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1
Preparation for Calculus
Copyright © Cengage Learning. All rights reserved.
1.2
Linear Models and Rates
of Change
Copyright © Cengage Learning. All rights reserved.
Objectives
 Find the slope of a line passing through two
points.
 Write the equation of a line given a point and
the slope.
 Interpret slope as a ratio or as a rate in a reallife application.
3
Objectives
 Sketch the graph of a linear equation in slopeintercept form.
 Write equations of lines that are parallel or
perpendicular to a given line.
4
The Slope of a Line
5
The Slope of a Line
The slope of a nonvertical line is a measure of the number
of units the line rises (or falls) vertically for each unit of
horizontal change from left to right. Consider the two points
(x1, y1) and (x2, y2) on the line in Figure 1.12.
y = y2 – y1 = change in y
x = x2 – x1 = change in x
Figure 1.12
6
The Slope of a Line
As you move from left to right along this line, a vertical
change of
y = y2 – y1
change in y
units corresponds to a horizontal change of
x = x2 – x1
change in x
units. ( is the Greek uppercase letter delta, and the
symbols y and x are read “delta y” and “delta x.”)
7
The Slope of a Line
8
The Slope of a Line
Figure 1.13 shows four lines: one has a positive slope, one
has a slope of zero, one has a negative slope, and one has
an “undefined” slope.
If m is positive, then
the line rises from left
to right.
If m is zero, then the
line is horizontal.
If m is negative, then
the line falls from left
to right.
If m is undefined, then
the line is vertical.
Figure 1.13
9
The Slope of a Line
In general, the greater the absolute value of the slope of a
line, the steeper the line is. For instance, in Figure 1.13, the
line with a slope of –5 is steeper than the line with a slope
of .
10
Equations of Lines
11
Equations of Lines
Any two points on a nonvertical line can be used to
calculate its slope. This can be verified from the similar
triangles shown in Figure 1.14. (Recall that the ratios of
corresponding sides of similar triangles are equal.)
Any two points on a nonvertical line can be
used to determine its slope.
Figure 1.14
12
Equations of Lines
You can write an equation of a nonvertical line if you know
the slope of the line and the coordinates of one point on the
line.
Suppose the slope is m and the point is (x1, y1). If (x, y) is
any other point on the line, then
This equation, involving the two variables x and y can be
rewritten in the form y – y1 = m(x – x1), which is called the
point-slope form of the equation of a line.
13
Equations of Lines
14
Example 1 – Finding an Equation of a Line
Find an equation of the line that has a slope of 3 and
passes through the point (1, –2).
Solution:
y – y1 = m(x – x1)
y – (–2) = 3(x – 1)
y + 2 = 3x – 3
y = 3x – 5
(See Figure 1.15.)
Point-slope form
Substitute –2 for y1, 1 for x1,
and 3 for m.
Simplify.
Solve for y.
The line with a slope of 3 passing
through the point (1, –2)
Figure 1.15
15
Ratios and Rates of Change
16
Ratios and Rates of Change
The slope of a line can be interpreted as either a ratio or
a rate.
If the x- and y-axes have the same unit of measure, the
slope has no units and is a ratio.
If the x- and y-axes have different units of measure, the
slope is a rate or rate of change.
In your study of calculus, you will encounter applications
involving both interpretations of slope.
17
Example 2(a) – Population Growth and Engineering Design
The population of Colorado was 3,827,000 in 1995 and
4,665,000 in 2005. Over this 10-year period, the average
rate of change of the population was
Population of Colorado
Figure 1.16
If Colorado’s population continues to increase at this same
rate for the next 10 years, it will have a 2015 population of
5,503,000 (see Figure 1.16).(Source: U.S.Census Bureau)
18
Example 2(b) – Population Growth and Engineering Design
cont’d
In tournament water-ski jumping, the ramp rises to a height
of 6 feet on a raft that is 21 feet long, as shown in
Figure 1.17.
Dimensions of a water-ski ramp
Figure 1.17
19
Example 2(b) – Population Growth and Engineering Design
cont’d
The slope of the ski ramp is the ratio of its height (the rise)
to the length of its base (the run).
