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Forming and Solving Equations Section A – unknown on one side For each question you need to write out an equation (using ‘x’ or whatever letter you want!) and solve it using the methods you’ve learnt. a) I think of a number. I multiply it by 6 and add 3. If my answer is 75, calculate the number I started with. b) There are ‘b’ daffodil bulbs in a bag. I buy 4 bags, but 5 of the bulbs have gone bad and will not grow. If I still have 55 bulbs that will grow, calculate the number of bulbs in each bag. c) The mean of 3 numbers is 12. If one number is 5 and the other is 11, write an equation and solve it to find the third number. (Think about what you’d do with the numbers to calculate the mean!) d) The triangle to the right is Isosceles. Calculate the lengths of the sides if the perimeter is 68cm. 2x - 1 x Section B – unknown on both sides a) Tom and Ellie both have the same amount of money to begin with. Tom multiplies his by 4 and adds 50p. Ellie multiplies hers by 9 and subtracts £3. They end up with the same amount of money. Calculate the amount they started with. b) Alex thinks of a number. He adds 18 then divides it by 2. He gets the same answer that he would have if he had multiplied the original number by 5. Calculate the mystery number. c) Rectangle A has one side which is 6cm long and the other is (x + 2)cm long. Rectangle B has sides of length (2x + 1) and 3cm. If the perimeters are the same, calculate the value of x and hence, the lengths of the sides of the rectangles. d) Rectangle X measures 7cm by (x + 1)cm. Rectangle Y has dimensions of (3x + 6)cm and 4cm. The area of rectangle X is half the area of rectangle Y. Calculate the lengths of the sides of the rectangles, and hence, their areas. Super Challenge Question Adam has sticks of the following lengths: (3x + 4)cm (2x + 10)cm (x + 12)cm He puts all 3 sticks together to make a triangle. The triangle is Isosceles. Calculate the 3 possible values of x. Forming and Solving Equations Section A 1) 12 2) 15 3) 20 4) x = 14, sides - 14, 27, 27 Section B 1) 70p 2) 2 3) x = 4, sides are 6 x 6 and 9 x 3 4) x = 5, sides are 6 x 7 and 4 x 21 so areas are 42 and 84 Super Challenge Question 2, 4, or 6