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November Problem Sets ­ final.notebook
November 18, 2014
Honors November Cumulative Problem Sets
Problem Set ­ November 6th 1. The area of a rectangular garden cannot exceed 105 square feet. If the length of the garden is 6 more than 5 times the width of the garden, what are the largest possible integral values for each dimension of the garden? Only an algebraic solution will be accepted. 2. The height of an object thrown in the air is modeled by the equation h(t) = ­16t2 + 48t + 6 where h represents the height of the object, in feet,
and t represents the time, in seconds, since the object was thrown.
During what interval of time will the object be at least 26 feet high?
November 10th Problem Set
Solve for x. 2. Starting with ax2 + bx + c = 0, by completing the square, derive the quadratic formula. Problem Set ­ November 12th Solve the following inequality, graph the solution set, and write the solution set using interval notation. 1
November Problem Sets ­ final.notebook
November 18, 2014
Problem Set ­ November 17th 1. A depth finder shows that the water in a certain place is 620 feet deep. The difference between, d, the actual depth of the water, and the reading is |d ­ 620| and must be less than or equal to 0.05d. Find the minimum and maximum values of d, to the nearest tenth of a foot.
2. Solve: 3(x ­ 2)2 ­ 4 = 20 leave the answer in simplest radical form. Problem Set ­ November 18th 1. Solve the inequality, round values to the nearest hundredth and write the solution using interval notation.
2. The heights, h, of the students in the chorus at Central Middle School satisfy the inequality
when h is measured in inches. Determine the interval in which these heights lie and express your answer to the nearest tenth of a foot. Write your answer in interval notation. Problem Set November 19th 1. Simplify completely.
2. Solve for all values of x, leave your answer in simplest form.
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November Problem Sets ­ final.notebook
November 18, 2014
Problem Set ­ November 20th
1. The path of an object lauched into the air can be described by the equation h(t) = ­16t2 + 20t + 3, where h is the height, in feet, and t is time, in seconds. a. What is the maximum height of the object?
b. When will the object be exactly 5.25 feet in the air?
2. Simplify completely. Problem Set ­ November 24th Simplify completely.
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