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171S5.5o Solving Exponential and Logarithmic Equations MAT 171 Precalculus Algebra Dr. Claude Moore Cape Fear Community College CHAPTER 5: Exponential and Logarithmic Functions 5.1 Inverse Functions 5.2 Exponential Functions and Graphs 5.3 Logarithmic Functions and Graphs 5.4 Properties of Logarithmic Functions 5.5 Solving Exponential and Logarithmic Equations 5.6 Applications and Models: Growth and Decay; and Compound Interest Solving Exponential Equations Equations with variables in the exponents, such as 3x = 20 and 25x = 64, are called exponential equations. Use the following property to solve exponential equations. BaseExponent Property For any a > 0, a ≠ 1, November 21, 2011 5.5 Solving Exponential and Logarithmic Equations • Solve exponential equations. • Solve logarithmic equations. Example Solve Solution: Write each side as a power of the same number (base). Since the bases are the same number, 2, we can use the baseexponent property and set the exponents equal: Check x = 4: ax = ay if and only if x = y. The solution is 4. TRUE 1 171S5.5o Solving Exponential and Logarithmic Equations Another Property November 21, 2011 Example Solve: 3x = 20. Property of Logarithmic Equality For any M > 0, N > 0, a > 0, and a ≠ 1, loga M = loga N This is an exact answer. We cannot simplify further, but we can approximate using a calculator. M = N. We can check by finding 32.7268 ≈ 20. Solving Logarithmic Equations Example Solve: e0.08t = 2500. Equations containing variables in logarithmic expressions, such as log2 x = 4 and log x + log (x + 3) = 1, are called logarithmic equations. To solve logarithmic equations algebraically, we first try to obtain a single logarithmic expression on one side and then write an equivalent exponential equation. The solution is about 97.8. 2 171S5.5o Solving Exponential and Logarithmic Equations Example November 21, 2011 Example Solve: log3 x = −2. Solve: Check: Solution: TRUE The solution is Example Example (continued) Check x = 2: Check x = –5: Solve: Solution: FALSE TRUE The number –5 is not a solution because negative numbers do not have real number logarithms. The solution is 2. Only the value 2 checks, and it is the only solution. 3 171S5.5o Solving Exponential and Logarithmic Equations Example Using the Graphing Calculator November 21, 2011 Suggestions for solving exponential and logarithmic equations: Solve: e0.5x – 7.3 = 2.08x + 6.2. Exponential equation: Write so that bases are equal, set exponents equal, and solve, if possible. If not possible, write as logarithmic equation and solve. Solve: Graph y1 = e0.5x – 7.3 and y2 = 2.08x + 6.2 and use the Intersect method. BaseExponent Property For any a > 0, a ≠ 1, ax = ay if and only if x = y. The approximate solutions are –6.471 and 6.610. Solve the exponential equation algebraically. Then check using a graphing calculator. 444/4. 37x = 27 Logarithmic equation: If bases of logs are equal, set quantities equal and solve. If not possible, write as exponential equation and solve. Property of Logarithmic Equality: For any M > 0, N > 0, a > 0, and a ≠ 1, loga M = loga N if and only if M = N. loga x = y if and only if x = ay Solve the exponential equation algebraically. Then check using a graphing calculator. 444/10. 4 171S5.5o Solving Exponential and Logarithmic Equations November 21, 2011 Solve the exponential equation algebraically. Then check using a graphing calculator. 444/20. 1000e0.09t = 5000 Solve the exponential equation algebraically. Then check using a graphing calculator. 444/28. 2x+1 = 52x Solve the logarithmic equation algebraically. Then check using a graphing calculator. 444/36. log5 (8 7x) = 3 Solve the logarithmic equation algebraically. Then check using a graphing calculator. 444/48. log5 (x + 4) + log5 (x 4) = 2 5 171S5.5o Solving Exponential and Logarithmic Equations Use a graphing calculator to find the approximate solutions of the equation. 444/54. 0.082e0.05x = 0.034 November 21, 2011 Use a graphing calculator to find the approximate solutions of the equation. 444/62. log5 x + 7 = 4 log5 x 6