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Transcript
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Small-Signal Analysis of
Multi-Stage Amps
Consider a multi-stage amplifier like the earlier example:
VCC
VCC
VCC
VCC
VCC
vO (t )
v2
v1
I
VEE
Q: How do we analyze such a big circuit?
A: Well, the DC analysis is simplified (for this case), since
each stage is connected with a DC blocking (AC coupling)
capacitor. Since capacitors are open circuits at DC, the
circuit above turns into 3 separate DC circuits with 3
separate DC solutions:
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VCC
VCC
VB
VB
VCC
VO
VCC
VCC
I
VEE
Q: Great. That works for DC analysis, but for small-signal
analysis the large capacitors become approximate shorts, and
the three stages become inextricably connected. Do we just
have to analyze one great big small-signal circuit?
A: Certainly we could replace each transistor with its smallsignal equivalent circuit, and then analyze the entire resulting
mess to find the overall open-circuit voltage gain, input
resistance, and output resistance. However, there is an
alternate way!
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Recall what we learned in Chapter 1. We can fully
characterize an amplifier with its open-circuit voltage gain, its
input resistance, and its output resistance. We these
parameters, we can replace even the most complex amplifier
with a simple equivalent model:
Ro
+
vi
-
Ri
+
-
Avo vi
We can likewise do this for each stage of a multi-stage
amplifier! We can:
 “Disconnect” a single stage from the stages preceding it
and the stages after it.
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 Then apply a small-signal analysis to just that stage, and
find the small-signal open-circuit voltage gain, the input
resistance, and the output resistance of just that single
stage.
 Then form a simple, equivalent amplifier circuit for that
stage, and use this small-signal equivalent circuit in the
overall multi-stage circuit.
What we are left with looks like a problem from Chapter 1—a
string of cascaded amplifiers where we know nothing more
than the 3 fundamental parameters of each:
+
Input
Stage
BJT Diff Pair
Rid  50K
Ad  60
Ro  5K
Gain
Stage
Output
Stage
CommonEmitter
CommonCollector
Ri  10K
Ri  50K
Avo  70
Avo  1.0
Ro  5K
Ro  10