Rise is vertical change, run is horizontal change.
In this case, note that the slope is a ratio and has no units.
20
Ratios and Rates of Change
The rate of change found in Example 2(a) is an average
rate of change.
An average rate of change is always calculated over an
interval. In this case, the interval is [1995, 2005].
21
Graphing Linear Models
22
Graphing Linear Models
Many problems in analytic geometry can be classified in
two basic categories:
(1) Given a graph, what is its equation? and
(2) Given an equation, what is its graph?
The point-slope equation of a line can be used to solve
problems in the first category.
However, this form is not especially useful for solving
problems in the second category.
23
Graphing Linear Models
The form that is better suited to sketching the graph of a
line is the slope-intercept form of the equation of a line.
24
Example 3 – Sketching Lines in the Plane
Sketch the graph of each equation.
a. y = 2x + 1
b. y = 2
c. 3y + x – 6 = 0
Solution:
a. Because b = 1, the y-intercept is (0, 1).
Because the slope is m = 2,
you know that the line rises
two units for each unit it moves
to the right, as shown in
Figure 1.18(a).
m = 2; line rises
Figure 1.18(a)
25
Example 3 – Solution
cont’d
b. Because b = 2 the y-intercept is (0, 2).
Because the slope is m = 0, you know that the line is
horizontal, as shown in Figure 1.18(b).
m = 0; line is horizontal
Figure 1.18(b)
26
Example 3 – Solution
cont’d
c. Begin by writing the equation in slope-intercept form.
3y + x – 6 = 0
3y = –x + 6
Write original equation.
Isolate y-term on the left.
Slope-intercept form
In this form, you can see that the y-intercept is (0, 2) and
the slope is m = .
27
Example 3 – Solution
cont’d
This means that the line falls one unit for every three
units it moves to the right, as shown in Figure 1.18(c).
m=
; line falls
Figure 1.18(c)
28
Graphing Linear Models
Because the slope of a vertical line is not defined, its
equation cannot be written in the slope-intercept form.
However, the equation of any line can be written in the
general form
General form of the equation of a line
where A and B are not both zero. For instance, the vertical
line given by x = a can be represented by the general form
x – a = 0.
29
Graphing Linear Models
30
Parallel and Perpendicular
Lines
31
Parallel and Perpendicular Lines
The slope of a line is a convenient tool for determining
whether two lines are parallel or perpendicular, as shown in
Figure 1.19. Specifically, nonvertical lines with the same
slope are parallel and nonvertical lines whose slopes are
negative reciprocals are perpendicular.
Perpendicular lines
Parallel lines
Figure 1.19
32
Parallel and Perpendicular Lines
33
Example 4 – Finding Parallel and Perpendicular Lines
Find the general forms of the equations of the lines that
pass through the point (2, –1) and are
a. parallel to the line 2x – 3y = 5.
b. perpendicular to the line 2x – 3y = 5.
(See Figure 1.20.)
Lines parallel and perpendicular to 2x – 3y = 5
Figure 1.20
34
Example 4 – Solution
By writing the linear equation 2x – 3y = 5 in slope-intercept
form,
you can see that the given line has a slope
of m =
a. The line through (2, –1) that is parallel to the given line
also has a slope of
y – y1 = m(x – x1)
y – (–1) = (x – 2)
Point-slope form
Substitute.
35
Example 4 – Solution
3(y + 1) = 2(x – 2)
2x – 3y – 7 = 0
cont’d
Simplify.
General form
Note the similarity to the original equation.
b. Using the negative reciprocal of the slope of the given
line, you can determine that the slope of a line
perpendicular to the given line is
36
Example 4 – Solution
cont’d
So, the line through the point (2, –1) that is perpendicular
to the given line has the following equation.
y – y1 = m(x – x1)
y – (–1) =
(x – 2)
2(y + 1) = –3(x – 2)
3x + 2y – 4 = 0
Point-slope form
Substitute.
Simplify.
General form
37