product topology, and local bases for other points are Bn ( x,0, m)  {( x,0, m)}  { ( x, 1k , m) : k  n }  { ( x, 1k , m  1) : k  n } Bn (a  )  {a  }   m  n X  {m}, Bn (a  )  {a  }   m   n X  {m}, n N. Theorem (Y , ) for is regular but NOT completely regular since every continuous f : Y  R satisfies f (a  )  f (a  ). Separation by Continuous Functions Lemma 1. Dyadic numbers are dense in R. Lemma 2. Let X be a space and D dense  [0, ). t  D  open U t  X  (a) t1  t2  U t  U t , and (b)  tD U t  X , 1 2 then the function f : X  R defined by f ( x)  glb { t  D : x U t }, x  X is continuous. Theorem 8.13 Urysohn’s Lemma Let X be a T1 space. then X is normal iff for all disjoint closed A, B  X , If for every there exists a continuous f : X  R with f ( A)  0, f ( B)  1. Theorem 8.14 Tietze Extension Theorem Let X be a normal space, A closed  X , and f : A  R continuous. Then f has a continuous extension F : X  R. Assignment 16 Read pages 234-237, 237-241, 243-251 Prepare to solve during Tutorial Thursday 8 April Exercise 8.2 problem 4 (c) Exercise 8.3 problem 6 (a),(b),(c),(d) Exercise 8.4 problems 8 (a),(b), 11, 13, 14 (a),(b) 15, 16